Chapter 33: Problem 9
(II) An object is located 1.50 \(\mathrm{m}\) from an 8.0 -D lens. By how much does the image move if the object is moved \((a) 0.90 \mathrm{m}\) closer to the lens, and \((b) 0.90 \mathrm{m}\) farther from the lens?
Short Answer
Expert verified
For part (a), the image moves 0.027 m closer; for part (b), the image moves 0.025 m closer.
Step by step solution
01
Understand the Lens Formula
The lens formula relates the object distance \(d_o\), image distance \(d_i\), and the focal length \(f\) of a lens. It is given by: \(\frac{1}{f} = \frac{1}{d_o} + \frac{1}{d_i}\). A lens with a power of 8.0 D has a focal length \(f\) given by \(f = \frac{1}{P}\), where \(P\) is the power in diopters.
02
Calculate the Focal Length
Given the power \(P = 8.0\) D, calculate the focal length: \(f = \frac{1}{8.0} = 0.125\) meters.
03
Initial Image Distance Calculation
Calculate the initial image distance \(d_{i1}\) when the object is at \(d_{o1} = 1.50\) m. Use the lens formula: \(\frac{1}{0.125} = \frac{1}{1.50} + \frac{1}{d_{i1}}\). Solving for \(d_{i1}\) gives \(d_{i1} = 0.177\) m.
04
Calculate Image Distance for Object Moved Closer
If the object is moved 0.90 m closer, the new object distance is \(d_{o2a) = 1.50 - 0.90 = 0.60\) m. Use the lens formula again: \(\frac{1}{0.125} = \frac{1}{0.60} + \frac{1}{d_{i2a}}\). Solving for \(d_{i2a}\) gives \(d_{i2a} = 0.15\) m.
05
Calculate Image Distance Change for Closer Object
The change in image distance when the object is moved closer is \(\Delta d_{ia} = d_{i2a} - d_{i1} = 0.15 - 0.177 = -0.027\) m. The negative sign indicates the image gets closer.
06
Calculate Image Distance for Object Moved Farther
If the object is moved 0.90 m farther, the new object distance is \(d_{o2b) = 1.50 + 0.90 = 2.40\) m. Use the lens formula again: \(\frac{1}{0.125} = \frac{1}{2.40} + \frac{1}{d_{i2b}}\). Solving for \(d_{i2b}\) gives \(d_{i2b} = 0.152\) m.
07
Calculate Image Distance Change for Farther Object
The change in image distance when the object is moved farther is \(\Delta d_{ib} = d_{i2b} - d_{i1} = 0.152 - 0.177 = -0.025\) m. The negative sign indicates the image gets closer.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Focal Length
In simple terms, the focal length of a lens is the distance from the lens to the point where it focuses parallel rays of light. This point is known as the focal point. The focal length is a critical measurement in optics because it determines how strongly the lens converges or diverges light.
A lens with a shorter focal length will have stronger converging power, meaning it can focus light in a smaller area. Conversely, a longer focal length means the lens is less powerful in bringing light to focus.
When we talk about focal length in meters, it's often linked to a lens's power, measured in diopters. In physics and optics, diopters are a straightforward way to express a lens's ability to bend light.Calculating the focal length from the lens power is easy:
A lens with a shorter focal length will have stronger converging power, meaning it can focus light in a smaller area. Conversely, a longer focal length means the lens is less powerful in bringing light to focus.
When we talk about focal length in meters, it's often linked to a lens's power, measured in diopters. In physics and optics, diopters are a straightforward way to express a lens's ability to bend light.Calculating the focal length from the lens power is easy:
- If a lens has a power of 8.0 diopters, the formula is \( f = \frac{1}{P}\), which gives us \( f = \frac{1}{8.0}\) = 0.125 meters.
Diopters
Diopters are a unit of measurement that tells us about the optical power of a lens. The power of a lens in diopters is the inverse of its focal length in meters. This unit is incredibly convenient in the field of optics because it simplifies the calculation of a lens's strength.
When using diopters, higher numbers indicate stronger lenses with a shorter focal length that can bend light more quickly.Here's a quick way to remember:
When using diopters, higher numbers indicate stronger lenses with a shorter focal length that can bend light more quickly.Here's a quick way to remember:
- Positive diopters indicate converging lenses, where light rays meet.
- Negative diopters indicate diverging lenses, often used in glasses for nearsightedness.
Image Distance
Image distance, represented as \(d_i\), is the distance between the lens and the image it forms. This concept is significant in determining where and how an image is projected when an object is placed at a certain distance from the lens. The lens formula, \(\frac{1}{f} = \frac{1}{d_o} + \frac{1}{d_i}\), combines object distance \(d_o\), focal length \(f\), and image distance \(d_i\) in a straightforward relationship. It shows how these elements interact to position the image.
For instance, moving an object closer or farther from the lens changes the image distance:
For instance, moving an object closer or farther from the lens changes the image distance:
- Moving an object closer to the lens typically makes the image appear closer to the lens as well, leading to a smaller image distance.
- Conversely, moving an object farther away will generally increase the image distance.