Chapter 11: Problem 23
(II) What is the angle \(\theta\) between two vectors \(\vec{\mathbf{A}}\) and \(\vec{\mathbf{B}}\) , if \(|\vec{\mathbf{A}} \times \vec{\mathbf{B}}|=\vec{\mathbf{A}} \cdot \vec{\mathbf{B}} ?\)
Short Answer
Expert verified
\(\theta = 45^\circ\) or \(\frac{\pi}{4}\) radians.
Step by step solution
01
Understanding the Problem
We are given two vectors, \(\vec{\mathbf{A}}\) and \(\vec{\mathbf{B}}\), and need to find the angle \(\theta\) between them given \(|\vec{\mathbf{A}} \times \vec{\mathbf{B}}| = \vec{\mathbf{A}} \cdot \vec{\mathbf{B}}\). This condition involves both the cross product and the dot product of the vectors.
02
Using the Cross Product Formula
The magnitude of the cross product \(|\vec{\mathbf{A}} \times \vec{\mathbf{B}}|\) is given by the formula \(|\vec{\mathbf{A}}||\vec{\mathbf{B}}|\sin\theta\).
03
Using the Dot Product Formula
The dot product \(\vec{\mathbf{A}} \cdot \vec{\mathbf{B}}\) is given by the formula \(|\vec{\mathbf{A}}||\vec{\mathbf{B}}|\cos\theta\).
04
Equating and Simplifying the Problem
Since \(|\vec{\mathbf{A}} \times \vec{\mathbf{B}}| = \vec{\mathbf{A}} \cdot \vec{\mathbf{B}}\), we substitute the formulas: \(|\vec{\mathbf{A}}||\vec{\mathbf{B}}|\sin\theta = |\vec{\mathbf{A}}||\vec{\mathbf{B}}|\cos\theta\).
05
Canceling and Solving for \(\theta\)
Cancel \(|\vec{\mathbf{A}}||\vec{\mathbf{B}}|\) from both sides (assuming neither is zero), resulting in \(\sin\theta = \cos\theta\). Dividing both sides by \(\cos\theta\) gives \(\tan\theta = 1\).
06
Finding the Angle
The equation \(\tan\theta = 1\) implies that \(\theta\) is \(45^\circ\) or \(\frac{\pi}{4}\) radians, since tangent has a period of \(\pi\) and \(\tan 45^\circ = 1\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Dot Product
The dot product, also known as the scalar product, is a way to multiply two vectors to result in a scalar or a single number. It's one of the fundamentals of vector mathematics.When calculating the dot product of two vectors, say \( \vec{\mathbf{A}} \) and \( \vec{\mathbf{B}} \), you follow the formula:\[ \vec{\mathbf{A}} \cdot \vec{\mathbf{B}} = |\vec{\mathbf{A}}||\vec{\mathbf{B}}|\cos\theta \]Here, \(|\vec{\mathbf{A}}|\) and \(|\vec{\mathbf{B}}|\) are the magnitudes (or lengths) of vectors \(\vec{\mathbf{A}}\) and \(\vec{\mathbf{B}}\), while \(\theta\) is the angle between them.
The resulting dot product value can tell us several things:
The resulting dot product value can tell us several things:
- If the dot product is positive, the angle between the vectors is acute (less than 90°).
- If it's zero, the vectors are perpendicular.
- If negative, the angle is obtuse (greater than 90°).
Cross Product
The cross product, also known as the vector product, differs from the dot product as it results in a vector rather than a scalar. It's calculated using two vectors and results in a third vector that is perpendicular to the plane of the first two vectors.The formula for the magnitude of the cross product of vectors \( \vec{\mathbf{A}} \) and \( \vec{\mathbf{B}} \) is:\[ |\vec{\mathbf{A}} \times \vec{\mathbf{B}}| = |\vec{\mathbf{A}}||\vec{\mathbf{B}}|\sin\theta \]Here, \(|\vec{\mathbf{A}}|\) and \(|\vec{\mathbf{B}}|\) are still the magnitudes of the vectors, while \(\theta\) is the angle between them.
Some key points about the cross product are:
Some key points about the cross product are:
- The resulting vector's direction is determined by the right-hand rule.
- The magnitude of the cross product gives the area of the parallelogram formed by the two vectors.
- If the vectors are parallel, the cross product is zero because \(\sin 0 = 0\).
Angle Between Vectors
Finding the angle between two vectors involves using both the dot product and the cross product.If we have two vectors \( \vec{\mathbf{A}} \) and \( \vec{\mathbf{B}} \), we can find the angle \( \theta \) between them through the equations for their dot and cross products:
Solving this gives \( \tan\theta = 1 \), which means \( \theta = 45^\circ \) or \( \frac{\pi}{4} \) radians.
This relationship and calculation showcase how vector operations can help us understand geometric and spatial relationships between different directions in space.
- Dot Product: \( \vec{\mathbf{A}} \cdot \vec{\mathbf{B}} = |\vec{\mathbf{A}}||\vec{\mathbf{B}}|\cos\theta \)
- Cross Product: \( |\vec{\mathbf{A}} \times \vec{\mathbf{B}}| = |\vec{\mathbf{A}}||\vec{\mathbf{B}}|\sin\theta \)
Solving this gives \( \tan\theta = 1 \), which means \( \theta = 45^\circ \) or \( \frac{\pi}{4} \) radians.
This relationship and calculation showcase how vector operations can help us understand geometric and spatial relationships between different directions in space.