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(II) It is observed that 55.50 \(\mathrm{mL}\) of water at \(20^{\circ} \mathrm{C}\) completely fills a container to the brim. When the container and the water are heated to \(60^{\circ} \mathrm{C}, 0.35 \mathrm{g}\) of water is lost. (a) What is the coefficient of volume expansion of the container? \((b)\) What is the most likely material of the container? Density of water at \(60^{\circ} \mathrm{C}\) is 0.98324 \(\mathrm{g} / \mathrm{mL} .\)

Short Answer

Expert verified
The coefficient of volume expansion is 0.00022 掳C鈦宦 and the container is likely made of glass.

Step by step solution

01

Determine the initial mass of water

Calculate the initial mass of the water at \(20^{\circ} \mathrm{C}\) using the volume given. The density of water at \(20^{\circ} \mathrm{C}\) is approximately 0.9982 g/mL.\[ \text{Initial Mass} = 55.50 \, \mathrm{mL} \times 0.9982 \, \mathrm{g/mL} = 55.3891 \, \mathrm{g} \]
02

Calculate the final mass of water

After heating to \(60^{\circ} \mathrm{C}\), 0.35 g of water is lost. Hence, the final mass is:\[ \text{Final Mass} = 55.3891 \, \mathrm{g} - 0.35 \, \mathrm{g} = 55.0391 \, \mathrm{g} \]
03

Calculate the volume of water at 60掳C

Using the density of water at \(60^{\circ} \mathrm{C}\), which is 0.98324 g/mL, calculate the volume of the remaining water.\[ \text{Volume at 60掳C} = \frac{55.0391 \, \mathrm{g}}{0.98324 \, \mathrm{g/mL}} = 55.990 \, \mathrm{mL} \]
04

Calculate the volume expansion of the container

The initial volume of the container is 55.50 mL, and after heating, the volume of water indicates the expanded volume of the container. Hence, the volume expansion is:\[ \Delta V = 55.990 \, \mathrm{mL} - 55.50 \, \mathrm{mL} = 0.490 \, \mathrm{mL} \]
05

Find the coefficient of volume expansion

The coefficient of volume expansion \( \beta \) is given by:\[ \beta = \frac{\Delta V}{V_0 \Delta T} \]where \(V_0 = 55.50 \, \mathrm{mL}\), \(\Delta V = 0.490 \, \mathrm{mL}\), and \(\Delta T = 60 - 20 = 40^{\circ} \mathrm{C}\).\[ \beta = \frac{0.490}{55.50 \times 40} = 0.00022 \, \mathrm{^{\circ}C^{-1}} \]
06

Identify the most likely material of the container

The coefficient of volume expansion \(0.00022 \, \mathrm{^{\circ}C^{-1}}\) is within the typical range of glass, which commonly has a coefficient around \(0.00018 - 0.00020 \, \mathrm{^{\circ}C^{-1}}\). The nearest match is glass.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Coefficient of Volume Expansion
The coefficient of volume expansion is a measure of how much a material's volume changes in response to a temperature change. It's critical in understanding how materials behave when heated or cooled. To calculate this coefficient, we use the formula:\[ \beta = \frac{\Delta V}{V_0 \Delta T} \]where:
  • \( \Delta V \) is the change in volume
  • \( V_0 \) is the initial volume
  • \( \Delta T \) is the change in temperature
For example, in the given problem, the initial volume was 55.50 mL, and it expanded to 55.99 mL when the temperature increased by 40掳C. This results in a coefficient of volume expansion of 0.00022 掳C鈦宦, showing how much the container expanded due to heating.
Density of Water
Density is a fundamental concept related to how much mass is present in a certain volume of a substance. It changes with temperature because materials expand or contract, affecting their volume. Water鈥檚 density decreases as it heats up. At 20掳C, water has a density of 0.9982 g/mL, whereas at 60掳C, it's less dense at 0.98324 g/mL.

This detail is crucial when calculating the mass of water in various temperature conditions. Understanding water's density at different temperatures allows us to accurately determine volumes and masses of water, especially when it undergoes thermal changes.
Material Identification
Identifying a material based on its properties is a fascinating application of physics. Materials can be characterized by several properties, one of which is their coefficient of volume expansion. For instance, in our problem, we calculated a coefficient of approximately 0.00022 掳C鈦宦 for the container. This value matches closely with materials like glass, which have coefficients ranging from 0.00018 to 0.00020 掳C鈦宦.
The slight deviation is often acceptable in real life due to measurement precision and experimental errors. Such identification helps in choosing the right material for applications sensitive to temperature changes, ensuring the durability and stability of the material in various conditions.
Temperature Effects on Volume
Temperature significantly affects the volume of substances due to thermal expansion. As temperatures rise, most materials expand, increasing their volume. This is a general behavior due to increased molecular motion with heat, causing molecules to take up more space.

For liquids like water, heating results in noticeable volume changes; hence, knowing how temperature affects volume is crucial in applications like fluid dynamics and material science. Understanding these effects can help design systems that accommodate or exploit these changes, such as thermal expansion joints in bridges or the allowance for expansion in industrial pipes.

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Most popular questions from this chapter

(II) A tire is filled with air at \(15^{\circ} \mathrm{C}\) to a gauge pressure of \(250 \mathrm{kPa} .\) If the tire reaches a temperature of \(38^{\circ} \mathrm{C},\) what fraction of the original air must be removed if the original pressure of \(250 \mathrm{kPa}\) is to be maintained?

(II) If a fluid is contained in a long narrow vessel so it can expand in essentially one direction only, show that the effective coefficient of linear expansion \(\alpha\) is approximately equal to the coefficient of volume expansion \(\beta\)

(II) Is a gas mostly empty space? Check by assuming that the spatial extent of common gas molecules is about \(\ell_{0}=0.3 \mathrm{nm}\) so one gas molecule occupies an approximate volume equal to \(\ell_{0}^{3}\). Assume STP.

(II) A typical scuba tank, when fully charged, contains \(12 \mathrm{~L}\) of air at 204 atm. Assume an "empty" tank contains air at 34 atm and is connected to an air compressor at sea level. The air compressor intakes air from the atmosphere, compresses it to high pressure, and then inputs this highpressure air into the scuba tank. If the (average) flow rate of air from the atmosphere into the intake port of the air compressor is \(290 \mathrm{~L} / \mathrm{min}\), how long will it take to fully charge the scuba tank? Assume the tank remains at the same temperature as the surrounding air during the filling process.

(II) A storage tank contains \(21.6 \mathrm{~kg}\) of nitrogen \(\left(\mathrm{N}_{2}\right)\) at an absolute pressure of \(3.85 \mathrm{~atm} .\) What will the pressure be if the nitrogen is replaced by an equal mass of \(\mathrm{CO}_{2}\) at the same temperature?

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