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(1) What must your car's average speed be in order to travel 235 \(\mathrm{km}\) in 3.25 \(\mathrm{h} ?\)

Short Answer

Expert verified
The car's average speed must be approximately 72.31 km/h.

Step by step solution

01

Identify the Given Values

To solve this problem, first identify and note the given values: - Total distance to be covered, which is 235 kilometers. - Total time taken for the travel, which is 3.25 hours.
02

Recall the Formula for Average Speed

Recall the formula for average speed:\[\text{Average Speed} = \frac{\text{Total Distance}}{\text{Total Time}}\]
03

Substitute Given Values into the Formula

Substitute the known values into the average speed formula:\[\text{Average Speed} = \frac{235 \, \text{km}}{3.25 \, \text{h}}\]
04

Calculate the Average Speed

Perform the division to calculate the average speed:\[\text{Average Speed} = \frac{235}{3.25} \approx 72.31 \, \text{km/h}\]
05

State the Final Answer

The average speed required for the car to travel 235 km in 3.25 hours is approximately 72.31 km/h.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Distance-Time Relationship
The relationship between distance and time is fundamental in understanding how speed works. When we talk about this relationship, we are looking at how much ground is covered over a specific period. This is often visualized as a line on a graph where one axis represents distance and the other represents time.

In this relationship, if distance increases while time remains constant, speed increases. Similarly, if the time taken to cover a certain distance decreases, speed increases. This is because speed is a ratio of distance over time. This forms the basis of our speed calculation, allowing us to understand scenarios where either distance or time needs to be adjusted to achieve a desired speed.

Understanding this relationship helps in planning trips or solving problems related to motion in physics and everyday scenarios.
Speed Calculation
Calculating speed is a straightforward process if you know the distance traveled and the time taken. The formula for calculating average speed is
\[\text{Average Speed} = \frac{\text{Total Distance}}{\text{Total Time}}\].

Let's break it down with an example. If a car travels 235 kilometers in 3.25 hours, you'll substitute these values into the formula like this:
\[\text{Average Speed} = \frac{235 \text{ km}}{3.25 \text{ h}}\]
. Following the division, you'll find that the car's average speed is approximately 72.31 kilometers per hour.

This simple calculation is essential for understanding how fast something is moving, allowing you to make predictions about arrival times and adjust travel plans accordingly. Knowing how to calculate speed can also be crucial for solving more complex physics problems.
Units Conversion
In any calculation involving speed, distance, and time, it’s crucial to ensure that the units are consistent. This means that the units for distance and time should match the units used in the speed formula. If not, you'll need to convert them.

For example, if distance is given in kilometers and time in hours, speed will naturally be calculated in kilometers per hour (km/h). However, sometimes problems might require different units, such as meters per second (m/s). In such cases, you'll need to convert:
- Kilometers to meters (1 km = 1000 m)
- Hours to seconds (1 hour = 3600 s)

Ensuring proper units conversion allows you to accurately interpret results and prevents errors in calculations, particularly in fields that require high precision like engineering or navigation.

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Most popular questions from this chapter

(II) The position of a racing car, which starts from rest at \(t=0\) and moves in a straight line, is given as a function of time in the following Table. Estimate \((a)\) its velocity and (b) its acceleration as a function of time. Display each in a Table and on a graph. $$ \begin{array}{lrrrrrrrr} \hline t(\mathrm{~s}) & 0 & 0.25 & 0.50 & 0.75 & 1.00 & 1.50 & 2.00 & 2.50 \\ x(\mathrm{~m}) & 0 & 0.11 & 0.46 & 1.06 & 1.94 & 4.62 & 8.55 & 13.79 \\ \hline t(\mathrm{~s}) & 3.00 & 3.50 & 4.00 & 4.50 & 5.00 & 5.50 & 6.00 & \\ x(\mathrm{~m}) & 20.36 & 28.31 & 37.65 & 48.37 & 60.30 & 73.26 & 87.16 & \\ \hline \end{array} $$

You are traveling at a constant speed \(v_{\mathrm{M}},\) and there is a car in front of you traveling with a speed \(v_{\mathrm{A}}\). You notice that \(v_{M}>v_{\mathrm{A}},\) so you start slowing down with a constant acceleration \(a\) when the distance between you and the other car is \(x\). What relationship between \(a\) and \(x\) determines whether or not you run into the car in front of you?

(II) You are driving home from school steadily at \(95 \mathrm{~km} / \mathrm{h}\) for \(130 \mathrm{~km}\). It then begins to rain and you slow to \(65 \mathrm{~km} / \mathrm{h}\). You arrive home after driving 3 hours and 20 minutes. (a) How far is your hometown from school? (b) What was your average speed?

(I) What must your car's average speed be in order to travel \(235 \mathrm{~km}\) in \(3.25 \mathrm{~h} ?\)

In the design of a rapid transit system, it is necessary to balance the average speed of a train against the distance between stops. The more stops there are, the slower the train's average speed. To get an idea of this problem, calculate the time it takes a train to make a \(9.0-\mathrm{km}\) trip in two situations: \((a)\) the stations at which the trains must stop are \(1.8 \mathrm{~km}\) apart (a total of 6 stations, including those at the ends); and (b) the stations are \(3.0 \mathrm{~km}\) apart (4 stations total). Assume that at each station the train accelerates at a rate of \(1.1 \mathrm{~m} / \mathrm{s}^{2}\) until it reaches \(95 \mathrm{~km} / \mathrm{h},\) then stays at this speed until its brakes are applied for arrival at the next station, at which time it decelerates at \(-2.0 \mathrm{~m} / \mathrm{s}^{2} .\) Assume it stops at each intermediate station for \(22 \mathrm{~s}\).

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