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Estimate the binding energy of a KCl molecule by calculating the electrostatic potential energy when the \(\mathrm{K}^{+}\) and \(\mathrm{Cl}^{-}\) ions are at their stable separation of \(0.28 \mathrm{nm} .\) Assume each has a charge of magnitude \(1.0 e\).

Short Answer

Expert verified
-8.19 x 10^-19 J

Step by step solution

01

Identify the Coulomb's Law formula

The potential energy due to electrostatic interaction (Coulomb's Law) between two charges is given by the formula: \[ U = \frac{k_e \cdot q_1 \cdot q_2}{r} \]where \( U \) is the potential energy, \( k_e \) is the Coulomb's constant \((8.99 \times 10^9 \, \text{N m}^2/\text{C}^2)\), \( q_1 \) and \( q_2 \) are the charges involved, and \( r \) is the separation distance.
02

Substitute the given values into the formula

In this problem, \( q_1 = q_2 = 1.0e = 1.6 \times 10^{-19} \text{ C} \), and \( r = 0.28 \text{ nm} = 0.28 \times 10^{-9} \text{ m} \). Substitute these values into the formula: \[ U = \frac{(8.99 \times 10^9) \cdot (1.6 \times 10^{-19}) \cdot (-1.6 \times 10^{-19})}{0.28 \times 10^{-9}} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Coulomb's Law and Its Application
Coulomb's Law is the foundation for calculating electrostatic potential energy between two charged particles. It describes how the potential energy (often referred to as "electric potential energy") between two point charges depends on the magnitudes of the charges and the distance between them. The formula is expressed as:\[ U = \frac{k_e \cdot q_1 \cdot q_2}{r} \]Here:
  • \(U\) is the potential energy,
  • \(k_e\) is the Coulomb's constant \((8.99 \times 10^9 \, \text{N m}^2/\text{C}^2)\),
  • \(q_1\) and \(q_2\) are the magnitudes of the charges, and
  • \(r\) is the separation distance between the two charges.
Coulomb's Law is essential for understanding interactions between ions like \(\text{K}^+\) and \(\text{Cl}^-\) in a KCl molecule. When dealing with molecules, calculating this energy helps determine how strongly the ions attract each other.
Understanding Binding Energy
Binding energy refers to the energy required to separate two bonded particles or ions. When a potassium ion (\(\text{K}^+\)) and a chloride ion (\(\text{Cl}^-\)) form a bond, energy is released, which is reflected as a negative sign in the calculated potential energy. This is because the system loses energy as the ions come together. The binding energy is equivalent to the potential energy calculated using Coulomb's Law, because it represents the same amount of energy required to break the bond and separate the ions again to the point where they no longer influence each other. High binding energy means a stable and strong interaction between ions.
How to Calculate Potential Energy for Ions
To calculate the potential energy for a system of ions, like a potassium ion and a chloride ion, you can use Coulomb's Law. Start by inserting the charge values and separation distance into the formula. For this KCl problem:\[ q_1 = q_2 = 1.6 \times 10^{-19} \text{ C} \]and\[r = 0.28 \times 10^{-9} \text{ m}\]These charges are of equal magnitude but opposite signs (one is positive and the other is negative), leading to an attractive force. Substitute these values:\[ U = \frac{(8.99 \times 10^9) \cdot (1.6 \times 10^{-19}) \cdot (-1.6 \times 10^{-19})}{0.28 \times 10^{-9}} \]The result will be a negative value, indicating an attractive (or binding) interaction between the ions.
Ion Separation Distance and Its Importance
The separation distance \(r\) between ions plays a crucial role in determining the potential energy of their interaction. According to Coulomb's Law, potential energy is inversely proportional to the distance, which means that as the distance decreases, the potential energy becomes more negative, indicating stronger attraction. In the case of a KCl molecule, the stable separation distance \(r\) of \(0.28 \text{ nm}\) represents the distance at which the forces of attraction and repulsion balance each other, creating a stable ionic bond. At this optimal distance, the energy of interaction is minimized, meaning the system is energetically stable. Understanding the role of ion separation can help explain why certain molecular configurations are more stable than others.

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Most popular questions from this chapter

Consider a monatomic solid with a weakly bound cubic lattice, with each atom connected to six neighbors, each bond having a binding energy of \(3.9 \times 10^{-3} \mathrm{eV} .\) When this solid melts, its latent heat of fusion goes directly into breaking the bonds between the atoms. Estimate the latent heat of fusion for this solid, in J/mol. [Hint: Show that in a simple cubic lattice (Fig. 46), there are three times as many bonds as there are atoms, when the number of atoms is large.

Use the uncertainty principle to estimate the binding energy of the \(\mathrm{H}_{2}\) molecule by calculating the difference in kinetic energy of the electrons between when they are in separate atoms and when they are in the molecule. Take \(\Delta x\) for the electrons in the separated atoms to be the radius of the first Bohr orbit, \(0.053 \mathrm{nm},\) and for the molecule take \(\Delta x\) to be the separation of the nuclei, 0.074 \(\mathrm{nm} .\) [Hint: Let \(\Delta p \approx \Delta p_{x} .\)

(II) The equilibrium distance \(r_{0}\) between two atoms in a molecule is called the bond length. Using the bond lengths of homogeneous molecules (like \(\mathrm{H}_{2}, \mathrm{O}_{2},\) and \(\mathrm{N}_{2} ),\) one can estimate the bond length of heterogeneous molecules (like \(\mathrm{CO}, \mathrm{CN},\) and NO). This is done by summing half of each bond length of the homogenous molecules to estimate that of the heterogeneous molecule. Given the following bond lengths: \(\mathrm{H}_{2}(=74 \mathrm{pm})\) \(\mathrm{N}_{2}(=145 \mathrm{pm}), \mathrm{O}_{2}(=121 \mathrm{pm}), \mathrm{C}_{2}(=154 \mathrm{pm}),\) estimate the bond lengths for: HN, CN, and NO.

In the ionic salt \(\mathrm{KF}\) , the separation distance between ions is about 0.27 \(\mathrm{nm}\) . (a) Estimate the electrostatic potential energy between the ions assuming them to be point charges (magnitude 1\(e ) .\) (b) When \(\mathrm{F}^{\text { "grabs" an electron, it releases }}\) 3.41 \(\mathrm{eV}\) of energy, whereas 4.34 \(\mathrm{eV}\) is required to ionize \(\mathrm{K}\) . Find the binding energy of KF relative to free \(\mathrm{K}\) and \(\mathrm{F}\) atoms, neglecting the energy of repulsion.

Common salt, \(\mathrm{NaCl}\), has a density of \(2.165 \mathrm{~g} / \mathrm{cm}^{3} .\) The molecular weight of \(\mathrm{NaCl}\) is \(58.44 .\) Estimate the distance between nearest neighbor \(\mathrm{Na}\) and \(\mathrm{Cl}\) ions. [Hint: Each ion can be considered to have one "cube" or "cell" of side \(s\) (our unknown) extending out from it.

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