/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 37 (II) An aluminum rod conducts \(... [FREE SOLUTION] | 91Ó°ÊÓ

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(II) An aluminum rod conducts \(9.50 \mathrm{cal} / \mathrm{s}\) from a heat source maintained at \(225^{\circ} \mathrm{C}\) to a large body of water at \(22^{\circ} \mathrm{C}\). Calculate the rate at which entropy increases in this process.

Short Answer

Expert verified
The rate of entropy increase is \(0.0131 \text{ cal/(s K)}\).

Step by step solution

01

Understand the Heat Flow

The heat flow through the aluminum rod is given as \(9.50 \text{ cal/s}\). We need to know how this heat flow causes entropy to change in both the heat source and the large body of water.
02

Understand Entropy Change Formula

The change in entropy \(\Delta S\) is calculated by the formula \(\Delta S = \frac{Q}{T}\), where \(Q\) is the heat transferred and \(T\) is the temperature in Kelvin. Since we have a constant heat flow, the rate of entropy change for a body can be given by \(\frac{dS}{dt} = \frac{dQ}{dt} \times \frac{1}{T}\).
03

Convert Temperatures to Kelvin

Convert temperatures from Celsius to Kelvin. The source temperature is \(225^{\circ}C + 273.15 = 498.15 \text{ K}\). The sink (water) temperature is \(22^{\circ}C + 273.15 = 295.15 \text{ K}\).
04

Calculate Entropy Change for Heat Source

For the heat source: The rate of entropy change is \(- \frac{dQ}{dt} \times \frac{1}{T_\text{source}} = - \frac{9.50 \text{ cal/s}}{498.15 \text{ K}} = -0.0191 \text{ cal/(s K)}\).
05

Calculate Entropy Change for Water

For the water: The rate of entropy change is \(\frac{dQ}{dt} \times \frac{1}{T_\text{water}} = \frac{9.50 \text{ cal/s}}{295.15 \text{ K}} = 0.0322 \text{ cal/(s K)}\).
06

Calculate Net Entropy Change

The net rate of entropy change in the system is the sum of the entropy changes of the source and water: \(0.0322 \text{ cal/(s K)} - 0.0191 \text{ cal/(s K)} = 0.0131 \text{ cal/(s K)}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Thermal Conduction
Thermal conduction is an essential concept in physics, explaining how heat energy is transferred through materials. When we conduct heat through materials, it usually moves from a hotter area to a cooler one. This process continues until thermal equilibrium is achieved, meaning both areas reach the same temperature. When we talk about thermal conduction involving an aluminum rod, like in our exercise, heat moves from a heat source (which is warmer) to a heat sink, such as water (which is cooler). Imagine the heat as a stream of continuously moving energy. Some materials, like metals, are better conductors due to their atomic structure, which allows electrons to move more freely, facilitating heat transfer. For example, aluminum is a good conductor because it transfers heat effectively between its atoms and electrons.
Entropy Change
Entropy is a measure of disorder in a system. The second law of thermodynamics tells us that the total entropy of an isolated system tends to increase over time. This means that systems naturally progress towards a state of higher disorder or randomness. In the context of our exercise, we want to determine the rate of entropy change as heat flows from the heat source through the aluminum rod to the water. Entropy change, \( \Delta S \), can be calculated using the formula: \( \Delta S = \frac{Q}{T} \), where \( Q \) is the heat transferred, and \( T \) is the temperature in Kelvin.For each side in the process (the heat source and the water), we calculate their respective rates of entropy change separately, considering their temperatures and heat flow rates. Net entropy change is a summation of both parts, usually resulting in a positive value, reflecting the second law of thermodynamics. This means more disorder as heat disperses.
Thermodynamics
Thermodynamics is the study of heat, energy, and work—and how they interact within a system. There are four main laws of thermodynamics, but here we'll focus on the first and second laws, which are pivotal for our exercise. The first law, also known as the law of conservation of energy, states that energy cannot be created or destroyed. Instead, it changes from one form to another. In our scenario, the heat energy moves from the source to the water without any loss, though its effects (disorder) can be observed differently. The second law, as introduced through entropy, dictates that the entropy of isolated systems will increase over time, and processes occur in a direction that increases the entropy. So, while heat energy conserves, its destination yields a higher state of disorder. By computing the rates of entropy change for our source and water, we abide by this law and show the inherent increase in disorder due to thermal conduction.

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Most popular questions from this chapter

(III) Consider an isolated gas-like system consisting of a box that contains \(N=10\) distinguishable atoms, each moving at the same speed \(v\). The number of unique ways that these atoms can be arranged so that \(N_{\mathrm{L}}\) atoms are within the left-hand half of the box and \(N_{\mathrm{R}}\) atoms are within the right-hand half of the box is given by \(N ! / N_{\mathrm{L}} ! N_{\mathrm{R}} !\), where, for example, the factorial \(4 !=4 \cdot 3 \cdot 2 \cdot 1\) (the only exception is that \(0 !=1\) ). Define each unique arrangement of atoms within the box to be a microstate of this system. Now imagine the following two possible macrostates: state \(\mathrm{A}\) where all of the atoms are within the left-hand half of the box and none are within the right-hand half; and state \(\mathrm{B}\) where the distribution is uniform (that is, there is the same number in each half). See Fig. \(20-21 .\) (a) Assume the system is initially in state \(\mathrm{A}\) and, at a later time, is found to be in state B. Determine the system's change in entropy. Can this process occur naturally? (b) Assume the system is initially in state \(\mathrm{B}\) and, at a later time, is found to be in state A. Determine the system's change in entropy. Can this process occur naturally?

(II) A \(150-\mathrm{~g}\) insulated aluminum cup at \(15^{\circ} \mathrm{C}\) is filled with \(215 \mathrm{~g}\) of water at \(100^{\circ} \mathrm{C}\). Determine \((a)\) the final temperature of the mixture, and (b) the total change in entropy as a result of the mixing process (use \(\left.\Delta S=\int d Q / T\right) .\)

Two \(1100-\mathrm{kg}\) cars are traveling \(75 \mathrm{~km} / \mathrm{h}\) in opposite directions when they collide and are brought to rest. Estimate the change in entropy of the universe as a result of this collision. Assume \(T=15^{\circ} \mathrm{C}\).

(I) What is the maximum efficiency of a heat engine whose operating temperatures are \(550^{\circ} \mathrm{C}\) and \(365^{\circ} \mathrm{C} ?\)

Thermodynamic processes can be represented not only on \(P V\) and \(P T\) diagrams; another useful one is a \(T S\) (temperature-entropy) diagram. \((a)\) Draw a TS diagram for a Carnot cycle. \((b)\) What does the area within the curve represent?

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