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(I) The magnetic flux through a coil of wire containing two loops changes at a constant rate from \(-58 \mathrm{~Wb}\) to \(+38 \mathrm{~Wb}\) in \(0.42 \mathrm{~s}\). What is the emf induced in the coil?

Short Answer

Expert verified
The induced emf is approximately -457.14 V.

Step by step solution

01

Understand the Formula for Induced EMF

The induced electromotive force (emf) in a coil is calculated using Faraday's Law of Electromagnetic Induction. The formula is \( \text{emf} = -n \frac{\Delta \Phi}{\Delta t} \), where \( n \) is the number of loops, \( \Delta \Phi \) is the change in magnetic flux, and \( \Delta t \) is the change in time.
02

Identify Given Values

From the problem, we have \( n = 2 \) loops, the change in magnetic flux \( \Delta \Phi \) from \( -58 \text{ Wb} \) to \( +38 \text{ Wb} \), and \( \Delta t = 0.42 \text{ s} \).
03

Calculate Change in Magnetic Flux

The change in magnetic flux \( \Delta \Phi \) is calculated as: \( \Delta \Phi = \Phi_{final} - \Phi_{initial} = 38 \text{ Wb} - (-58 \text{ Wb}) = 96 \text{ Wb} \).
04

Apply Faraday's Law to Find the Induced EMF

Substitute the values into the formula:\[ \text{emf} = -2 \times \frac{96 \text{ Wb}}{0.42 \text{ s}} \]Calculate the result:\[ \text{emf} = -2 \times 228.57 \approx -457.14 \text{ V} \]
05

Conclude Solution

The negative sign indicates the direction of the induced emf as per Lenz's Law. The magnitude of the induced emf in the coil is approximately \( 457.14 \text{ V} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Induced Electromotive Force (emf)
Electromotive force, or emf, is a term used in electromagnetism to describe the potential difference that can cause current to flow in a circuit. In the context of Faraday's Law of Electromagnetic Induction, an induced emf is generated when there is a change in magnetic flux through a coil. This is not a force as its name might suggest, but rather a voltage. Faraday's Law states that the induced emf is equal to the negative rate of change of magnetic flux multiplied by the number of loops in the coil. The formula is given by:
  • \( \text{emf} = -n \frac{\Delta \Phi}{\Delta t} \)
Here, \( n \) is the number of loops, \( \Delta \Phi \) is the change in magnetic flux, and \( \Delta t \) is the change in time. This induced emf is what causes a current to flow if the circuit is closed.
The negative sign in the formula signifies the direction of the induced emf as explained by Lenz's Law which we will discuss in a later section. Understanding this concept is fundamental to using Faraday's Law in problems involving electromagnetic induction.
Magnetic Flux
Magnetic flux refers to the amount of magnetic field passing through a given surface area. It is an important concept when discussing electromagnetic induction. The magnetic flux \( \Phi \) through a surface is given by the equation:
  • \( \Phi = B \cdot A \cdot \cos(\theta) \)
where \( B \) is the magnetic field, \( A \) is the area the field lines pass through, and \( \theta \) is the angle between the magnetic field lines and the normal (perpendicular) to the surface.
In the exercise, the magnetic flux changes from \(-58\) to \(+38\) Weber (Wb), a unit of magnetic flux. The greater this change in a given time, the higher the induced emf according to Faraday's Law. Flux helps us to quantify the number or density of magnetic field lines intersecting a coil or surface, and hence it's fundamental when calculating induced emf.
Changes in magnetic flux can occur due to variations in the magnetic field strength, the area of the loop, or the angle between them.
Lenz's Law
Lenz's Law is a fundamental principle that helps determine the direction of the induced current resulting from a change in magnetic flux. This law is part of the broader Faraday's Law, characterized by the negative sign in the induced emf formula \( \text{emf} = -n \frac{\Delta \Phi}{\Delta t} \). Lenz's Law states that the direction of the induced emf and, therefore, the induced current is such that it opposes the change in magnetic flux that caused it.
In simpler terms, if an increase in magnetic flux occurs, the induced current will create its magnetic field opposing the increase. Conversely, if the magnetic flux decreases, the induced current will create its magnetic field to increase it. This law is a manifestation of the conservation of energy, ensuring that the induced effects oppose the change that produces them.
In our given solution, the negative sign in the computed emf of \(-457.14 \text{ V}\) indicates this opposition, pointing to how the induced current would flow to counteract the increasing magnetic flux.

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Most popular questions from this chapter

(II) A 22.0-cm-diameter coil consists of 28 turns of circular copper wire \(2.6 \mathrm{~mm}\) in diameter. A uniform magnetic field, perpendicular to the plane of the coil, changes at a rate of \(8.65 \times 10^{-3} \mathrm{~T} / \mathrm{s}\). Determine \((a)\) the current in the loop, and (b) the rate at which thermal energy is produced.

(II) A 420-turn solenoid, \(25 \mathrm{~cm}\) long, has a diameter of \(2.5 \mathrm{~cm}\). A 15-turn coil is wound tightly around the center of the solenoid. If the current in the solenoid increases uniformly from 0 to \(5.0 \mathrm{~A}\) in \(0.60 \mathrm{~s}\), what will be the induced emf in the short coil during this time?

(II) A single circular loop of wire is placed inside a long solenoid with its plane perpendicular to the axis of the solenoid. The area of the loop is \(A_{1}\) and that of the solenoid, which has \(n\) turns per unit length, is \(A_{2} .\) A current \(I=I_{0} \cos \omega t\) flows in the solenoid turns. What is the induced emf in the small loop?

(II) When a car drives through the Earth's magnetic field, an \(\mathrm{emf}\) is induced in its vertical \(75.0-\mathrm{cm}\) -long radio antenna. If the Earth's field \(\left(5.0 \times 10^{-5} \mathrm{~T}\right)\) points north with a dip angle of \(45^{\circ},\) what is the maximum emf induced in the antenna and which direction(s) will the car be moving to produce this maximum value? The car's speed is \(30.0 \mathrm{~m} / \mathrm{s}\) on a horizontal road.

A coil with 150 turns, a radius of \(5.0 \mathrm{~cm},\) and a resistance of \(12 \Omega\) surrounds a solenoid with 230 turns \(/ \mathrm{cm}\) and a radius of \(4.5 \mathrm{~cm}\); see Fig. \(29-50 .\) The current in the solenoid changes at a constant rate from 0 to \(2.0 \mathrm{~A}\) in \(0.10 \mathrm{~s}\). Calculate the magnitude and direction of the induced current in the 150 -turn coil.

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