Chapter 18: Problem 48
(II) (a) The mean free path of \(\mathrm{CO}_{2}\), molecules at STP is measured to be about \(5.6 \times 10^{-8} \mathrm{~m} .\) Estimate the diameter of a \(\mathrm{CO}_{2}\) molecule. (b) Do the same for He gas for which \(\ell_{\mathrm{M}} \approx 25 \times 10^{-8}\) at STP.
Short Answer
Expert verified
The diameter of a COâ‚‚ molecule is approximately \(3.3 \times 10^{-10} \, \mathrm{m}\), and for He, it is \(2.2 \times 10^{-10} \, \mathrm{m}\).
Step by step solution
01
Understanding Mean Free Path
The mean free path \( \ell \) of a gas molecule is the average distance it travels before colliding with another molecule. It is given by the formula \( \ell = \frac{k_B T}{\sqrt{2}\, \pi d^2 P} \), where \( k_B \) is Boltzmann's constant, \( T \) is the temperature, \( d \) is the diameter of the molecule, and \( P \) is the pressure.
02
Apply Mean Free Path Formula for COâ‚‚
To estimate the diameter of a \( \mathrm{CO}_2 \) molecule, we rearrange the formula for mean free path as \( d = \sqrt{\frac{k_B T}{\sqrt{2} \pi \ell P}} \). Using values at Standard Temperature and Pressure (STP), \( T = 273.15 \, \mathrm{K} \), \( P = 101325 \, \mathrm{Pa} \), and \( \ell = 5.6 \times 10^{-8} \, \mathrm{m} \), and \( k_B = 1.38 \times 10^{-23} \, \mathrm{J/K} \), substitute these into the equation to solve for \( d \).
03
Calculation for COâ‚‚ Diameter
Substitute the known values into the equation: \[ d = \sqrt{\frac{1.38 \times 10^{-23} \times 273.15}{\sqrt{2} \times \pi \times 5.6 \times 10^{-8} \times 101325}} \]. Calculate \( d \) to find that the diameter of a \( \mathrm{CO}_2 \) molecule is approximately \( 3.3 \times 10^{-10} \, \mathrm{m} \).
04
Apply Mean Free Path Formula for He
Similarly, for helium \(( \mathrm{He} ) \) gas, using \( \ell \approx 25 \times 10^{-8} \, \mathrm{m} \), we use \( d = \sqrt{\frac{k_B T}{\sqrt{2} \pi \ell P}} \) to determine the diameter, using the same values for \( k_B \), \( T \), and \( P \).
05
Calculation for He Diameter
Substitute the known values into the formula: \[ d = \sqrt{\frac{1.38 \times 10^{-23} \times 273.15}{\sqrt{2} \times \pi \times 25 \times 10^{-8} \times 101325}} \]. Calculate \( d \) to find that the diameter of a \( \mathrm{He} \) atom is approximately \( 2.2 \times 10^{-10} \, \mathrm{m} \).
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Molecular Diameter Estimation
To estimate the diameter of a molecule, such as \( \mathrm{CO}_2 \) or \( \mathrm{He} \), we use the concept of the mean free path. This is the average distance a molecule travels before colliding with another molecule. For molecules in a gaseous state, the mean free path \( \ell \) can be expressed in terms of known constants and conditions:
- The temperature \( T \)
- The pressure \( P \)
- Boltzmann's constant \( k_B \)
Kinetic Theory of Gases
The kinetic theory of gases is a fundamental scientific theory that explains the behavior of gases based on the notion that gases consist of numerous tiny particles in constant motion. According to this theory:
- Gas particles are in constant, random motion.
- They frequently collide with each other and the walls of their container.
- The collisions are perfectly elastic, meaning there is no net loss of kinetic energy.
Boltzmann Constant
The Boltzmann constant \( k_B \) is a crucial element in the kinetic theory of gases and plays a critical role in the equation for mean free path. It provides a connection between the macroscopic and microscopic worlds by relating the average kinetic energy of particles in a gas with temperature:\[E_{k} = \frac{3}{2} k_B T\]Here:
- \( E_{k} \) is the average kinetic energy of gas molecules
- \( T \) is the absolute temperature in Kelvin