/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 5 (II) A circular wire loop of rad... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

(II) A circular wire loop of radius \(r=12 \mathrm{~cm}\) is immersed in a uniform magnetic field \(B=0.500 \mathrm{~T}\) with its plane normal to the direction of the field. If the field magnitude then decreases at a constant rate of \(-0.010 \mathrm{~T} / \mathrm{s}\), at what rate should \(r\) increase so that the induced emf within the loop is zero?

Short Answer

Expert verified
The radius should increase at 0.0012 m/s to keep the induced emf zero.

Step by step solution

01

Understanding Faraday's Law of Induction

According to Faraday's law of electromagnetic induction, the induced emf (\(\varepsilon\)) in a loop is equal to the negative rate of change of magnetic flux through the loop, i.e., \(\varepsilon = -\frac{d\Phi}{dt}\), where \(\Phi\) is the magnetic flux.
02

Expression for Magnetic Flux

The magnetic flux \(\Phi\) through the loop is given by \(\Phi = B \cdot A\), where \(A\) is the area of the loop. For a circular loop of radius \(r\), area \(A = \pi r^2\). Thus, \(\Phi = B \cdot \pi r^2\).
03

Differentiate Magnetic Flux

Differentiate the expression for magnetic flux \(\Phi = B \cdot \pi r^2\) with respect to time \(t\):\[\frac{d\Phi}{dt} = \pi r^2 \frac{dB}{dt} + 2\pi r B \frac{dr}{dt}\]This accounts for changes in both \(B\) and \(r\).
04

Apply the Condition for Zero Induced EMF

For the induced emf to be zero, \(\varepsilon = -\frac{d\Phi}{dt} = 0\). Thus,\[\pi r^2 \frac{dB}{dt} + 2\pi r B \frac{dr}{dt} = 0\]Simplifying, we get \(r^2 \frac{dB}{dt} + 2r B \frac{dr}{dt} = 0\).
05

Solve for the Rate of Radius Change

Rearranging the equation from Step 4 gives:\[\frac{dr}{dt} = -\frac{r}{2B} \cdot \frac{dB}{dt}\]Substituting \(r = 0.12\) m, \(B = 0.500\) T, and \(\frac{dB}{dt} = -0.010\) T/s:\[\frac{dr}{dt} = -\frac{0.12}{2 \times 0.500} \times (-0.010) = 0.0012 \, \text{m/s}\]Thus, the radius should increase at the rate of 0.0012 m/s.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Magnetic Flux
Magnetic flux is a fundamental concept in electromagnetism that refers to the measure of the magnetic field passing through a given area. Imagine a magnetic "stream" flowing through a loop; the flux quantifies how much of this stream crosses the surface area you're considering. Mathematically, it can be expressed as - \( \Phi = B \cdot A \) - where \( B \) is the magnetic field strength and \( A \) is the area through which the field lines pass. In our case, with a circular wire loop, the area \( A \) is the area of the circle, which is calculated by \( \pi r^2 \), where \( r \) is the radius of the loop. This means the magnetic flux through a circular loop is - \( \Phi = B \cdot \pi r^2 \). - When a magnetic field changes over time, the magnetic flux does too, leading us to a related concept: the induced emf.
Induced EMF
Induced electromotive force, or emf, is the voltage generated in a conductor when it experiences a change in magnetic flux. This principle is described by Faraday's Law of Induction, a cornerstone of electromagnetism. Faraday's Law states that the induced emf in a closed loop equals the negative rate of change of magnetic flux through the loop: - \( \varepsilon = - \frac{d\Phi}{dt} \). - In simpler terms, if magnetic flux is changing, an emf is induced to oppose this change—a reflection of Lenz's Law. Let's say the magnetic field through a loop starts decreasing. The induced emf will work to drive a current that maintains the original flux, creating a self-stabilizing mechanism. In the case study we examined, the decreasing magnetic field means \( \frac{dB}{dt} \) is negative. However, to maintain zero induced emf, the radius of the loop must change in such a way that the total change in flux is zero.
Circular Wire Loop
A circular wire loop is a versatile tool in electromagnetism, used to detect changes in the magnetic field. Picture a simple circular ring sitting perpendicular to the direction of a magnetic field line, much like a hula-hoop in mid-air with a breeze flowing through it. This set-up maximizes the magnetic flux in the loop. As the magnetic field changes, either by altering its strength or by mechanical movements of the loop, the area through which the field lines pass can adjust. In mathematical terms, the area is defined as - \( \pi r^2 \), - where the radius \( r \) can change over time to compensate for any changes in the field. The relationship between magnetic flux and Induced emf is crucial here. If, as in the exercise, the magnetic field decreases at a constant rate, the looping radius must increase to cancel out any changes in flux, thus keeping the induced emf at zero. This delicate interplay ensures that changing one variable can balance the effect of another.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

(I) A 22.0-cm-diameter loop of wire is initially oriented perpendicular to a 1.5-T magnetic field. The loop is rotated so that its plane is parallel to the field direction in \(0.20 \mathrm{~s}\) s. What is the average induced emf in the loop?

A high-intensity desk lamp is rated at \(35 \mathrm{~W}\) but requires only \(12 \mathrm{~V}\). It contains a transformer that converts \(120-\mathrm{V}\) household voltage. ( \(a\) ) Is the transformer step-up or stepdown? (b) What is the current in the secondary coil when the lamp is on? (c) What is the current in the primary coil? ( \(d\) ) What is the resistance of the bulb when on?

(II) A model-train transformer plugs into \(120-\mathrm{V}\) ac and draws \(0.35 \mathrm{~A}\) while supplying \(7.5 \mathrm{~A}\) to the train. \((a)\) What voltage is present across the tracks? (b) Is the transformer step-up or step- down?

(II) While demonstrating Faraday's law to her class, a physics professor inadvertently moves the gold ring on her finger from a location where a \(0.80-\mathrm{T}\) magnetic field points along her finger to a zero-field location in 45 \(\mathrm{ms}\) . The 1.5-cm-diameter ring has a resistance and mass of 55\(\mu \Omega\) and 15 g, respectively. (a) Estimate the thermal energy produced in the ring due to the flow of induced current. (b) Find the temperature rise of the ring, assuming all of the thermal energy produced goes into increasing the ring's temperature. The specific heat of gold is 129 \(\mathrm{J} / \mathrm{kg} \cdot \mathrm{C}^{\circ} .\)

A ring with a radius of \(3.0 \mathrm{~cm}\) and a resistance of \(0.025 \Omega\) is rotated about an axis through its diameter by \(90^{\circ}\) in a magnetic field of \(0.23 \mathrm{~T}\) perpendicular to that axis. What is the largest number of electrons that would flow past a fixed point in the ring as this process is accomplished?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.