Chapter 28: Problem 16
(II) A power line carries a current of \(95 \mathrm{~A}\) west along the tops of 8.5 -m-high poles. ( \(a\) ) What is the magnitude and direction of the magnetic field produced by this wire at the ground directly below? How does this compare with the Earth's field of about \(\frac{1}{2} \mathrm{G} ?(b)\) Where would the line's field cancel the Earth's?
Short Answer
Step by step solution
Understanding the problem
Using Biot-Savart Law
Calculating Magnetic Field below the wire
Comparing with Earth's magnetic field
Finding location where fields cancel
Calculating the cancellation distance
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Biot-Savart Law
Current-Carrying Wire
- In our example, a power line carries a current of 95 A.
- The wire is suspended 8.5 meters above the ground.
- This configuration allows us to determine the magnetic field at various points below it.
Magnetic Field Comparison
- Earth's magnetic field is about 0.5 G .
- The calculated field from the wire must be compared to this value.
Earth's Magnetic Field
- Human-made fields can interfere with navigational instruments.
- Infrastructure like power lines can add to or subtract from Earth's magnetic field depending on their orientation.
Magnetic Field Cancellation
- Set the magnetic field formula equal to 0.5 \times 10^{-4} T.
- Solve for \( r \), the distance from the wire where the cancellation occurs.