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(I) The heating element of an electric oven is designed to produce \(3.3 \mathrm{~kW}\) of heat when connected to a \(240-\mathrm{V}\) source. What must be the resistance of the element?

Short Answer

Expert verified
The resistance must be approximately 17.45 ohms.

Step by step solution

01

Understand the Formula for Power

The power (P) of an electrical element can be calculated using the formula:\[P = \frac{V^2}{R}\]whereP is the power in watts (W),V is the voltage in volts (V), andR is the resistance in ohms (\(\Omega\)).We can rearrange this formula to solve for resistance:\[R = \frac{V^2}{P}\].
02

Convert Kilowatts to Watts

The power given is 3.3 kilowatts (kW). To use the formula from Step 1, the power must be in watts (W). Since 1 kW = 1000 W, we convert as follows:\[P = 3.3 \times 1000 = 3300 \text{ W}\].
03

Substitute Values into the Equation

Substitute the given values for power (P = 3300 W) and voltage (V = 240 V) into the rearranged formula:\[R = \frac{V^2}{P} = \frac{240^2}{3300}\].
04

Calculate the Resistance

Calculate the resistance using a calculator:\[240^2 = 57600\],\[R = \frac{57600}{3300} \approx 17.45 \Omega\].Thus, the resistance of the heating element is approximately 17.45 ohms.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Power Calculation in Electric Circuits
The power calculation is a fundamental concept in understanding electric circuits. Power, in electrical terms, is the rate at which energy is used or transformed in a circuit. It is measured in watts (W). In our context, power is calculated using the formula \( P = \frac{V^2}{R} \), which is derived from combining Ohm's Law and the basic formula for electrical power \( P = IV \).
Knowing how to rearrange this formula is crucial as it allows us to solve for various unknowns, such as resistance in this example. When given a problem, always ensure your power value is converted to watts if it isn't already, because equations rely on consistent units.
Understanding power calculations help you determine how much energy a device uses, which is important for energy management and design of electrical systems.
  • Convert kilowatts to watts by multiplying by 1000. In our exercise, 3.3 kW becomes 3300 W.
  • Use the formula \( R = \frac{V^2}{P} \) to find resistance when power and voltage are known.
Understanding Resistance in Circuits
Resistance is a measure of how much a component in a circuit opposes the flow of electric current. It’s measured in ohms (\( \Omega \)).
The resistance determines how much current flows for a given voltage. Higher resistance means less current flows, while lower resistance allows more current to pass through.
  • Resistance is calculated with the rearranged power formula: \( R = \frac{V^2}{P} \).
  • In our example, substituting the voltage 240 V and the power 3300 W gives approximately 17.45 ohms.
Knowing resistance helps in designing circuits to ensure they function correctly and safely. It influences how much heat is produced and how efficiently a device operates. By managing resistance, you can conserve energy and avoid overheating.
Ohm's Law Basics
Ohm's Law is a foundational principle in electricity, stating that the current flowing through a conductor between two points is directly proportional to the voltage across the two points, assuming temperature remains constant. It is articulated in the formula \( V = IR \), where \( V \) is voltage, \( I \) is current, and \( R \) is resistance.
This law is pivotal because it links the three basic properties of electric circuits: voltage, current, and resistance. Understanding Ohm's Law helps you predict how circuits will behave under different conditions and solve complex circuit problems by breaking them into simpler calculations.
In the context of the exercise, while we focused on power calculations, Ohm's Law underpins our ability to rearrange and manipulate formulas to find missing values such as resistance. It forms the basis from which the power formula \( P = \frac{V^2}{R} \) is derived, demonstrating the interconnection between these essential concepts in electrical engineering.

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Most popular questions from this chapter

A person accidentally leaves a car with the lights on. If each of the two headlights uses \(40 \mathrm{~W}\) and each of the two taillights \(6 \mathrm{~W},\) for a total of \(92 \mathrm{~W},\) how long will a fresh \(12-\mathrm{V}\) battery last if it is rated at \(85 \mathrm{~A} \cdot \mathrm{h} ?\) Assume the full \(12 \mathrm{~V}\) appears across each bulb.

The Tevatron accelerator at Fermilab (Illinois) is designed to carry an 11 -mA beam of protons traveling at very nearly the speed of light \(\left(3.0 \times 10^{8} \mathrm{~m} / \mathrm{s}\right)\) around a ring \(6300 \mathrm{~m}\) in circumference. How many protons are in the beam?

(II) Estimate the resistance of the \(120-\mathrm{V}_{\mathrm{rms}}\) circuits in your house as seen by the power company, when ( \(a\) ) everything electrical is unplugged, and \((b)\) there are two \(75-\mathrm{W}\) lightbulbs burning.

(II) A \(120-\mathrm{V}\) hair dryer has two settings: 850 \(\mathrm{W}\) and 1250 \(\mathrm{W}\) . (a) At which setting do you expect the resistance to be higher? After making a guess, determine the resistance at (b) the lower setting; and (c) the higher setting.

A proposed electric vehicle makes use of storage batteries as its source of energy. Its mass is \(1560 \mathrm{~kg}\) and it is powered by 24 batteries, each \(12 \mathrm{~V}, 95 \mathrm{~A} \cdot \mathrm{h}\). Assume that the car is driven on level roads at an average speed of \(45 \mathrm{~km} / \mathrm{h},\) and the average friction force is \(240 \mathrm{~N}\). Assume \(100 \%\) efficiency and neglect energy used for acceleration. No energy is consumed when the vehicle is stopped, since the engine doesn't need to idle. (a) Determine the horsepower required. (b) After approximately how many kilometers must the batteries be recharged?

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