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(II) What is the energy density at the center of a circular loop of wire carrying a \(23.0 -\) A current if the radius of the loop is 28.0\(\mathrm { cm } ?\)

Short Answer

Expert verified
The magnetic energy density at the center is approximately \(1.054 \times 10^{-4} \ \text{J/m}^3\).

Step by step solution

01

Understand the problem

We need to find the magnetic energy density at the center of a circular loop of wire carrying a given current. This requires using the formula for magnetic energy density and an understanding of how the magnetic field at the center of a loop is determined.
02

Recall the formula for magnetic field at the center of a loop

The magnetic field at the center of a circular loop carrying a current can be calculated using the formula: \( B = \frac{\mu_0 I}{2R} \), where \( \mu_0 \) is the permeability of free space, \( I \) is the current, and \( R \) is the radius of the loop.
03

Substitute the known values in the magnetic field formula

Substitute \( I = 23.0 \ \text{A} \) and \( R = 0.28 \ \text{m} \) into the formula to find \( B \). Thus, \( B = \frac{4\pi \times 10^{-7} \times 23.0}{2 \times 0.28} \).
04

Calculate the magnetic field at the center of the loop

Compute the magnetic field using the substituted values: \( B = \frac{4\pi \times 10^{-7} \times 23.0}{2 \times 0.28} \approx 5.149 \times 10^{-5} \ \text{T} \).
05

Recall the formula for magnetic energy density

The magnetic energy density \( u \) is given by \( u = \frac{B^2}{2\mu_0} \), where \( B \) is the magnetic field, and \( \mu_0 \) is the permeability of free space.
06

Substitute the magnetic field in energy density formula

Substitute the value of \( B = 5.149 \times 10^{-5} \ \text{T} \) into the energy density formula: \( u = \frac{(5.149 \times 10^{-5})^2}{2 \times 4\pi \times 10^{-7}} \).
07

Calculate the energy density

Solve for \( u \) by computing the expression: \( u \approx 1.054 \times 10^{-4} \ \text{J/m}^3 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Magnetic Field
Magnetic fields are invisible forces that result from the movement of electric charges. When charges move, such as within a wire, they create a magnetic field that envelops the space around them.

To understand how strongly a magnetic field exerts its influence, we often quantify it using a term known as magnetic flux density or simply "magnetic field strength," denoted by the letter 'B'. The field falls into a vector category, meaning it has both magnitude and direction.

In the case of a circular loop of wire, the magnetic field is primarily concentrated at its center and diminishes as you move away from it. **To calculate it in a loop's center**, we use the expression:
  • \( B = \frac{\mu_0 I}{2R} \)
Here:
  • \( \mu_0 \) is the permeability of free space, approximately \( 4\pi \times 10^{-7} \ \text{T}\cdot\text{m/A} \)
  • \( I \) is the current passing through the loop
  • \( R \) is the radius of the loop
The strength of the magnetic field at the loop's center depends on the current's intensity and the loop radius, enabling us to determine the field accurately for further calculations, such as magnetic energy density.
Circular Loop of Wire
A circular loop of wire serves as a critical element in understanding magnetic fields, as it channels the flow of electric current into a circular, continuous path. The loop’s geometry plays a vital role in generating a uniform magnetic field at its center.

When current flows through the loop, the magnetic field lines form concentric circles around the wire, with the field strength peaking at the loop’s center. This configuration is frequently used in applications such as magnetic resonance imaging (MRI) and wireless charging.

The radius of the loop, denoted by 'R,' is a critical factor. It determines how spread out the field lines appear and how intense the magnetic field becomes. The smaller the radius, the stronger and more concentrated the field at the center, as per the formula discussed earlier.

Such loops also help augment our understanding of electromagnetism's principles, showcasing the interaction between electricity and magnetism and setting the stage for more complex setups like solenoids and coils.
Current in a Loop
The concept of electric current passing through a loop is quite fundamental and ties directly into the generation of magnetic fields. Current, measured in Amperes (A), is the rate of flow of charge through the wire, and it's this very flow that creates the surrounding magnetic field.

**When we talk about a 'current in a loop,'** we refer to a consistent and continuous flow around the circuit, which maintains the magnetic field's intensity and stability. In a practical scenario, like the one given in the exercise, a current of
  • 23.0 A is running through a wire loop
This stable current ensures the field remains constant and is crucial for precise calculations, such as determining magnetic energy density.

Increased current not only intensifies the magnetic field inside the loop, but also increases the energy stored in that field, as indicated by the relevant equations. This dependency explains why superconductors, materials that conduct current without resistance, can generate powerful magnetic fields when used in specific loop designs.

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Most popular questions from this chapter

(II) Capacitors made from piezoelectric materials are commonly used as sound transducers ("speakers"). They often require a large operating voltage. One method for providing the required voltage is to include the speaker as part of an \(L R C\) circuit as shown in Fig. \(29 ,\) where the speaker is modeled electrically as the capacitance \(C = 1.0 \mathrm { nF } .\) Take \(R = 35 \Omega\) and \(L = 55 \mathrm { mH } .\) (a) What is the resonant frequency \(f _ { 0 }\) for this circuit? (b) If the voltage source has peak amplitude \(V _ { 0 } = 2.0 \mathrm { V }\) at frequency \(f = f _ { 0 } ,\) find the peak voltage \(V _ { c 0 }\) across the speaker (i.e., the capacitor \(C\) ). (c) Determine the ratio \(V _ { C 0 } / V _ { 0 . }\)

A 425-pF capacitor is charged to \(135 \mathrm{~V}\) and then quickly connected to a \(175-\mathrm{mH}\) inductor. Determine \((a)\) the frequency of oscillation, \((b)\) the peak value of the current, and \((c)\) the maximum energy stored in the magnetic field of the inductor.

A \(75-\Omega\) resistor and a \(6.8-\mu \mathrm{F}\) capacitor are connected in series to an ac source. Calculate the impedance of the circuit if the source frequency is \((a) 60 \mathrm{~Hz} ;(b) 6.0 \mathrm{MHz}\)

At \(t = 0 ,\) the current through a 60.0 -mH inductor is 50.0\(\mathrm { mA }\) and is increasing at the rate of 78.0\(\mathrm { mA } / \mathrm { s } .\) What is the initial energy stored in the inductor, and how long does it take for the energy to increase by a factor of 5.0 from the initial value?

(I) At what frequency will a \(32.0-\mathrm{mH}\) inductor have a reactance of \(660 \Omega ?\)

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