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(II) Determine the moment of inertia of a 19 -kg door that is 2.5 \(\mathrm{m}\) high and 1.0 \(\mathrm{m}\) wide and is hinged along one side. Ignore the thickness of the door.

Short Answer

Expert verified
The moment of inertia is approximately 39.58 kg·m².

Step by step solution

01

Identify the Door as a Rectangular Object

The door is a rectangular plane, so we can model it as a rectangle rotating about an axis along one of its sides. Its mass ( \(M\)) is 19 kg, height ( \(h\)) is 2.5 \(m\), and width ( \(b\)) is 1.0 \(m\).
02

Use the Moment of Inertia Formula for a Rectangle

The formula for the moment of inertia of a rectangle about an axis through one of its sides is given by \(I = \frac{1}{3} Mh^2\), where \(M\) is the mass and \(h\) is the height from the axis of rotation.
03

Substitute Known Values into the Formula

Substitute the values into the formula: \(I = \frac{1}{3} \times 19\, \text{kg} \times (2.5\, \text{m})^2\).
04

Calculate the Moment of Inertia

Compute: \(I = \frac{1}{3} \times 19 \times 6.25 = \frac{1}{3} \times 118.75 = 39.58\). Thus, the moment of inertia is approximately \(39.58\, \text{kg} \cdot \text{m}^2\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rotational Dynamics
Rotational dynamics is a branch of physics that deals with the motion of objects that rotate around a point or an axis. It extends the concepts of linear motion to rotational systems.
The dynamics involve important quantities like Torque, Angular Momentum, and Moment of Inertia. While torque acts like a rotational force influencing the motion, angular momentum is analogous to linear momentum in linear dynamics.
However, the core focal point for understanding problems related to rotation, like our exercise, is the moment of inertia. This quantity expresses how the mass distribution of an object affects its rotation. A higher moment of inertia means that the object is more resistant to changes in its rotational speed. It's crucial in rotational dynamics because it helps predict how objects will respond to torques.
Physics Problem Solving
Solving physics problems effectively, such as calculating moments of inertia, often requires a systematic approach. This ensures that you understand each step thoroughly and arrive at the correct solution.
Here’s a simplified approach:
  • Identify the physical system or object: Understand what the problem tells you. Read the exercise carefully.
  • Determine what is being asked: In our case, calculate the moment of inertia.
  • List all known values and variables: Mass (19 kg), height (2.5 m), width (1.0 m).
  • Choose the correct formula: Use the standard formulas related to your concept, as we did for calculating the moment of inertia of a rectangle.
  • Plug in the values, solve, and check your work: Ensure that calculations were done using the correct arithmetic procedures.
This approach not only helps in understanding but also increases problem-solving efficiency.
Rectangular Plates
Rectangular plates, often encountered in physics problems, like doors or boards, are flat, two-dimensional objects with a clearly defined width and height. Understanding these objects is key in exercises involving the moment of inertia.
When considering a rectangular plate for rotational dynamics, we assume it to be a plane surface with uniform thickness and material distribution, focusing only on length and width. Thickness is generally ignored unless specified.
Important factors include:
  • Mass: Related to the density and material of the plate
  • Dimensions: Specifically the height and width for inertia calculations.
These parameters help in applying the known inertia formulas. As we saw, the formula \[I = \frac{1}{3} Mh^2\] provides a means to calculate how the mass distribution across a rectangular shape affects its inertia.
Rotational Axis
The rotational axis is a fundamental aspect when examining rotational dynamics. It is the line around which an object or a system rotates. The choice of axis can significantly alter calculations for inertia.
In our exercise, the door rotates around an axis along one of its vertical sides. Knowing this helps in selecting the correct moment of inertia formula.
Clarifying the axis aids in:
  • Determining the rotational resistance (moment of inertia).
  • Understanding the object's motion behavior when torques are applied.
  • Relating the importance of axis placement, as moving an axis can change inertia markedly.
By understanding the axis position, you gain deeper insights into the physics involved in rotation, facilitating the learning and application of rotational principles.

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Most popular questions from this chapter

(III) A string passing over a pulley has a 3.80 -kg mass hanging from one end and a 3.15 -kg mass hanging from the other end. The pulley is a uniform solid cylinder of radius 4.0 \(\mathrm{cm}\) and mass 0.80 \(\mathrm{kg}\) (a) If the bearings of the pulley were frictionless, what would be the acceleration of the two masses? (b) In fact, it is found that if the heavier mass is given a downward speed of \(0.20 \mathrm{m} / \mathrm{s},\) it comes to rest in 6.2 \(\mathrm{s}\) . What is the average frictional torque acting on the pulley?

(I) An automobile engine develops a torque of 255 \(\mathrm{m} \cdot \mathrm{N}\) at 3750 \(\mathrm{rpm} .\) What is the horsepower of the engine?

Bicycle gears: \((a)\) How is the angular velocity \(\omega_{\mathrm{R}}\) of the rear wheel of a bicycle related to the angular velocity \(\omega_{\mathrm{F}}\) of the front sprocket and pedals? Let \(N_{\mathrm{F}}\) and \(N_{\mathrm{R}}\) be the number of teeth on the front and rear sprockets, respectively, Fig. \(10-64\) The teeth are spaced the same on both sprockets and the rear sprocket is firmly attached to the rear wheel. \((b)\) Evaluate the ratio \(\omega_{\mathrm{R}} / \omega_{\mathrm{F}}\) when the front and rear sprockets (1) have 52 and 13 teeth, respectively, and (c) when they have 42 Rear sprocket \(\quad\) and 28 teeth.

(III) A 2.30 -m-long pole is balanced vertically on its tip. It starts to fall and its lower end does not slip. What will be the speed of the upper end of the pole just before it hits the ground? [Hint: Use conservation of energy.]

A centrifuge rotor has a moment of inertia of \(4.25 \times 10^{-2} \mathrm{~kg} \cdot \mathrm{m}^{2} .\) How much energy is required to bring it from rest to 9750 rpm?

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