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When dealing with microwaves or any electromagnetic waves, converting the wavelength to the correct unit is crucial. Wavelength is often given in centimeters when the speed of light is in meters per second. This is why converting the wavelength from centimeters to meters is a vital first step.

• The basic conversion rule is that 1 centimeter equals 0.01 meters.
• Thus, to convert 1.50 cm to meters, you multiply by 0.01, resulting in 0.015 meters.
• This conversion ensures that the units match for further calculations using the speed of light.

By understanding this conversion, you can confidently interchange between units as needed for various physics problems. Always remember to convert to meters when working with the speed of light in meters per second.

The speed of light is a fundamental constant in physics, denoted by the letter \( c \). It represents the speed at which light travels in a vacuum, which is approximately \( 3 \times 10^8 \) meters per second. This constant plays a crucial role in connecting wavelength and frequency in electromagnetic waves.The formula that interrelates these quantities is:\[ c = \lambda \times f \]Where:

• \( c \) is the speed of light.
• \( \lambda \) represents the wavelength in meters.
• \( f \) is the frequency in Hertz (Hz).

This formula provides a means of determining one quantity if the other two are known. In this context, if you know the wavelength and the speed of light, you can calculate the frequency. Rearranging the formula can help solve for different unknowns.

Frequency is a measure of how often a wave's peaks pass a point, usually measured in Hertz (Hz), or cycles per second. To calculate frequency when you have the wavelength, you can rearrange the speed of light formula to isolate frequency:\[ f = \frac{c}{\lambda} \]This format means:

• The frequency \( f \) is the speed of light \( c \) divided by the wavelength \( \lambda \).
• It allows for the calculation of the number of wave cycles passing a fixed point in one second.

By substituting the known values, such as \( c = 3 \times 10^8 \) m/s and \( \lambda = 0.015 \) m for a specific microwave, you can perform the division:\[ f = \frac{3 \times 10^8 \text{ m/s}}{0.015 \text{ m}} \]Resulting in a frequency of \( 2 \times 10^{10} \) Hz, showing the high frequency that microwaves typically exhibit. This repeated process of applying formulas helps in understanding and predicting wave behavior effectively.