Chapter 27: Problem 8
A long wire stretches along the \(x\) axis and carries a 3.0-A current to the right \((+x)\). The wire is in a uniform magnetic field \(\overrightarrow{\mathbf{B}}=(0.20 \hat{\mathbf{i}}-0.36 \hat{\mathbf{j}}+0.25 \hat{\mathbf{k}})\) T. Determine the components of the force on the wire per \(\mathrm{cm}\) of length.
Short Answer
Step by step solution
Understand the Force on a Current-Carrying Wire
Identify the Components
Set-up the Cross Product
Perform the Cross Product
Calculate the Force Components
Conclude the Components of the Force per cm of Wire
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Current-Carrying Wire
For instance, a wire with a 3.0 A current, like the one mentioned in the original exercise, means that 3.0 coulombs of charge are flowing through the wire per second. This current can interact with other elements, such as a magnetic field, to produce some interesting phenomena.
Key elements to remember about current-carrying wires:
- Current direction is important. It dictates how the wire interacts with external fields.
- Current is measured in amperes (A).
- The wire's length along a particular axis can be represented as a vector (e.g., along the \( x \) axis, it is \( L \hat{\mathbf{i}} \)).
Cross Product
In the formula \( \overrightarrow{\mathbf{F}} = I \cdot \left( \overrightarrow{\mathbf{L}} \times \overrightarrow{\mathbf{B}} \right) \), the cross product \( \overrightarrow{\mathbf{L}} \times \overrightarrow{\mathbf{B}} \) produces a new vector perpendicular to both \( \overrightarrow{\mathbf{L}} \) and \( \overrightarrow{\mathbf{B}} \). This new vector is crucial for calculating the magnetic force.
Considerations when dealing with cross products:
- The cross product of two parallel vectors is zero.
- The right-hand rule helps determine the direction of the resultant vector.
- Unit vector combinations, such as \( \hat{\mathbf{i}} \times \hat{\mathbf{j}} = \hat{\mathbf{k}} \), are helpful references for solving cross products.
Magnetic Field
We represent a magnetic field with a vector \( \overrightarrow{\mathbf{B}} \), which showcases both its magnitude and direction. In the exercise, the magnetic field \( \overrightarrow{\mathbf{B}} = (0.20 \hat{\mathbf{i}} - 0.36 \hat{\mathbf{j}} + 0.25 \hat{\mathbf{k}}) \), suggests a field pointing in a 3D space with specific influences along the \( \hat{\mathbf{i}}, \hat{\mathbf{j}}, \) and \( \hat{\mathbf{k}} \) directions.
Key points to note about magnetic fields:
- They exist around magnets and moving electric charges.
- The strength and direction of the magnetic field are described by the vector \( \overrightarrow{\mathbf{B}} \).
- Magnetic fields exert forces on current-carrying wires, which can be calculated using the cross product.