/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 70 Sketch the electric field and eq... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Sketch the electric field and equipotential lines for two charges of the same sign and magnitude separated by a distance \(d\).

Short Answer

Expert verified
Electric field lines radiate outwards and bulge between the charges; equipotential lines form arcs.

Step by step solution

01

Understand the Scenario

We are dealing with two charges, both having the same sign and magnitude, which means they repel each other. The problem asks for the electric field lines and equipotential lines.
02

Sketch the Electric Field Lines

Electric field lines start at positive charges and end at negative charges. Since both charges have the same sign, the lines will radiate outward from each charge and bulge outwards between them due to repulsion.
03

Sketch the Equipotential Lines

Equipotential lines are perpendicular to the electric field lines and represent points of equal electric potential. For two like charges, these lines will form concentric circles around each charge, and in the region between the charges, they will arc outwards, maintaining perpendicularity to the field lines.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Equipotential Lines
Equipotential lines are a fascinating feature in the study of electric fields. These lines represent areas where the electric potential is constant. Imagine an invisible contour map, where each line signifies the same electric potential along its path. No work is required to move a charge along these lines because the potential energy doesn't change.
Understanding their interaction with electric field lines is crucial. These lines are always perpendicular to electric field lines. This is because the electric field points in the direction of decreasing potential. For like charges, say two positive charges, equipotential lines look like bulging circles around each charge. In the region between the charges, they arc gracefully outward.
To visualize this, picture the electric field lines as sunbeams radiating outward from each charge. The equipotential lines act as invisible walls, cutting across these beams, illustrating equal potential points. They provide a clear demonstration of the underlying electric field structure without actually moving the charges.
Like Charges
Like charges, such as two positive charges, exhibit a repulsive force. According to Coulomb's Law, this repulsion grows stronger as the charges come closer. This is due to the nature of the electric field they create. Electric field lines demonstrate this effect clearly by pointing away from each charge.
When placed near each other, these charges will exert forces on each other, pushing them apart. This is because like charges repel, wanting more space between them. As a result, field lines from one charge appear as if they bulge outward to circumvent the other charge's field.
The implications of like charges repelling each other are vast. It's not just about the lines escaping from each other, but about the nature of electric interactions. In practical situations, understanding this concept can be applied in technologies ranging from the mundane act of combing your hair to the art of designing electric circuits.
Electric Potential
Electric potential is a concept that helps us understand how much potential energy a unit charge would have in a field. It's akin to a hill or a valley in a topographic map; hills represent high potential energy, while valleys represent low potential energy.
In the context of our two like charges, each creates its own area of influence or potential. This potential is highest right at the charge and decreases with distance. When visualizing this, equipotential lines come into play, showing where the potential is the same. Around each charge, these lines form concentric circles, depicting areas of equal electric potential.
Understanding electric potential is vital because it directs the movement of charges. A charge will naturally move from a region of high potential to low potential. This movement is spontaneous, involving no external work, and is driven purely by the differences in electric potential. Exploring this principle helps us grasp why charges behave the way they do in various electric fields.

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Most popular questions from this chapter

(III) The volume charge density \(\rho_{\mathrm{E}}\) within a sphere of radius \(r_{0}\) is distributed in accordance with the following spherically symmetric relation $$ \rho_{\mathrm{E}}(r)=\rho_{0}\left[1-\frac{r^{2}}{r_{0}^{2}}\right] $$ where \(r\) is measured from the center of the sphere and \(\rho_{0}\) is a constant. For a point \(\mathrm{P}\) inside the sphere \(\left(r

(II) Many chemical reactions release energy. Suppose that at the beginning of a reaction, an electron and proton are separated by \(0.110 \mathrm{nm}\), and their final separation is \(0.100 \mathrm{nm}\) How much electric potential energy was lost in this reaction (in units of \(\mathrm{eV}\) )?

(I) Thunderclouds typically develop voltage differences of about \(1 \times 10^{8} \mathrm{~V}\). Given that an electric field of \(3 \times 10^{6} \mathrm{~V} / \mathrm{m}\) is required to produce an electrical spark within a volume of air, estimate the length of a thundercloud lightning bolt. [Can you see why, when lightning strikes from a cloud to the ground, the bolt actually has to propagate as a sequence of steps?]

(II) Two point charges, 3.4\(\mu \mathrm{C}\) and \(-2.0 \mu \mathrm{C},\) are placed 5.0 \(\mathrm{cm}\) apart on the \(x\) axis. At what points along the \(x\) axis is \((a)\) the electric field zero and \((b)\) the potential zero? Let \(V=0\) at \(r=\infty\) .

(III) You are trying to determine an unknown amount of charge using only a voltmeter and a ruler, knowing that it is either a single sheet of charge or a point charge that is creating it. You determine the direction of greatest change of potential, and then measure potentials along a line in that direction. The potential versus position (note that the zero of position is arbitrary, and the potential is measured relative to ground) is measured as follows: $$ \begin{array}{lllllllllll} \hline x(\mathrm{~cm}) & 0.0 & 1.0 & 2.0 & 3.0 & 4.0 & 5.0 & 6.0 & 7.0 & 8.0 & 9.0 \\ \mathrm{~V} \text { (volts) } & 3.9 & 3.0 & 2.5 & 2.0 & 1.7 & 1.5 & 1.4 & 1.4 & 1.2 & 1.1 \\ \hline \end{array} $$ (a) Graph V versus position. Do you think the field is caused by a sheet or a point charge? \((b)\) Graph the data in such a way that you can determine the magnitude of the charge and determine that value. \((c)\) Is it possible to determine where the charge is from this data? If so, give the position of the charge.

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