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(II) Show by direct substitution that the following functions satisfy the wave equation: (a) \(D(x, t)=A \ln (x+v t)\) (b) \(D(x, t)=(x-v t)^{4}\)

Short Answer

Expert verified
Functions (a) and (b) satisfy the wave equation by direct substitution of their second derivatives.

Step by step solution

01

Understand the Wave Equation

The wave equation in one dimension is given by \[ \frac{\partial^2 D}{\partial t^2} = v^2 \frac{\partial^2 D}{\partial x^2} \] where \(D(x,t)\) is the displacement as a function of \(x\) and \(t\), and \(v\) is the wave speed.
02

Differentiate Function (a)

Given \(D(x, t) = A \ln (x + vt)\), we find the partial derivatives: \[ \frac{\partial D}{\partial t} = \frac{Av}{x + vt} \] \[ \frac{\partial^2 D}{\partial t^2} = -\frac{Av^2}{(x + vt)^2} \] \[ \frac{\partial D}{\partial x} = \frac{A}{x + vt} \] \[ \frac{\partial^2 D}{\partial x^2} = -\frac{A}{(x + vt)^2} \]
03

Verify Wave Equation for (a)

Substitute the second derivatives into the wave equation: \[ -\frac{Av^2}{(x + vt)^2} = v^2 \left(-\frac{A}{(x + vt)^2}\right) \] Since both sides are equal, function (a) satisfies the wave equation.
04

Differentiate Function (b)

Given \(D(x, t) = (x - vt)^4\), we find the partial derivatives: \[ \frac{\partial D}{\partial t} = -4v(x - vt)^3 \] \[ \frac{\partial^2 D}{\partial t^2} = 12v^2(x - vt)^2 \] \[ \frac{\partial D}{\partial x} = 4(x - vt)^3 \] \[ \frac{\partial^2 D}{\partial x^2} = 12(x - vt)^2 \]
05

Verify Wave Equation for (b)

Substitute the second derivatives into the wave equation: \[ 12v^2(x - vt)^2 = v^2 \cdot 12(x - vt)^2 \] Again, both sides are equal, thus function (b) also satisfies the wave equation.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Partial Differentiation
Partial differentiation is a fundamental concept when dealing with multivariable functions. It involves finding the derivative of a function with respect to one variable, while keeping other variables constant. In the context of the wave equation, partial derivatives help us understand how the wave displacement, denoted as \(D(x, t)\), changes with respect to time \(t\) and space \(x\).

When you differentiate a function like \(D(x, t) = A \ln (x + vt)\) partially with respect to \(t\), you treat \(x\) as constant and differentiate with respect to \(t\) only. This gives us \(\frac{\partial D}{\partial t}\), which tells us how the function changes as time progresses. Partial differentiation is essential for verifying whether a function satisfies the wave equation, which is a common task in physics and mathematics.

  • The partial derivative \(\frac{\partial D}{\partial t}\) measures the rate of change of displacement \(D\) with respect to time.
  • Similarly, \(\frac{\partial D}{\partial x}\) reflects the rate of change with respect to position.
  • These derivatives provide insights into the behavior and propagation of waves in different media.
Wave Function
A wave function is a mathematical representation that describes how waves move in a medium. In this context, \(D(x, t)\) is the wave function that depends on both position \(x\) and time \(t\). Wave functions are pivotal in describing various phenomena such as sound waves, light waves, and water waves. By analyzing wave functions, we can predict how waves interact with their surroundings and determine their speed and direction.

In our example, \(D(x, t) = A \ln (x + vt)\) and \(D(x, t) = (x - vt)^4\) are different forms of wave functions. Each provides specific information about the wave's characteristics.

  • The constant \(A\) is an amplitude that determines the wave's maximum displacement.
  • The variable \(v\) signifies the wave's velocity, dictating how fast the wave propagates through the medium.
Understanding these features helps in solving the wave equation, which models how waves spread over time and space.
Second Derivatives
Second derivatives are crucial in wave equations because they provide information on how the rate of change itself changes over time or space. In the wave equation \( \frac{\partial^2 D}{\partial t^2} = v^2 \frac{\partial^2 D}{\partial x^2} \), both sides involve second derivatives, representing the concave or convex nature of the wave function.

  • \(\frac{\partial^2 D}{\partial t^2}\) measures the acceleration of the wave function with respect to time.
  • \(\frac{\partial^2 D}{\partial x^2}\) measures the curvature with respect to space.
For a function to satisfy the wave equation, the rate of change of the time curvature must equal the spatial curvature scaled by the square of the wave's speed.

When checking if a function like \(D(x, t) = A \ln (x + vt)\) satisfies the wave equation, we calculate its second derivatives with respect to \(t\) and \(x\). If these derivatives fulfill the equation's balance, the function properly models a wave. Understanding how these derivatives influence the wave helps physicists and engineers design better wave-related technology, such as acoustic devices and antennas.

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Most popular questions from this chapter

(II) Show that the wave forms of Eqs. 13 and 15 satisfy the wave equation, Eq. \(16 .\) $$D(x, t)=A \sin \left[\frac{2 \pi}{\lambda}(x+v t)\right] (13 a)$$ $$=A \sin \left(\frac{2 \pi x}{\lambda}+\frac{2 \pi t}{T}\right) (13 b)$$ $$=A \sin (k x+\omega t) (13 b) $$ $$D(x, t)=D(x+v t) (15)$$ $$\frac{\partial^{2} D}{\partial x^{2}}=\frac{1}{v^{2}} \frac{\partial^{2} D}{\partial t^{2}} (16)$$

(II) A transverse wave on a cord is given by \(D(x, t)=\) \(0.12 \sin (3.0 x-15.0 t),\) where \(D\) and \(x\) are in \(\mathrm{m}\) and \(t\) is in s. At \(t=0.20 \mathrm{s},\) what are the displacement and velocity of the point on the cord where \(x=0.60 \mathrm{m} ?\)

(II) \(\mathrm{A} 65\) -cm guitar string is fixed at both ends. In the frequency range between 1.0 and 2.0 \(\mathrm{kHz}\) , the string is found to resonate only at frequencies \(1.2,1.5,\) and 1.8 \(\mathrm{kHz}\) . What is the speed of traveling waves on this string?

(II) The displacement of a standing wave on a string is given by \(D=2.4 \sin (0.60 x) \cos (42 t),\) where \(x\) and \(D\) are in centimeters and \(t\) is in seconds. (a) What is the distance (cm) between nodes? (b) Give the amplitude, frequency, and speed of each of the component waves. (c) Find the speed of a particle of the string at \(x=3.20 \mathrm{~cm}\) when \(t=2.5 \mathrm{~s}\).

(I) In an earthquake, it is noted that a footbridge oscillated up and down in a one-loop (fundamental standing wave) pattern once every \(1.5 \mathrm{~s}\). What other possible resonant periods of motion are there for this bridge? What frequencies do they correspond to?

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