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In some diatomic molecules, the force each atom exerts on the other can be approximated by \(F=-C / r^{2}+D / r^{3}\) where \(r\) is the atomic separation and \(C\) and \(D\) are positive constants. ( \(a\) ) Graph \(F\) vs. \(r\) from \(r=0.8 D / C\) to \(r=4 D / C\). (b) Show that equilibrium occurs at \(r=r_{0}=D / C .\) (c) Let \(\Delta r=r-r_{0}\) be a small displacement from equilibrium, where \(\Delta r \ll r_{0} .\) Show that for such small displacements, the motion is approximately simple harmonic, and \((d)\) determine the force constant. ( \(e\) ) What is the period of such motion? [Hint: Assume one atom is kept at rest.]

Short Answer

Expert verified
Equilibrium occurs at \( r_0 = \frac{D}{C} \), force constant is \( k = \frac{2C^3}{D^2} \), period is \( T = 2\pi \sqrt{\frac{mD^2}{2C^3}} \).

Step by step solution

01

Understanding the Function

The force function given is \( F = -\frac{C}{r^2} + \frac{D}{r^3} \). This indicates the relationship between force, \( F \), and atomic separation, \( r \). The terms are inversely related to powers of \( r \), suggesting complex interactions.
02

Graphing the Function

To graph \( F \) versus \( r \) from \( r = 0.8\frac{D}{C} \) to \( r = 4\frac{D}{C} \), calculate \( F \) at multiple points within the interval and plot these points to visualize the force as a function of separation distance \( r \).
03

Finding Equilibrium

To find equilibrium, set the force \( F = 0 \). Thus, solve \(-\frac{C}{r^2} + \frac{D}{r^3} = 0 \), which simplifies to \( C = \frac{D}{r} \). Solving for \( r \), we find the equilibrium position \( r_0 = \frac{D}{C} \).
04

Examining Small Displacements

For small displacements \( \Delta r = r - r_0 \), expand the force function around \( r_0 \) using a Taylor series. The linear term in \( \Delta r \) provides an approximation: \( F \approx -k \Delta r \), where \( k \) is the force constant, indicating simple harmonic motion.
05

Finding the Force Constant

By expanding the force function and equating the linear term, we find \( F = -\frac{2C}{r_0^3} \Delta r \). Substituting \( r_0 = \frac{D}{C} \), the force constant \( k = \frac{2C^3}{D^2} \).
06

Calculating the Period

For simple harmonic motion, the period \( T \) is given by \( T = 2\pi \sqrt{\frac{m}{k}} \), where \( m \) is the mass of an oscillating atom. Substituting our expression for \( k \), the period becomes \( T = 2\pi \sqrt{\frac{mD^2}{2C^3}} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Equilibrium Position
In the context of diatomic molecules, the equilibrium position is where the force between two atoms is balanced, meaning the net force is zero. Think of this as a perfect distance between the atoms where neither is being pushed or pulled by the other.

Mathematically speaking, for the given force function, \[ F = -\frac{C}{r^2} + \frac{D}{r^3}, \] the equilibrium occurs when the force equals zero. This is achieved when \[ -\frac{C}{r^2} + \frac{D}{r^3} = 0. \]
By solving this equation, we find that the equilibrium position occurs at \[ r_0 = \frac{D}{C}. \]
This formula indicates the specific distance at which these forces balance out. It is crucial because small deviations around this point dictate how the molecules behave under small disturbances, leading us to our next topic of discussion.
Simple Harmonic Motion
Simple harmonic motion (SHM) is a type of periodic motion where the restoring force is directly proportional to the displacement and acts in the direction opposite to that of displacement.

In the context of diatomic molecules, if we slightly displace an atom from the equilibrium position, the system tends to bring the atom back to equilibrium, making it oscillate back and forth.
  • The motion is described by:\[ F \approx -k \Delta r, \] where \( \Delta r \) is the small displacement from equilibrium.

In SHM, the force function can be expanded using a Taylor series about the equilibrium position. The first few terms of the series help approximate the force and show that the behavior near equilibrium follows the principles of SHM. It is approximated by a linear function of displacement, which results in a sinusoidal motion. This is a foundational behavior in physics as it underpins the concept of vibrational spectroscopy in chemistry.
Force Constant
The force constant, denoted \( k \), is a measure of the stiffness of the bond; essentially, how strong the restoring force is in response to a displacement from the equilibrium position.

For small oscillations near equilibrium in diatomic molecules, the force constant relates directly to the properties of the potential energy surface around that equilibrium.
  • The formula for the force constant in this system is:\[ k = \frac{2C^3}{D^2}. \]
  • It quantifies how resistant the molecule is to being stretched or compressed.

The force constant plays a crucial role in determining the period of the oscillation. A larger \( k \) means a stiffer bond, leading to a faster oscillation and a shorter period. In practical terms, knowing \( k \) helps chemists and physicists predict the behavior of molecules when they undergo vibrations, which is important for understanding molecular stability and dynamics.

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Most popular questions from this chapter

(II) A pinball machine uses a spring launcher that is compressed 6.0 \(\mathrm{cm}\) to launch a ball up a \(15^{\circ}\) ramp. Assume that the pinball is a solid uniform sphere of radius \(r=1.0 \mathrm{cm}\) and mass \(m=25 \mathrm{g}\) . If it is rolling without slipping at a speed of 3.0 \(\mathrm{m} / \mathrm{s}\) when it leaves the launcher, what is the spring constant of the spring launcher?

Your grandfather clock's pendulum has a length of \(0.9930 \mathrm{~m} .\) If the clock loses \(26 \mathrm{~s}\) per day, how should you adjust the length of the pendulum?

If one oscillation has 5.0 times the energy of a second one of equal frequency and mass, what is the ratio of their amplitudes?

A child of mass \(m\) sits on top of a rectangular slab of mass \(M=35 \mathrm{kg},\) which in turn rests on the frictionless horizontal floor at a pizza shop. The slab is attached to a horizontal spring with spring constant \(k=430 \mathrm{N} / \mathrm{m}\) (the other end is attached to an immovable wall, Fig. 45. The coefficient of static friction between the child and the top of the slab is \(\mu=0.40 .\) The shop owner's intention is that, when displaced from the equilibrium position and released, the slab and child (with no slippage between the two) execute SHM with amplitude \(A=0.50 \mathrm{m} .\) Should there be a weight restriction for this ride? If so, what is it?

A vertical spring with spring stiffness constant \(305 \mathrm{~N} / \mathrm{m}\) oscillates with an amplitude of \(28.0 \mathrm{~cm}\) when \(0.260 \mathrm{~kg}\) hangs from it. The mass passes through the equilibrium point \((y=0)\) with positive velocity at \(t=0 .\) (a) What equation describes this motion as a function of time? (b) At what times will the spring be longest and shortest?

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