Chapter 3: Problem 3
If \(V_{x}=7.80\) units and \(V_{y}=-6.40\) units, determine the magnitude and direction of \(\overrightarrow{\mathbf{V}}\).
Short Answer
Expert verified
The magnitude is approximately 10.09 units, and the direction is \(-39.19^\circ\) from the positive x-axis.
Step by step solution
01
Understanding the Components
You are given the components of the vector \(\overrightarrow{\mathbf{V}}\): \(V_{x} = 7.80\) units and \(V_{y} = -6.40\) units. These represent the horizontal and vertical components of the vector, respectively.
02
Calculating the Magnitude
To find the magnitude of vector \(\overrightarrow{\mathbf{V}}\), use the Pythagorean theorem: \[|\overrightarrow{\mathbf{V}}| = \sqrt{V_{x}^2 + V_{y}^2}\] Substitute the given values: \[|\overrightarrow{\mathbf{V}}| = \sqrt{(7.80)^2 + (-6.40)^2} = \sqrt{60.84 + 40.96} = \sqrt{101.80} \approx 10.09\] Thus, the magnitude of \(\overrightarrow{\mathbf{V}}\) is approximately 10.09 units.
03
Finding the Direction
The direction \(\theta\) of vector \(\overrightarrow{\mathbf{V}}\) is the angle it makes with the positive x-axis, calculated using the tangent function: \[\theta = \tan^{-1}\left(\frac{V_{y}}{V_{x}}\right)\]Substitute the given values: \[\theta = \tan^{-1}\left(\frac{-6.40}{7.80}\right) \approx \tan^{-1}(-0.8205) \approx -39.19^\circ\]Since the angle is negative, it indicates the vector is below the x-axis. Therefore, the direction of \(\overrightarrow{\mathbf{V}}\) is approximately \(-39.19^\circ\) from the positive x-axis.
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Magnitude of a Vector
The magnitude of a vector refers to its length or size. It is a fundamental concept in vector analysis and is used to determine how much a vector spans in the space it's defined. To calculate the magnitude of a vector
like \(\overrightarrow{\mathbf{V}}\)
with components \(V_x\) and \(V_y\), we use the Pythagorean Theorem. This is expressed through the formula:
the magnitude is calculated as:
\[|\overrightarrow{\mathbf{V}}| = \sqrt{(7.80)^2 + (-6.40)^2} = \sqrt{101.80} \approx 10.09\] So, for each specific direction, the vector spans approximately 10.09 units in magnitude.
like \(\overrightarrow{\mathbf{V}}\)
with components \(V_x\) and \(V_y\), we use the Pythagorean Theorem. This is expressed through the formula:
- \(|\overrightarrow{\mathbf{V}}| = \sqrt{V_{x}^2 + V_{y}^2}\)
the magnitude is calculated as:
\[|\overrightarrow{\mathbf{V}}| = \sqrt{(7.80)^2 + (-6.40)^2} = \sqrt{101.80} \approx 10.09\] So, for each specific direction, the vector spans approximately 10.09 units in magnitude.
Direction of a Vector
The direction of a vector indicates the orientation it has in its space, specifically regarding which way it "points". This direction is usually calculated as the angle with respect to a reference line, often the positive x-axis. To determine a vector's direction, you can use trigonometric functions, primarily the tangent function. Here is how you calculate it:
This gives you the direction in degrees from the x-axis. For instance, with \(V_{x} = 7.80\) and \(V_{y} = -6.40\), this becomes:
\[\theta = \tan^{-1}\left(\frac{-6.40}{7.80}\right) \approx -39.19^\circ\] The negative angle here indicates that the vector is positioned below the x-axis. Knowing this direction helps us understand not just where the vector ends but the path it follows from the origin.
- \(\theta = \tan^{-1}\left(\frac{V_{y}}{V_{x}}\right)\)
This gives you the direction in degrees from the x-axis. For instance, with \(V_{x} = 7.80\) and \(V_{y} = -6.40\), this becomes:
\[\theta = \tan^{-1}\left(\frac{-6.40}{7.80}\right) \approx -39.19^\circ\] The negative angle here indicates that the vector is positioned below the x-axis. Knowing this direction helps us understand not just where the vector ends but the path it follows from the origin.
Pythagorean Theorem
The Pythagorean Theorem is a principle of geometry that relates the sides of a right triangle. It states that for a right triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides:
For example, if we have components \(V_x = 7.80\) and \(V_y = -6.40\), we plug these into the theorem's formula:
\[(7.80)^2 + (-6.40)^2 = (\overrightarrow{\mathbf{V}})^2\] Solving this equation helps demonstrate that the vector's magnitude, as calculated by its components, is consistent and precise.
- \(a^2 + b^2 = c^2\)
For example, if we have components \(V_x = 7.80\) and \(V_y = -6.40\), we plug these into the theorem's formula:
\[(7.80)^2 + (-6.40)^2 = (\overrightarrow{\mathbf{V}})^2\] Solving this equation helps demonstrate that the vector's magnitude, as calculated by its components, is consistent and precise.