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(II) A source emits sound of wavelengths 2.64 \(\mathrm{m}\) and 2.72 \(\mathrm{m}\) in air. (a) How many beats per second will be heard? (Assume \(T=20^{\circ} \mathrm{C}\) ) \((b)\) How far apart in space are the regions of maximum intensity?

Short Answer

Expert verified
3.61 beats per second; regions are 1.34 m apart.

Step by step solution

01

Calculate the Speed of Sound at 20°C

We use the formula for the speed of sound in air, which is given by \( v = 331.4 + 0.6T \), where \( T \) is the temperature in Celsius. Here, \( T = 20^{\circ} \). Substitute to find \( v \):\[ v = 331.4 + 0.6(20) = 343.4 \text{ m/s} \].
02

Calculate Frequencies of the Two Sounds

To find the frequency \( f \), we use the formula \( f = \frac{v}{\lambda} \), where \( \lambda \) is the wavelength. For the first sound with \( \lambda_1 = 2.64 \text{ m} \):\[ f_1 = \frac{343.4}{2.64} \approx 130.08 \text{ Hz} \].For the second sound with \( \lambda_2 = 2.72 \text{ m} \):\[ f_2 = \frac{343.4}{2.72} \approx 126.47 \text{ Hz} \].
03

Calculate Beat Frequency

The number of beats per second is given by the difference in frequencies of the two sounds. Calculate the beat frequency \[ f_{\text{beats}} = |f_1 - f_2| = |130.08 - 126.47| \approx 3.61 \text{ beats per second} \].
04

Calculate Distance Between Regions of Maximum Intensity

In a standing wave, nodes (or regions of maximum intensity) occur at half-wavelength intervals. To find the distance between successive regions of maximum intensity, use the average wavelength. Calculate the average wavelength: \[ \lambda_{\text{avg}} = \frac{2.64 + 2.72}{2} = 2.68 \text{ m} \].The distance between nodes (or antinodes) is half the average wavelength \[ \frac{\lambda_{\text{avg}}}{2} = \frac{2.68}{2} = 1.34 \text{ m} \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sound Waves
Sound waves are disturbances that travel through a medium such as air, water, or solids. These waves are created by vibrating objects such as vocal cords, speakers, or musical instruments. When an object vibrates, it compresses and rarifies the surrounding medium, propagating the sound wave. You can imagine sound waves as ripples on the water surface, spreading outward from the source.
A sound wave requires a medium to travel. It cannot move through a vacuum since there are no particles to vibrate. In any medium, the molecules do not travel with the sound; instead, they pass the vibration from one molecule to the next, much like a line of dominoes falling.
  • Sound is a mechanical wave.
  • It is longitudinal, meaning particle displacement is parallel to wave propagation direction.
  • It requires a medium, commonly air.
Sound waves can be characterized by their wavelengths, frequencies, and amplitudes. The human ear detects changes in frequency as differing pitches, with higher frequencies producing higher pitches. Wavelength is directly related to frequency, as they both determine a sound's pitch and quality.
Speed of Sound
The speed of sound varies depending on the medium through which it travels. In air, the speed of sound is affected by temperature, humidity, and atmospheric pressure. At 20°C, for example, the speed of sound in air is calculated using the formula: \( v = 331.4 + 0.6T \), where \( T \) is the temperature in Celsius. This factor explains why sounds travel faster on warm days, as molecules move more quickly, aiding wave transmission.
The speed of sound also differs in other mediums. Generally, sound travels faster in solids than in liquids, and faster in liquids than in gases. The density and elasticity of the medium affect how quickly sound waves are propagated.
  • Speed of sound is higher in densely packed materials.
  • Elasticity affects sound speed; more elastic materials allow quicker wave transmission.
  • Speed in air at 20°C is approximately 343.4 m/s.
In terms of practical applications, the speed of sound helps calibrate equipment, assists in sonar navigation, and determines the timing for echoes and other phenomena.
Standing Waves
Standing waves occur when two waves with the same frequency and amplitude traverse in opposite directions in a medium, leading to a pattern of stationary nodes and antinodes. These waves are often observed in musical instruments and can explain why certain instruments produce particular notes.
Nodes are specific points where the wave has zero amplitude, whereas antinodes are the regions of maximum amplitude. The distance between consecutive nodes or antinodes is half of the wavelength. This property can be used to calculate how far apart regions of maximum intensity (antinodes) are situated in standing wave conditions.
  • Standing waves result from wave interference.
  • They are characterized by nodes (minimum intensity) and antinodes (maximum intensity).
  • In a medium, these formations occur at half-wavelength intervals.
Understanding standing waves plays a crucial role in fields like acoustics, where designing concert halls or tuning instruments requires precise knowledge of how waves interact in a confined space.

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Most popular questions from this chapter

(1I) A jet plane emits \(5.0 \times 10^{5} \mathrm{J}\) of sound energy per second. \((a)\) What is the sound level 25 \(\mathrm{m}\) away? Air absorbs sound at a rate of about 7.0 \(\mathrm{dB} / \mathrm{km}\) ; calculate what the sound level will be \((b) 1.00 \mathrm{km}\) and \((c) 7.50 \mathrm{km}\) away from this jet plane, taking into account air absorption.

The predominant frequency of a certain fire truck's siren is \(1350 \mathrm{~Hz}\) when at rest. What frequency do you detect if you move with a speed of \(30.0 \mathrm{~m} / \mathrm{s}(a)\) toward the fire truck, and \((b)\) away from it?

In a quartz oscillator, used as a stable clock in electronic devices, a transverse (shear) standing sound wave is excited across the thickness \(d\) of a quartz disk and its frequency \(f\) is detected electronically. The parallel faces of the disk are unsupported and so behave as "free ends" when the sound wave reflects from them (see Fig. \(16-36\) ). If the oscillator is designed to operate with the first harmonic, determine the required disk thickness if \(f=12.0 \mathrm{MHz}\). The density and shear modulus of quartz are \(\rho=2650 \mathrm{~kg} / \mathrm{m}^{3}\) and \(G=2.95 \times 10^{10} \mathrm{~N} / \mathrm{m}^{2}\)

A wave on the surface of the ocean with wavelength \(44 \mathrm{~m}\) is traveling east at a speed of \(18 \mathrm{~m} / \mathrm{s}\) relative to the ocean floor. If, on this stretch of ocean surface, a powerboat is moving at \(15 \mathrm{~m} / \mathrm{s}\) (relative to the ocean floor), how often does the boat encounter a wave crest, if the boat is traveling (a) west, and (b) east?

If the velocity of blood flow in the aorta is normally about \(0.32 \mathrm{~m} / \mathrm{s},\) what beat frequency would you expect if 3.80-MHz ultrasound waves were directed along the flow and reflected from the red blood cells? Assume that the waves travel with a speed of \(1.54 \times 10^{3} \mathrm{~m} / \mathrm{s}\)

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