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(II) A circular loop in the plane of the paper lies in a 0.75-T magnetic field pointing into the paper. If the loop's diameter changes from \(20.0 \mathrm{~cm}\) to \(6.0 \mathrm{~cm}\) in \(0.50 \mathrm{~s}\), (a) what is the direction of the induced current, \((b)\) what is the magnitude of the average induced emf, and \((c)\) if the coil resistance is \(2.5 \Omega\), what is the average induced current?

Short Answer

Expert verified
(a) Clockwise; (b) 0.042855 V; (c) 0.017142 A.

Step by step solution

01

Understanding the direction of induced current

According to Lenz's Law, the induced current flows in a direction that opposes the change in magnetic flux through the loop. Since the magnetic field is pointing into the paper and the loop is shrinking, the magnetic flux through the loop is decreasing. The induced current will therefore create a magnetic field pointing into the paper to oppose this decrease.
02

Calculate initial and final areas

The area of a circle is given by the formula \(A = \pi r^2\). First, calculate the radius of the loop in its initial and final states:- Initial diameter = \(20.0\, \text{cm}\) gives \(r_1 = 10.0\, \text{cm} = 0.1\, \text{m}\).- Final diameter = \(6.0\, \text{cm}\) gives \(r_2 = 3.0\, \text{cm} = 0.03\, \text{m}\).Then, calculate the areas:\[A_1 = \pi (0.1)^2 = 0.0314\, \text{m}^2\]\[A_2 = \pi (0.03)^2 = 0.00283\, \text{m}^2\]
03

Calculate change in magnetic flux

Magnetic flux \(\Phi\) is given by \(\Phi = B \cdot A\), where \(B = 0.75\, \text{T}\) is the magnetic field:- Initial flux: \(\Phi_1 = B \times A_1 = 0.75 \times 0.0314 = 0.02355\, \text{Wb}\)- Final flux: \(\Phi_2 = B \times A_2 = 0.75 \times 0.00283 = 0.0021225\, \text{Wb}\)Change in flux: \(\Delta \Phi = \Phi_2 - \Phi_1 = 0.0021225 - 0.02355 = -0.0214275\, \text{Wb}\) (the negative sign indicates a reduction).
04

Calculate the magnitude of average induced emf

The average induced emf \(\varepsilon\) is given by Faraday's Law: \(\varepsilon = -\frac{\Delta \Phi}{\Delta t}\), where \(\Delta t = 0.50\, \text{s}\):\[\varepsilon = -\frac{-0.0214275}{0.50} = 0.042855\, \text{V}\]
05

Calculate the average induced current

Using Ohm's Law, the average induced current \(I\) is given by \(I = \frac{\varepsilon}{R}\), where \(R = 2.5\, \Omega\) is the coil resistance:\[I = \frac{0.042855}{2.5} = 0.017142\, \text{A}\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Lenz's Law
Lenz's Law is a fundamental principle in electromagnetism that describes the direction of induced current resulting from changes in magnetic flux. When a magnetic field through a circuit changes, an electromotive force (emf) is induced. According to Lenz's Law, this induced emf generates a current that flows in a direction that opposes the change in the magnetic flux.

In the context of the circular loop exercise, the magnetic field is pointing into the paper and is constant in magnitude. However, as the loop's diameter is decreasing, the magnetic flux through the loop is also decreasing.

According to Lenz's Law:
  • The induced current will flow in a direction such that it tries to keep the original magnetic flux constant.
  • Given that the magnetic flux is reducing (since the area of the loop is decreasing), the induced current will generate a field pointing into the paper to oppose the reduction.
This ensures that the magnetic field generated by the induced current acts to counterbalance the diminishing magnetic flux, aligning with Lenz's Law.
Faraday's Law
Faraday's Law quantifies the induced electromotive force (emf) in a loop resulting from a change in magnetic flux over time. It is given by the equation:
  • \[ \varepsilon = - \frac{\Delta \Phi}{\Delta t} \]
Here, \( \varepsilon \) is the induced emf, \( \Delta \Phi \) is the change in magnetic flux, and \( \Delta t \) is the time interval over which this change occurs.

In this scenario, the magnetic flux changes because the area of the circular loop reduces as its diameter decreases from 20 cm to 6 cm. The change in flux \( \Delta \Phi \) was calculated using the formula for the area of a circle \( A = \pi r^2 \), and then applying the flux equation \( \Phi = B \times A \) with a constant magnetic field \( B = 0.75 \, \text{T} \).

The resulting change in flux was used to determine the average induced emf using the equation from Faraday's Law, yielding an emf of \( 0.042855 \, \text{V} \).

