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(II) A pump lifts \(21.0 \mathrm{~kg}\) of water per minute through a height of \(3.50 \mathrm{~m}\). What minimum output rating (watts) must the pump motor have?

Short Answer

Expert verified
The pump requires a minimum output power of 13 watts.

Step by step solution

01

Understand the Problem

The pump lifts water through a certain height, which involves work done against gravity. The problem requires us to find the pump's minimum output power in watts.
02

Calculate Weight Force

The weight force of the water can be calculated using the formula: \[ F_w = m \cdot g \]where \( m = 21.0 \; \text{kg} \) is the mass of water and \( g = 9.81 \; \text{m/s}^2 \) is the acceleration due to gravity. Substituting the values:\[ F_w = 21.0 \cdot 9.81 \approx 206.01 \; \text{N} \]
03

Calculate Work Done

Work done is given by the formula:\[ W = F_w \cdot h \]where \( h = 3.50 \; \text{m} \) is the height. Substitute the values we calculated:\[ W = 206.01 \cdot 3.50 \approx 721.035 \; \text{J} \]
04

Determine Power Required

Power is the work done per unit time. Since the work is done per minute, convert minutes to seconds to find power in watts:\[ P = \frac{W}{t} \]where \( t = 60 \; \text{s} \) (because power must be in watts, i.e., joules per second). Substituting the values:\[ P = \frac{721.035}{60} \approx 12.017 \; \text{W} \]
05

Finalize the Solution

Since power must be in whole numbers for practical applications, round up the value to ensure that the pump has enough power:\[ P = 13 \; \text{W} \] Thus, the minimum output rating required for the pump is 13 watts.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Work and Energy
In physics, the concepts of work and energy are closely related. Work is defined as a force causing an object to move in the direction of the force. When you do work on an object, you transfer energy to that object.
For example, in the exercise provided, the pump is doing work by moving water against the gravitational pull of the Earth. The work done can be calculated using the formula:
\[W = F \cdot d\]where \(W\) is work, \(F\) is the force applied, and \(d\) is the distance over which the force is applied. In this case, the force is the weight of the water, and the distance is the height the water is lifted.
Work is measured in joules, which is a unit representing the amount of energy transferred when work is done. Energy, like work, can come in many forms and be transformed from one form to another. By lifting water, we are converting mechanical energy from the pump to gravitational potential energy in the water.
Gravitational Force
Gravitational force is a fundamental concept in physics, describing the attractive force between two masses. The formula for calculating gravitational force on an object near the Earth's surface is:
\[F_g = m \cdot g\]where \(m\) is the mass of the object and \(g\) is the acceleration due to gravity, approximately \(9.81 \text{ m/s}^2\) on Earth. This concept is critical when dealing with any object being moved vertically.
In our exercise, the gravitational force is the weight of the water the pump must overcome to lift it. This force acts downward due to Earth's gravity, and to lift the water, the pump must exert an equal and opposite force. Understanding this force allows us to calculate the work needed to lift the water, supplying the necessary energy to overcome gravity.
Mechanics Problem Solving
Mechanics problem solving in physics involves breaking down problems into manageable components using fundamental principles. Here, we addressed a problem by first understanding the forces involved.
Whenever you face a mechanics problem:
  • Identify all forces acting on the object.
  • Determine what quantities you need to find (like work or power).
  • Use appropriate formulas connecting force, distance, and time.
In our pump example, the steps were:
  • Calculate the gravitational force acting on the water.
  • Determine the work done against this force by moving the water.
  • Calculate the power required, which is the work done per unit of time.
By systematically approaching the problem, you simplify complex situations and find precise and accurate results. Consistent practice with such problems will build strong problem-solving skills, which are invaluable in understanding physics and engineering concepts.

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Most popular questions from this chapter

A particle of mass \(m\) moves under the influence of a potential energy $$ U(x)=\frac{a}{x}+b x $$ where \(a\) and \(b\) are positive constants and the particle is restricted to the region \(x>0\). Find a point of equilibrium for the particle and demonstrate that it is stable.

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