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(II) A world-class sprinter can reach a top speed (of about \(11.5 \mathrm{~m} / \mathrm{s}\) ) in the first \(15.0 \mathrm{~m}\) of a race. What is the average acceleration of this sprinter and how long does it take her to reach that speed?

Short Answer

Expert verified
Average acceleration is \(4.41\, \text{m/s}^2\) and time is \(2.61\, \text{seconds}\).

Step by step solution

01

Identify Given and Required Quantities

We need to identify what is given in the problem and what we need to find. We are given that the sprinter reaches a top speed of \(v_f = 11.5\, \text{m/s}\) and covers a distance of \(s = 15.0\, \text{m}\) from rest \((v_0 = 0)\). We need to find the average acceleration \(a\) and the time \(t\) it takes to reach this speed.
02

Use Kinematic Equation for Acceleration

The kinematic equation relating final velocity, initial velocity, acceleration, and distance is:\[v_f^2 = v_0^2 + 2a s\]Substituting the known values:\[(11.5)^2 = 0 + 2a \times 15.0\]We need to solve for \(a\).
03

Solve for Acceleration

Simplify and solve the equation:\[132.25 = 30a\]Divide both sides by 30:\[a = \frac{132.25}{30} = 4.41 \text{ m/s}^2\]The average acceleration is \(4.41\, \text{m/s}^2\).
04

Use Another Kinematic Equation for Time

To find the time, use the kinematic equation:\[v_f = v_0 + at\]Substitute the known values:\[11.5 = 0 + 4.41t\]Solve for \(t\).
05

Solve for Time

Rearrange the equation to find \(t\):\[t = \frac{11.5}{4.41}\]Calculate:\[t \approx 2.61 \, \text{seconds}\]The time taken to reach the top speed is approximately \(2.61\, \text{seconds}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Average Acceleration
In physics, average acceleration is a key concept to understand when analyzing motion. It describes how quickly an object's velocity changes over a specified period of time. Average acceleration is calculated using the formula:\[a = \frac{\Delta v}{\Delta t}\]where \(a\) is the average acceleration, \(\Delta v\) is the change in velocity, and \(\Delta t\) is the time interval. For the sprinter, knowing that she started from rest
  • with an initial velocity \(v_0\) of 0 m/s,
  • reached a final velocity \(v_f\) of 11.5 m/s,
  • covered a distance \(s\) of 15 m.
We need to determine the rate of change of velocity, or average acceleration.Using the kinematic equation, we find that her average acceleration is \(4.41 \, \text{m/s}^2\). This means that every second, her speed increases by 4.41 m/s until she reaches her top speed.
Kinematic Equations
Kinematics is the branch of mechanics that deals with motion without considering the forces that cause it. Kinematic equations are crucial tools for solving questions about motion in physics. They allow us to calculate unknown variables such as time, distance, velocity, and acceleration using given data.In the context of the sprinter's motion, we utilize two kinematic equations:
  • The equation for acceleration: \[v_f^2 = v_0^2 + 2a s\]
  • The equation for time: \[v_f = v_0 + at\]
By substituting the known quantities into these equations, we can solve for the unknowns. This method allows us to find the average acceleration and the time it takes for the sprinter to reach her top speed, which are 4.41 m/s² and approximately 2.61 seconds, respectively.Using these equations provides a systematic way to understand motion, showcasing the elegance of physics through mathematical relationships.
Problem Solving in Physics
Problem solving is an integral part of learning physics, helping students apply theoretical concepts to real-world scenarios. Here's how you can approach solving kinematics problems effectively: 1. **Read the Problem Carefully**: Understand what is given and what needs to be determined. 2. **Identify the Known and Unknown Variables**: For instance, in our sprinter problem, we knew the initial and final velocities, and the distance, while we needed to find the acceleration and time. 3. **Select the Relevant Kinematic Equations**: Use equations that incorporate the known data and solve for the unknown variables. For the sprinter, we used two equations to find both acceleration and time. 4. **Solve Mathematically**: Carefully perform arithmetic operations and solve for the unknowns. 5. **Reflect on the Solution**: Assess if the result makes sense in the context of the problem. These steps will not only aid in solving kinematics problems but also enhance critical thinking and analytical skills, which are fundamental to success in physics and other scientific disciplines.

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Most popular questions from this chapter

(III) A toy rocket moving vertically upward passes by a 2.0-m-high window whose sill is \(8.0 \mathrm{~m}\) above the ground. The rocket takes \(0.15 \mathrm{~s}\) to travel the \(2.0 \mathrm{~m}\) height of the window. What was the launch speed of the rocket, and how high will it go? Assume the propellant is burned very quickly at blastoff.

(II) A rocket rises vertically, from rest, with an acceleration of \(3.2 \mathrm{~m} / \mathrm{s}^{2}\) until it runs out of fuel at an altitude of \(950 \mathrm{~m}\) After this point, its acceleration is that of gravity, downward. \((a)\) What is the velocity of the rocket when it runs out of fuel? \((b)\) How long does it take to reach this point? (c) What maximum altitude does the rocket reach? \((d)\) How much time (total) does it take to reach maximum altitude? (e) With what velocity does it strike the Earth? \((f)\) How long (total) is it in the air?

In putting, the force with which a golfer strikes a ball is planned so that the ball will stop within some small distance of the cup, say \(1.0 \mathrm{~m}\) long or short, in case the putt is missed. Accomplishing this from an uphill lie (that is, putting the ball downhill, see Fig. \(2-48\) ) is more difficult than from a downhill lie. To see why, assume that on a particular green the ball decelerates constantly at \(1.8 \mathrm{~m} / \mathrm{s}^{2}\) going downhill, and constantly at \(2.8 \mathrm{~m} / \mathrm{s}^{2}\) going uphill. Suppose we have an uphill lie \(7.0 \mathrm{~m}\) from the cup. Calculate the allowable range of initial velocities we may impart to the ball so that it stops in the range \(1.0 \mathrm{~m}\) short to \(1.0 \mathrm{~m}\) long of the cup. Do the same for a downhill lie \(7.0 \mathrm{~m}\) from the cup. What in your results suggests that the downhill putt is more difficult?

(1II) A bowling ball traveling with constant speed hits the pins at the end of a bowling lane 16.5 \(\mathrm{m}\) long. The bowler hears the sound of the ball hitting the pins 2.50 s after the ball is released from his hands. What is the speed of the ball, assuming the speed of sound is 340 \(\mathrm{m} / \mathrm{s} ?\)

(I) At highway speeds, a particular automobile is capable of an acceleration of about \(1.8 \mathrm{~m} / \mathrm{s}^{2}\). At this rate, how long does it take to accelerate from \(80 \mathrm{~km} / \mathrm{h}\) to \(110 \mathrm{~km} / \mathrm{h} ?\)

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