/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 31 \(\begin{array}{llll}\text { (II... [FREE SOLUTION] | 91Ó°ÊÓ

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\(\begin{array}{llll}\text { (II) } & \text { Suppose } & \mathbf{A}=1.0 \mathbf{i}+1.0 \mathbf{j}-2.0 \mathbf{k} & \text { and } & \mathbf{B}=\end{array}\) \(-1.0 \hat{\mathrm{i}}+1.0 \mathrm{j}+2.0 \hat{\mathbf{k}}, \quad(a)\) what is the angle between these two vectors? \((b)\) Explain the significance of the sign in part \((a)\).

Short Answer

Expert verified
The angle between the vectors is \( \cos^{-1}(-\frac{2}{3}) \). The negative dot product indicates an obtuse angle.

Step by step solution

01

Understanding the Problem

We have two vectors \( \mathbf{A} = 1.0 \mathbf{i} + 1.0 \mathbf{j} - 2.0 \mathbf{k} \) and \( \mathbf{B} = -1.0 \hat{\mathbf{i}} + 1.0 \mathbf{j} + 2.0 \mathbf{k} \). We need to calculate the angle between them and explain the significance of its sign.
02

Calculate the Dot Product

The dot product of two vectors \( \mathbf{A} \) and \( \mathbf{B} \) is given by \( \mathbf{A} \cdot \mathbf{B} = (1.0)(-1.0) + (1.0)(1.0) + (-2.0)(2.0) = -1.0 + 1.0 - 4.0 = -4.0 \).
03

Calculate Magnitudes of the Vectors

The magnitude of vector \( \mathbf{A} \) is \( \| \mathbf{A} \| = \sqrt{(1.0)^2 + (1.0)^2 + (-2.0)^2} = \sqrt{1.0 + 1.0 + 4.0} = \sqrt{6.0} \).The magnitude of vector \( \mathbf{B} \) is \( \| \mathbf{B} \| = \sqrt{(-1.0)^2 + (1.0)^2 + (2.0)^2} = \sqrt{1.0 + 1.0 + 4.0} = \sqrt{6.0} \).
04

Calculate the Angle Using the Dot Product Formula

The angle \( \theta \) between two vectors is given by \( \cos \theta = \frac{\mathbf{A} \cdot \mathbf{B}}{\| \mathbf{A} \| \| \mathbf{B} \|} = \frac{-4.0}{\sqrt{6.0} \cdot \sqrt{6.0}} = \frac{-4.0}{6.0} = -\frac{2}{3} \).Thus, \( \theta = \cos^{-1}(-\frac{2}{3}) \).
05

Interpret the Sign of the Angle

The sign of the dot product determines the direction between the two vectors. Since the dot product is negative, the angle between them is obtuse, meaning the vectors are pointing in more opposite directions.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Dot Product
In vector mathematics, the dot product is a way to multiply two vectors to get a single scalar value. It provides information about the relationship between the two vectors, specifically the angle. The formula to calculate the dot product for two vectors \( \mathbf{A} \) and \( \mathbf{B} \) is:
  • \( \mathbf{A} \cdot \mathbf{B} = A_x \times B_x + A_y \times B_y + A_z \times B_z \)
Where \( A_x, A_y, \) and \( A_z \) are the components of vector \( \mathbf{A} \), and \( B_x, B_y, \) and \( B_z \) are the components of vector \( \mathbf{B} \). For our example, the vectors were:
  • \( \mathbf{A} = 1.0 \mathbf{i} + 1.0 \mathbf{j} - 2.0 \mathbf{k} \)
  • \( \mathbf{B} = -1.0 \mathbf{i} + 1.0 \mathbf{j} + 2.0 \mathbf{k} \)
By substituting the components into the dot product formula, we calculated:
  • \( \mathbf{A} \cdot \mathbf{B} = (1.0)(-1.0) + (1.0)(1.0) + (-2.0)(2.0) = -4.0 \)
The result was a negative value, indicating that the vectors are pointing in more opposite than similar directions. Note that when the dot product is positive, the vectors are generally pointing in the same direction, whereas a negative result means the vectors are pointing in opposite directions.
Magnitude of a Vector
The magnitude of a vector measures its length or size and is always a positive number. We calculate it using the Pythagorean theorem, applied to its components. For a vector \( \mathbf{A} \), given by \( \mathbf{A} = a_x \mathbf{i} + a_y \mathbf{j} + a_z \mathbf{k} \), its magnitude \( \| \mathbf{A} \| \) is:
  • \( \| \mathbf{A} \| = \sqrt{a_x^2 + a_y^2 + a_z^2} \)
In our example:
  • \( \mathbf{A} = 1.0 \mathbf{i} + 1.0 \mathbf{j} - 2.0 \mathbf{k} \)
  • \( \| \mathbf{A} \| = \sqrt{(1.0)^2 + (1.0)^2 + (-2.0)^2} = \sqrt{6.0} \)
Similarly, for \( \mathbf{B} = -1.0 \mathbf{i} + 1.0 \mathbf{j} + 2.0 \mathbf{k} \), the magnitude is:
  • \( \| \mathbf{B} \| = \sqrt{(-1.0)^2 + (1.0)^2 + (2.0)^2} = \sqrt{6.0} \)
When comparing magnitudes, if two vectors have the same magnitude, they are considered to have the same length irrespective of their direction.
Cosine of the Angle Between Vectors
The cosine of the angle between two vectors is a valuable concept in understanding the spatial relationship between them. It is calculated using the dot product and the magnitudes of the respective vectors. The formula is:
  • \( \cos \theta = \frac{\mathbf{A} \cdot \mathbf{B}}{\| \mathbf{A} \| \| \mathbf{B} \|} \)
Using this formula, you can determine the angle \( \theta \) between any two vectors. In our specific case, we found:
  • \( \cos \theta = \frac{-4.0}{\sqrt{6.0} \cdot \sqrt{6.0}} = \frac{-4.0}{6.0} = -\frac{2}{3} \)
The \( \cos \theta \) of \(-\frac{2}{3} \) implies that the angle \( \theta \) is obtuse, as the cosine of an obtuse angle is negative. This is consistent with our earlier observation from the negative dot product, indicating the vectors point somewhat oppositely. Understanding the angle between vectors can help in various applications, such as determining how two forces might counteract each other.

