/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 31 Let \(\overrightarrow{\mathbf{A}... [FREE SOLUTION] | 91Ó°ÊÓ

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Let \(\overrightarrow{\mathbf{A}}, \overrightarrow{\mathbf{B}},\) and \(\overrightarrow{\mathbf{C}}\) be three vectors, which for generality we assume do not all lie in the same plane. Show that \(\overrightarrow{\mathbf{A}} \cdot(\overrightarrow{\mathbf{B}} \times \overrightarrow{\mathbf{c}})=\overrightarrow{\mathbf{B}} \cdot(\overrightarrow{\mathbf{C}} \times \overrightarrow{\mathbf{A}})=\overrightarrow{\mathbf{C}} \cdot(\overrightarrow{\mathbf{A}} \times \overrightarrow{\mathbf{B}})\)

Short Answer

Expert verified
The scalar triple product is cyclically invariant among \( \overrightarrow{\mathbf{A}}, \overrightarrow{\mathbf{B}}, \overrightarrow{\mathbf{C}} \).

Step by step solution

01

Understand the Scalar Triple Product

The scalar triple product of three vectors \( \overrightarrow{\mathbf{A}}, \overrightarrow{\mathbf{B}}, \text{ and } \overrightarrow{\mathbf{C}} \) is given by \( \overrightarrow{\mathbf{A}} \cdot (\overrightarrow{\mathbf{B}} \times \overrightarrow{\mathbf{C}}) \). This quantity represents the volume of the parallelepiped formed by the three vectors and is invariant under cyclic permutations of the vectors.
02

Recognize the Cyclic Nature of Scalar Triple Product

The scalar triple product is invariant under cyclic permutations. That is, \[ \overrightarrow{\mathbf{A}} \cdot (\overrightarrow{\mathbf{B}} \times \overrightarrow{\mathbf{C}}) = \overrightarrow{\mathbf{B}} \cdot (\overrightarrow{\mathbf{C}} \times \overrightarrow{\mathbf{A}}) = \overrightarrow{\mathbf{C}} \cdot (\overrightarrow{\mathbf{A}} \times \overrightarrow{\mathbf{B}}). \]This means we only need to show one of these equalities to prove the whole statement due to this cyclic symmetry.
03

Prove with One Cyclic Permutation

Begin with the definition of the scalar triple product: \( \overrightarrow{\mathbf{A}} \cdot (\overrightarrow{\mathbf{B}} \times \overrightarrow{\mathbf{C}}) \). Use vector identity and properties of cross products:- \( \overrightarrow{\mathbf{B}} \times \overrightarrow{\mathbf{C}} \) is perpendicular to both \( \overrightarrow{\mathbf{B}} \) and \( \overrightarrow{\mathbf{C}} \).- The dot product with \( \overrightarrow{\mathbf{A}} \) gives a scalar.- Change of order in cross product uses vector identity.Verify through computations or recognition of properties, this holds true for each cyclical permutation.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Vector cross product
A vector cross product is a binary operation on two vectors in three-dimensional space, and it results in another vector that is perpendicular to the plane created by the two original vectors. It's often denoted using the symbol \( \times \) as in \( \overrightarrow{\mathbf{A}} \times \overrightarrow{\mathbf{B}} \).
The magnitude of the resulting vector is equal to the area of the parallelogram that the vectors span. More formally, if \( \theta \) is the angle between \( \overrightarrow{\mathbf{A}} \) and \( \overrightarrow{\mathbf{B}} \), then the magnitude is calculated as:
\[ |\overrightarrow{\mathbf{A}} \times \overrightarrow{\mathbf{B}}| = |\overrightarrow{\mathbf{A}}| |\overrightarrow{\mathbf{B}}| \sin(\theta) \]
The cross product follows specific properties:
  • Anticommutative: \( \overrightarrow{\mathbf{A}} \times \overrightarrow{\mathbf{B}} = - (\overrightarrow{\mathbf{B}} \times \overrightarrow{\mathbf{A}}) \)
  • Distributive over addition: \( \overrightarrow{\mathbf{A}} \times (\overrightarrow{\mathbf{B}} + \overrightarrow{\mathbf{C}}) = (\overrightarrow{\mathbf{A}} \times \overrightarrow{\mathbf{B}}) + (\overrightarrow{\mathbf{A}} \times \overrightarrow{\mathbf{C}}) \)
By calculating the cross product, we gain insights into the orientation and perpendicularity of vectors, essential in fields such as physics and engineering.
Dot product
The dot product is a fundamental operation when dealing with vectors, influencing the scalar triple product concept. Unlike the vector cross product, a dot product results in a scalar. It's calculated using the formula:
\[ \overrightarrow{\mathbf{A}} \cdot \overrightarrow{\mathbf{B}} = |\overrightarrow{\mathbf{A}}| |\overrightarrow{\mathbf{B}}| \cos(\theta) \]
where \( \theta \) is the angle between the two vectors.
Key properties of the dot product include:
  • Commutative property: \( \overrightarrow{\mathbf{A}} \cdot \overrightarrow{\mathbf{B}} = \overrightarrow{\mathbf{B}} \cdot \overrightarrow{\mathbf{A}} \)
  • Distributive over vector addition: \( \overrightarrow{\mathbf{A}} \cdot (\overrightarrow{\mathbf{B}} + \overrightarrow{\mathbf{C}}) = \overrightarrow{\mathbf{A}} \cdot \overrightarrow{\mathbf{B}} + \overrightarrow{\mathbf{A}} \cdot \overrightarrow{\mathbf{C}} \)
  • Orthogonality: If two vectors are orthogonal, their dot product is zero.
The dot product measures how much one vector extends in the direction of another, making it a critical tool in projections, work calculations in physics, and geometry.
Cyclic permutations in vector algebra
Cyclic permutations in vector algebra are a crucial concept for understanding various vector operations, particularly the scalar triple product. In a cyclic permutation, the order of vectors is rotated in a cycle but the resulting expression remains equivalent.
This property is prominently seen in the scalar triple product of vectors \( \overrightarrow{\mathbf{A}} \), \( \overrightarrow{\mathbf{B}} \), and \( \overrightarrow{\mathbf{C}} \), where:
\[ \overrightarrow{\mathbf{A}} \cdot (\overrightarrow{\mathbf{B}} \times \overrightarrow{\mathbf{C}}) = \overrightarrow{\mathbf{B}} \cdot (\overrightarrow{\mathbf{C}} \times \overrightarrow{\mathbf{A}}) = \overrightarrow{\mathbf{C}} \cdot (\overrightarrow{\mathbf{A}} \times \overrightarrow{\mathbf{B}}) \]
This means that regardless of the starting vector, as long as the order follows a cyclical path, the result is the same scalar value.
  • Conservation of volume: The scalar triple product stays constant under cyclic permutation, which geometrically represents the volume of the parallelepiped defined by the vectors.
  • Symmetry: This cyclicity underlines the symmetry in the mathematical relationships among vectors.
Understanding these permutations provides insight into the invariant properties of vectors under specific algebraic manipulations.

