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What is the dot product of \(\overrightarrow{\mathbf{A}}=2.0 x^{2} \hat{\mathbf{i}}-4.0 x \hat{\mathbf{j}}+5.0 \hat{\mathbf{k}}\) and \(\overrightarrow{\mathbf{B}}=11.0 \hat{\mathbf{i}}+2.5 x \hat{\mathbf{j}}\) ?

Short Answer

Expert verified
The dot product is \( 12.0x^2 \).

Step by step solution

01

Identify Components of Vectors

The vector \( \overrightarrow{\mathbf{A}} \) is given as \( 2.0 x^2 \hat{\mathbf{i}} - 4.0 x \hat{\mathbf{j}} + 5.0 \hat{\mathbf{k}} \). The vector \( \overrightarrow{\mathbf{B}} \) is given as \( 11.0 \hat{\mathbf{i}} + 2.5 x \hat{\mathbf{j}} \). Identify the components: \( \overrightarrow{\mathbf{A}} = (2.0x^2, -4.0x, 5.0) \) and \( \overrightarrow{\mathbf{B}} = (11.0, 2.5x, 0) \).
02

Apply Dot Product Formula

The formula for the dot product of two vectors \( \overrightarrow{A} = (a_1, a_2, a_3) \) and \( \overrightarrow{B} = (b_1, b_2, b_3) \) is \( a_1b_1 + a_2b_2 + a_3b_3 \). For \( \overrightarrow{\mathbf{A}} \) and \( \overrightarrow{\mathbf{B}} \), the dot product is: \( (2.0x^2)(11.0) + (-4.0x)(2.5x) + (5.0)(0) \).
03

Calculate Each Term

Compute each term of the dot product: \( 2.0x^2 \cdot 11.0 = 22.0x^2 \), \( -4.0x \cdot 2.5x = -10.0x^2 \), and \( 5.0 \cdot 0 = 0 \).
04

Sum the Terms

Add up the computed terms to find the final result of the dot product: \( 22.0x^2 - 10.0x^2 + 0 = 12.0x^2 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Vector Components
Vectors are fundamental elements in mathematics, representing quantities having both direction and magnitude. To work with vectors analytically, it's crucial to break them down into vector components. **Vector components** are the individual parts along each axis of a coordinate system, typically the x, y, and z axes.
Each vector component corresponds to a direction and magnitude in that particular axis. For instance, the vector \( \overrightarrow{\mathbf{A}} = 2.0 x^2 \hat{\mathbf{i}} - 4.0 x \hat{\mathbf{j}} + 5.0 \hat{\mathbf{k}} \) can be expressed with components \( (2.0x^2, -4.0x, 5.0) \) where:
  • \( 2.0x^2 \) is the component in the x-direction (\( \hat{\mathbf{i}} \))
  • \( -4.0x \) is the component in the y-direction (\( \hat{\mathbf{j}} \))
  • \( 5.0 \) is the component in the z-direction (\( \hat{\mathbf{k}} \))
Understanding vector components allows us to perform various vector operations, like adding vectors, calculating the dot product, or projecting one vector onto another. This step lays the groundwork for more complex vector mathematics.
Dot Product Formula
The **dot product** is a fundamental operation in vector mathematics that produces a scalar (a single number) from two vectors. It is a measure of the extent to which two vectors align with each other. To calculate the dot product, each component of one vector is multiplied by the corresponding component of the other vector, and then all the products are summed up.
The dot product formula for two vectors \( \overrightarrow{A} = (a_1, a_2, a_3) \) and \( \overrightarrow{B} = (b_1, b_2, b_3) \) is:\[a_1b_1 + a_2b_2 + a_3b_3\]This operation helps in evaluating angles between vectors, projecting vectors onto other vectors, and in physics, determining work done by a force along a displacement. For the vectors \( \overrightarrow{\mathbf{A}} \) and \( \overrightarrow{\mathbf{B}} \) in this example, the dot product is computed as follows:
  • Multiply the i-components: \( (2.0x^2)(11.0) = 22.0x^2 \)
  • Multiply the j-components: \( (-4.0x)(2.5x) = -10.0x^2 \)
  • The k-component in \( \overrightarrow{\mathbf{B}} \) is zero so \( (5.0)(0) = 0 \)
Summing these results gives the dot product: \( 22.0x^2 - 10.0x^2 + 0 = 12.0x^2 \).
Vector Mathematics
**Vector mathematics** encompasses a variety of operations and applications related to vectors in mathematics and beyond. It's an essential branch of mathematics facilitating the analysis and solution of problems involving multi-directional quantities. Key activities in vector mathematics include:
  • Vector addition and subtraction: Combines vectors to determine resultant displacement or force.
  • Scalar multiplication: Changes a vector's magnitude without affecting its direction.
  • Dot product: Determines scalar product and is crucial in physics and computer graphics.
  • Cross product: Produces a vector perpendicular to two given vectors and is important in calculating torque.
  • Projections: Helps in finding one vector’s influence in the direction of another.
Understanding these basic operations builds a solid foundation for engaging deeply with fields such as physics, engineering, graphics, and many areas of research. This branch of mathematics provides tools needed to model and predict behaviors of complex systems, making it a cornerstone of scientific inquiry.

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Most popular questions from this chapter

If \(\overrightarrow{\mathbf{A}}=9.0 \hat{\mathbf{i}}-8.5 \hat{\mathbf{j}}, \quad \overrightarrow{\mathbf{B}}=-8.0 \hat{\mathbf{i}}+7.1 \hat{\mathbf{j}}+4.2 \hat{\mathbf{k}},\) and \(\overrightarrow{\mathbf{C}}=6.8 \hat{\mathbf{i}}-9.2 \hat{\mathbf{j}},\) determine \((a) \overrightarrow{\mathbf{A}} \cdot(\overrightarrow{\mathbf{B}}+\overrightarrow{\mathbf{C}}) ;(b)(\overrightarrow{\mathbf{A}}+\overrightarrow{\mathbf{C}}) \cdot \overrightarrow{\mathbf{B}} ;\) \((c)(\overrightarrow{\mathbf{B}}+\overrightarrow{\mathbf{A}}) \cdot \mathbf{C}\)

(a) What magnitude force is required to give a helicopter of mass \(M\) an acceleration of \(0.10 g\) upward? (b) What work is done by this force as the helicopter moves a distance \(h\) upward?

(I) Calculate the angle between the vectors: \(\overrightarrow{\mathbf{A}}=6.8 \hat{\mathbf{i}}-3.4 \hat{\mathbf{j}}-6.2 \hat{\mathbf{k}} \quad\) and \(\quad \overrightarrow{\mathbf{B}}=8.2 \hat{\mathbf{i}}+2.3 \hat{\mathbf{j}}-7.0 \hat{\mathbf{k}}\).

Given the vector \(\overrightarrow{\mathbf{A}}=3.0 \hat{\mathbf{i}}+1.5 \hat{\mathbf{j}},\) find a vector \(\overrightarrow{\mathbf{B}}\) that is perpendicular to \(\overrightarrow{\mathbf{A}}\).

(II) A train is moving along a track with constant speed \(v _ { 1 }\) relative to the ground. A person on the train holds a ball of mass \(m\) and throws it toward the front of the train with a speed \(v _ { 2 }\) relative to the train. Calculate the change in kinetic energy of the ball \(( a )\) in the Earth frame of reference, and (b) in the train frame of reference. (c) Relative to each frame of reference, how much work was done on the ball? (d) Explain why the results in part (c) are not the same for the two frames - after all, it's the same ball.

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