Keep in mind that the negative sign in Faraday's Law depicts Lenz's Law, indicating the direction of the induced emf opposes the change in flux.
Ohm's Law
Ohm's Law is a key principle that relates voltage, current, and resistance in an electrical circuit. It is fundamental for solving problems involving induced current and is expressed as:
  • \[ I = \frac{\varepsilon}{R} \]
Where \( I \) is the current, \( \varepsilon \) is the electromotive force or voltage, and \( R \) is the resistance within the circuit.

After calculating the induced emf using Faraday's Law, Ohm's Law helps us find the average induced current in the loop. Given the coil resistance of \( 2.5 \, \Omega \), and the induced emf \( \varepsilon = 0.042855 \, \text{V} \), the induced current is \( 0.017142 \, \text{A} \).

This relation underscores how resistance impacts the induced current, with higher resistance reducing the current flow for a given emf. Understanding and applying Ohm's Law is crucial for completing circuits with varying sources of emf, especially those induced by changing magnetic fields.

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Most popular questions from this chapter

(II) \(\mathrm{A} 25\) -cm-diameter circular loop of wire has a resistance of 150\(\Omega .\) It is initially in a \(0.40-\mathrm{T}\) magnetic field, with its plane perpendicular to \(\overline{\mathbf{B}}\) , but is removed from the field in 120 \(\mathrm{ms}\) . Calculate the electric energy dissipated in this process.

In a certain region of space near Earth's surface, a uniform horizontal magnetic field of magnitude \(B\) exists above a level defined to be \(y=0 .\) Below \(y=0,\) the field abruptly becomes zero (Fig. \(29-54\) ). A vertical square wire loop has resistivity \(\rho,\) mass density \(\rho_{m},\) diameter \(d,\) and side length \(\ell .\) It is initially at rest with its lower horizontal side at \(y=0\) and is then allowed to fall under gravity, with its plane perpendicular to the direction of the magnetic field. ( \(a\) ) While the loop is still partially immersed in the magnetic field (as it falls into the zero-field region), determine the magnetic "drag" force that acts on it at the moment when its speed is \(v .(b)\) Assume that the loop achieves a terminal velocity \(v_{\mathrm{T}}\) before its upper horizontal side exits the field. Determine a formula for \(v_{\mathrm{T}}\). \((c)\) If the loop is made of copper and \(B=0.80 \mathrm{~T},\) find \(v_{\mathrm{T}}\).

(III) In an experiment, a coil was mounted on a low-friction cart that moved through the magnetic field \(B\) of a permanent magnet. The speed of the cart \(v\) and the induced voltage \(V\) were simultaneously measured, as the cart moved through the magnetic field, using a computer-interfaced motion sensor and a voltmeter. The Table below shows the collected data: $$ \begin{array}{lrrrrr} \hline \text { Speed, } v(\mathrm{~m} / \mathrm{s}) & 0.367 & 0.379 & 0.465 & 0.623 & 0.630 \\ \text { Induced voltage, } V(\mathrm{~V}) & 0.128 & 0.135 & 0.164 & 0.221 & 0.222 \\ \hline \end{array} $$ (a) Make a graph of the induced voltage, \(V\), vs. the speed, \(v\). Determine a best-fit linear equation for the data. Theoretically, the relationship between \(V\) and \(v\) is given by \(V=B N \ell v\) where \(N\) is the number of turns of the coil, \(B\) is the magnetic field, and \(\ell\) is the average of the inside and outside widths of the coil. In the experiment, \(B=0.126 \mathrm{~T}, N=50,\) and \(\ell=0.0561 \mathrm{~m} .\) (b) Find the \(\%\) error between the slope of the experimental graph and the theoretical value for the slope. \((c)\) For each of the measured speeds \(v\), determine the theoretical value of \(V\) and find the \(\%\) error of each.

(II) A 25 -cm-diameter circular loop of wire has a resistance of \(150 \Omega\). It is initially in a 0.40-T magnetic field, with its plane perpendicular to \(\overrightarrow{\mathbf{B}},\) but is removed from the field in \(120 \mathrm{~ms}\). Calculate the electric energy dissipated in this process.

Power is generated at \(24 \mathrm{kV}\) at a generating plant located \(85 \mathrm{~km}\) from a town that requires \(65 \mathrm{MW}\) of power at \(12 \mathrm{kV}\) Two transmission lines from the plant to the town each have a resistance of \(0.10 \Omega / \mathrm{km} .\) What should the output voltage of the transformer at the generating plant be for an overall transmission efficiency of \(98.5 \%,\) assuming a perfect transformer?

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