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Most popular questions from this chapter

A \(6.10 - \mathrm { kg }\) block is pushed 9.25\(\mathrm { m }\) up a smooth \(37.0 ^ { \circ }\) inclined plane by a horizontal force of 75.0\(\mathrm { N }\) . If the initial speed of the block is 3.25\(\mathrm { m } / \mathrm { s }\) up the plane, calculate \(( a )\) the initial kinetic energy of the block; \(( b )\) the work done by the 75.0 -N force; \(( c )\) the work done by gravity; \(( d )\) the work done by the normal force; \(( e )\) the final kinetic energy of the block.

When different masses are suspended from a spring, the spring stretches by different amounts as shown in the Table below. Masses are ±1.0 gram. \begin{tabular}{lllrrrrrrr} \hline Mass (g) & 0 & 50 & 100 & 150 & 200 & 250 & 300 & 350 & 400 \\ Stretch (cm) & 0 & 5.0 & 9.8 & 14.8 & 19.4 & 24.5 & 29.6 & 34.1 & 39.2 \\ \hline \end{tabular} (a) Graph the applied force (in Newtons) versus the stretch (in meters) of the spring, and determine the best-fit straight line. (b) Determine the spring constant ( \(\mathrm{N} / \mathrm{m}\) ) of the spring from the slope of the best-fit line. \((c)\) If the spring is stretched by \(20.0 \mathrm{~cm},\) estimate the force acting on the spring using the best-fit line.

If the speed of a car is increased by \(50 \%\), by what factor will its minimum braking distance be increased, assuming all else is the same? Ignore the driver's reaction time.

A force \(\overrightarrow{\mathbf{F}}=(10.0 \hat{\mathbf{i}}+9.0 \hat{\mathbf{j}}+12.0 \hat{\mathbf{k}}) \mathbf{k N}\) acts on a small object of mass \(95 \mathrm{~g}\). If the displacement of the object is \(\overrightarrow{\mathbf{d}}=(5.0 \hat{\mathbf{i}}+4.0 \hat{\mathbf{j}}) \mathrm{m},\) find the work done by the force. What is the angle between \(\overrightarrow{\mathbf{F}}\) and \(\overrightarrow{\mathbf{d}}\) ?

The arrangement of atoms in zinc is an example of "hexagonal close-packed" structure. Three of the nearest neighbors are found at the following \((x, y, z)\) coordinates, given in nanometers \(\left(10^{-9} \mathrm{~m}\right):\) atom 1 is at (0,0,0)\(;\) atom 2 is at (0.230,0.133,0)\(;\) atom 3 is at \((0.077,0.133,0.247) .\) Find the angle between two vectors: one that connects atom 1 with atom 2 and another that connects atom 1 with atom \(3 .\)

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