/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 8 (I) Estimate the pressure needed... [FREE SOLUTION] | 91Ó°ÊÓ

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(I) Estimate the pressure needed to raise a column of water to the same height as a \(35-\mathrm{m}\) -tall oak tree.

Short Answer

Expert verified
The pressure needed is approximately 343,000 Pa.

Step by step solution

01

Identify the Known Variables

The oak tree is 35 meters tall. Hence, the height of the water column is also 35 meters. We need to find the pressure required to raise the water to this height.
02

Recall the Formula for Pressure in a Fluid Column

The pressure needed to raise a column of water can be calculated using the formula: \[ P = \rho g h \] where: \(P\) = pressure, \(\rho\) = density of the fluid (water), \(g\) = acceleration due to gravity, and \(h\) = height of the water column. The typical density of water, \(\rho\), is \(1000\, \mathrm{kg/m^3}\). The typical value for \(g\) is \(9.8\, \mathrm{m/s^2}\). \(h\) is given as \(35\, \mathrm{m}\).
03

Substitute the Known Values into the Formula

Substitute \(\rho = 1000 \, \mathrm{kg/m^3}\), \(g = 9.8 \, \mathrm{m/s^2}\), and \(h = 35 \, \mathrm{m}\) into the formula: \[ P = 1000 \, \mathrm{kg/m^3} \times 9.8 \, \mathrm{m/s^2} \times 35 \, \mathrm{m} \]
04

Calculate the Pressure

Multiply the values to find the pressure: \[ P = 1000 \times 9.8 \times 35 = 343,000 \, \mathrm{Pa} \]
05

Conclusion About the Result

The pressure required to raise a column of water to a height of 35 meters is approximately 343,000 pascals (Pa).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Fluid Mechanics
Fluid mechanics is a fascinating field of physics that explores the behavior of fluids, both liquids and gases, in motion and at rest. It helps us understand a wide array of natural phenomena and plays a critical role in various engineering applications.
For instance, when examining fluids in various states of movement, this branch of science looks at concepts like buoyancy, viscosity, and flow rates. Understanding fluid mechanics allows us to explain why ships float, how water flows through pipes, and much more.
In the context of our exercise, fluid mechanics helps to determine the pressure required to push a column of water to a certain height. This concept is crucial in designing systems that involve fluid transport, such as irrigation systems or plumbing.
By studying fluid mechanics, we gain insights into how fluids behave under different forces and conditions, making it an essential field of study for engineers and scientists.
Pressure Calculation
Pressure calculation is essential in understanding how forces distributed over an area can affect fluid behavior. In fluid mechanics, pressure is the force exerted by a fluid per unit area, measured in pascals (Pa).
The calculation process involves several critical steps:
  • Identify the variables: Before calculating pressure, you must know key variables such as fluid density, gravity, and the height of the fluid column.
  • Apply the formula: The formula for calculating pressure in a fluid column is \[ P = \rho g h \] where \( P \) represents pressure, \( \rho \) is the density of the fluid, \( g \) is the acceleration due to gravity, and \( h \) is the height.
  • Substitute values: Substitute real numbers into the formula to find the pressure. For example, using 1000 \( \mathrm{kg/m^3} \) for water's density, 9.8 \( \mathrm{m/s^2} \) for gravity, and 35 \( \mathrm{m} \) for height yields 343,000 \( \mathrm{Pa} \).
This pressure calculation helps in understanding the fluid's ability to exert force over an area, relevant in many engineering designs and natural phenomena.
Density of Water
The density of water plays a crucial role in pressure calculation and numerous fluid mechanics applications. It essentially dictates how much mass is contained in a given volume of water.
Water's density is typically 1000 \( \mathrm{kg/m^3} \) at standard temperature and pressure. This value is fundamental when calculating the pressure in a fluid column since it directly influences the pressure exerted by the fluid.
Understanding water density is vital in diverse applications:
  • In underwater and atmospheric pressure calculations, as water density impacts how pressure changes with depth.
  • In engineering fields such as hydrology and civil engineering, where precise calculations of water force are needed for designing dams, canals, and pipelines.
  • In determining buoyancy, where the density of water plays a role in whether objects will sink or float.
Recognizing that water density is a constant in specific conditions allows scientists and engineers to make reliable predictions and efficient designs across various fluid-related scenarios.

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Most popular questions from this chapter

A hydraulic lift is used to jack a \(920-\mathrm{kg}\) car \(42 \mathrm{~cm}\) off the floor. The diameter of the output piston is \(18 \mathrm{~cm},\) and the input force is \(350 \mathrm{~N}\). \((a)\) What is the area of the input piston? \((b)\) What is the work done in lifting the car \(42 \mathrm{~cm} ?(c)\) If the input piston moves \(13 \mathrm{~cm}\) in each stroke, how high does the car move up for each stroke? \((d)\) How many strokes are required to jack the car up \(42 \mathrm{~cm} ?\) ( \(e\) ) Show that energy is conserved.

(II) An open-tube mercury manometer is used to measure the pressure in an oxygen tank. When the atmospheric pressure is \(1040 \mathrm{mbar}\), what is the absolute pressure (in \(\mathrm{Pa}\) ) in the tank if the height of the mercury in the open tube is (a) \(21.0 \mathrm{~cm}\) higher, \((b) 5.2 \mathrm{~cm}\) lower, than the mercury in the tube connected to the tank?

(II) A scuba diver and her gear displace a volume of \(65.0 \mathrm{~L}\) and have a total mass of \(68.0 \mathrm{~kg} .(a)\) What is the buoyant force on the diver in seawater? (b) Will the diver sink or float?

(II) \((a)\) Show that the buoyant force \(F_{B}\) on a partially submerged object such as a ship acts at the center of gravity of the fluid before it is displaced. This point is called the center of buoyancy. (b) To ensure that a ship is in stable equilibrium, would it be better if its center of buoyancy was above, below, or at the same point above, below, or at the same point as, its center of gravity? Explain.

A bucket of water is accelerated upward at \(1.8 g .\) What is the buoyant force on a \(3.0-\mathrm{kg}\) granite rock \((\mathrm{SG}=2.7)\) submerged in the water? Will the rock float? Why or why not?

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