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What is the sound level of a sound whose intensity is \(2.0 \times 10^{-6} \mathrm{~W} / \mathrm{m}^{2} ?\)

Short Answer

Expert verified
The sound level is approximately 63.01 dB.

Step by step solution

01

Understanding the Sound Level Formula

The sound level (measured in decibels, dB) can be determined using the formula: \[ L = 10 imes ext{log}_{10} \left( \frac{I}{I_0} \right) \] where \(L\) is the sound level in dB, \(I\) is the intensity of the sound, and \(I_0\) is the reference intensity level, which is \(1.0 \times 10^{-12} \mathrm{~W/m^2}\).
02

Plugging in the Values

Insert the given intensity \( I = 2.0 \times 10^{-6} \mathrm{~W/m^2} \) and the reference intensity \( I_0 = 1.0 \times 10^{-12} \mathrm{~W/m^2} \) into the formula: \[ L = 10 \times \log_{10} \left( \frac{2.0 \times 10^{-6}}{1.0 \times 10^{-12}} \right) \]
03

Calculating the Ratio

Calculate the ratio of \( \frac{I}{I_0} \):\[ \frac{2.0 \times 10^{-6}}{1.0 \times 10^{-12}} = 2.0 \times 10^{6} \]
04

Applying the Logarithm

Find the logarithm base 10 of the ratio calculated:\[ \log_{10} (2.0 \times 10^{6}) = \log_{10} (2) + \log_{10}(10^6) = 0.301 + 6 = 6.301 \]
05

Finding the Sound Level

Multiply the result of the logarithm by 10 to find the sound level:\[ L = 10 \times 6.301 = 63.01 \text{ dB} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Decibel Calculation
The concept of decibel calculation is essential to understand how we measure sound levels. Decibels (dB) are a unit used to express the intensity of a sound. The decibel scale is logarithmic, which means each increase of 10 dB represents a tenfold increase in sound intensity. This approach makes it easier to represent the vast range of sound intensities our ears can perceive.
To calculate the sound intensity level in decibels, we use the following formula:
  • \[ L = 10 \times \log_{10} \left( \frac{I}{I_0} \right) \]
where:
  • \(L\) is the sound level in decibels,
  • \(I\) is the intensity of the sound, and
  • \(I_0\) is the reference intensity level.
By applying this formula, we can quantify how loud or soft a sound is compared to a standard reference level.
Logarithmic Scale
A logarithmic scale is a non-linear scale used for many scientific measurements, which helps manage large ranges of values in a more comprehensible way. Unlike linear scales, a logarithmic scale increases by a multiplicative factor rather than adding a constant amount.
This is particularly useful for measuring sound intensity because the human ear perceives sound intensities logarithmically. In decibel calculations, the logarithmic scale helps convert the ratio of intensity \(\frac{I}{I_0}\) into a manageable number that represents the sound level in decibels.
For example, in our exercise, the intensity ratio \(2.0 \times 10^{6}\) converts to \(6.301\) on a logarithmic scale, showing a large range of actual intensities in a simplified manner.
Therefore, logarithmic scales are invaluable for engineering, biology, and acoustics, where tiny or vast differences in magnitude need to be expressed effectively.
Reference Intensity Level
The reference intensity level \(I_0\) in acoustics is crucial because it serves as the baseline against which all sound intensities are measured. This standard is universally recognized as \(1.0 \times 10^{-12} \mathrm{~W/m^2} \), which is approximately the threshold of human hearing.
By using this reference, the decibel scale can accurately reflect how much more intense a sound is than the quietest sound detectable by the average human ear. This makes it easier to communicate and compare the loudness of sounds in everyday life.
In the calculation, the ratio \(\frac{I}{I_0}\) signifies how much a sound intensity \(I\) differs from this reference level. For instance, an intensity \(I\) greater than \(I_0\) will result in a positive decibel reading, indicating the sound is perceptibly louder than the threshold of hearing. Conversely, a negative decibel value implies a softer sound in relation to \(I_0\), likely inaudible to most people.
This consistent reference point ensures all sound level measurements are meaningful and comparable across different contexts and applications.

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Most popular questions from this chapter

A Doppler flow meter is used to measure the speed of blood flow. Transmitting and receiving elements are placed on the skin, as shown in Fig. 16 - \(42 .\) Typical sound-wave frequencies of about \(5.0 \mathrm{MHz}\) are used, which have a reasonable chance of being reflected from red blood cells. By measuring the frequency of the reflected waves, which are Doppler-shifted because the red blood cells are moving, the speed of the blood flow can be deduced. "Normal" blood flow speed is about \(0.1 \mathrm{~m} / \mathrm{s}\). Suppose that an artery is partly constricted, so that the speed of the blood flow is increased, and the flow meter measures a Doppler shift of \(780 \mathrm{~Hz}\). What is the speed of blood flow in the constricted region? The effective angle between the sound waves (both transmitted and reflected) and the direction of blood flow is \(45^{\circ} .\) Assume the velocity of sound in tissue is \(1540 \mathrm{~m} / \mathrm{s}\)

The pressure variation in a sound wave is given by $$ \Delta P=0.0035 \sin (0.38 \pi x-1350 \pi t) $$ where \(\Delta P\) is in pascals, \(x\) in meters, and \(t\) in seconds. Determine \((a)\) the wavelength, \((b)\) the frequency, \((c)\) the speed, and \((d)\) the displacement amplitude of the wave. Assume the density of the medium to be \(\rho=2.3 \times 10^{3} \mathrm{~kg} / \mathrm{m}^{3}\).

A science museum has a display called a sewer pipe symphony. It consists of many plastic pipes of various lengths, which are open on both ends. (a) If the pipes have lengths of \(3.0 \mathrm{m}, 2.5 \mathrm{m}\) , \(2.0 \mathrm{m}, 1.5 \mathrm{m}\) and \(1.0 \mathrm{m},\) what frequencies will be heard by a visitor's ear placed near the ends of the pipes? (b) Why does this display work better on a noisy day than on a quiet day?

(II) A bat flies toward a wall at a speed of 7.0 \(\mathrm{m} / \mathrm{s}\) . As it flies, the bat emits an ultrasonic sound wave with frequency 30.0 \(\mathrm{kHz}\) , What frequency does the bat hear in the reflected wave?

A bat flies toward a moth at speed 7.5 \(\mathrm{m} / \mathrm{s}\) while the moth is flying toward the bat at speed 5.0 \(\mathrm{m} / \mathrm{s}\) . The bat emits a sound wave of 51.35 \(\mathrm{kHz}\) . What is the frequency of the wave detected by the bat after that wave reflects off the moth?

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