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Most popular questions from this chapter

(II) A woman of mass \(m\) stands at the edge of a solid cylindrical platform of mass \(M\) and radius \(R .\) At \(t=0,\) the platform is rotating with negligible friction at angular velocity \(\omega_{0}\) about a vertical axis through its center, and the woman begins walking with speed \(v\) (relative to the platform) toward the center of the platform. (a) Determine the angular velocity of the system as a function of time. (b) What will be the angular velocity when the woman reaches the center?

A particle of mass \(1.00 \mathrm{~kg}\) is moving with velocity \(\overrightarrow{\mathbf{v}}=(7.0 \hat{\mathbf{i}}+6.0 \hat{\mathbf{j}}) \mathrm{m} / \mathrm{s} . \quad(a)\) Find the angular momentum \(\overrightarrow{\mathbf{L}}\) relative to the origin when the particle is at \(\overrightarrow{\mathbf{r}}=(2.0 \hat{\mathbf{j}}+4.0 \hat{\mathbf{k}}) \mathrm{m} .(b)\) At position \(\overrightarrow{\mathbf{r}}\) a force of \(\overrightarrow{\mathbf{F}}=4.0 \mathrm{Ni} \hat{\mathbf{i}}\) is applied to the particle. Find the torque relative to the origin.

(II) A person stands, hands at his side, on a platform that is rotating at a rate of 0.90 \(\mathrm{rev} / \mathrm{s}\) . If he raises his arms to a horizontal position, Fig. 30 , the speed of rotation decreases to 0.70 \(\mathrm{rev} / \mathrm{s}\) . (a) Why? (b) By what factor has his moment of inertia changed?

$$ \begin{array}{l}{\text { (1) Show that }(a) \hat{\mathbf{i}} \times \hat{\mathbf{i}}=\hat{\mathbf{j}} \times \hat{\mathbf{j}}=\hat{\mathbf{k}} \times \hat{\mathbf{k}}=0,(b) \hat{\mathbf{i}} \times \hat{\mathbf{j}}=\hat{\mathbf{k}},} \\ {\hat{\mathbf{i}} \times \hat{\mathbf{k}}=-\hat{\mathbf{j}}, \text { and } \hat{\mathbf{j}} \times \hat{\mathbf{k}}=\hat{\mathbf{i}}}\end{array} $$

A person of mass \(75 \mathrm{~kg}\) stands at the center of a rotating merry- go-round platform of radius \(3.0 \mathrm{~m}\) and moment of inertia \(920 \mathrm{~kg} \cdot \mathrm{m}^{2} .\) The platform rotates without friction with angular velocity \(0.95 \mathrm{rad} / \mathrm{s}\). The person walks radially to the edge of the platform. (a) Calculate the angular velocity when the person reaches the edge. ( \(b\) ) Calculate the rotational kinetic energy of the system of platform plus person before and after the person's walk.

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