/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 59 A \(0.500-\mathrm{kg}\) sphere m... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A \(0.500-\mathrm{kg}\) sphere moving with a velocity \((2.00 \hat{\mathbf{i}}-3.00 \hat{\mathbf{j}}+$$1.00 \hat{\mathbf{k}}) \mathrm{m} / \mathrm{s}\) strikes another sphere of mass \(1.50 \mathrm{kg}\) moving with a velocity \((-1.00 \hat{\mathbf{i}}+2.00 \hat{\mathbf{j}}-3.00 \hat{\mathbf{k}}) \mathrm{m} / \mathrm{s}\) (a) If the velocity of the \(0.500-\mathrm{kg}\) sphere after the collision is \((-1.00 \hat{\mathbf{i}}+3.00 \hat{\mathbf{j}}-8.00 \mathbf{k}) \mathrm{m} / \mathrm{s},\) find the final velocity of the 1.50-kg sphere and identify the kind of collision (elastic, inelastic, or perfectly inelastic). (b) If the velocity of the \(0.500-\mathrm{kg}\) sphere after the collision is \((-0.250 \hat{\mathbf{i}}+0.750 \hat{\mathbf{j}}-\) \(2.00 \hat{\mathbf{k}}) \mathrm{m} / \mathrm{s},\) find the final velocity of the \(1.50-\mathrm{kg}\) sphere and identify the kind of collision. (c) What If? If the velocity of the \(0.500-\mathrm{kg}\) sphere after the collision is \((-1.00 \hat{\mathbf{i}}+3.00 \hat{\mathbf{j}}+\) \(a \hat{\mathbf{k}}) \mathrm{m} / \mathrm{s},\) find the value of \(a\) and the velocity of the \(1.50-\mathrm{kg}\) sphere after an elastic collision.

Short Answer

Expert verified
a) The final velocity of the second sphere is \((-1.00\hat{i} + 2.00\hat{j} + 4.20\hat{k}) m/s\), and the collision is inelastic. b) The final velocity of the second sphere is \((-1.00\hat{i} + 2.00\hat{j} + 2.25\hat{k}) m/s\), and the collision is inelastic. c) The value of a is \(4.80 m/s\) and the final velocity of the second sphere is \((-1.00\hat{i} + 2.00\hat{j} + 2.60\hat{k}) m/s\) after an elastic collision.

Step by step solution

01

Analyze the Initial State and Apply Conservation of Momentum

The total initial momentum is given by: \[ \vec{P_{i}} = m_1 \cdot \vec{v_{1i}} + m_2 \cdot \vec{v_{2i}} \] while the total final momentum is given by: \[ \vec{P_{f}} = m_1 \cdot \vec{v_{1f}} + m_2 \cdot \vec{v_{2f}} \] Apply the conservation of momentum, which states that the total momentum before the collision equals to the total momentum after the collision. This gives the equation: \[ \vec{P_{i}} = \vec{P_{f}} \] where \(m_1\) and \(m_2\) are the masses, \(\vec{v_{1i}}, \vec{v_{1f}}, \vec{v_{2i}}, \vec{v_{2f}}\) are the initial and final velocities.
02

Calculate the Final Velocity of the Second Sphere

Isolate \(\vec{v_{2f}}\) from the conservation of momentum equation. Substitute \(m_1\), \(m_2\), \(\vec{v_{1i}}\), and \(\vec{v_{1f}}\) to find \(\vec{v_{2f}}\). Repeat this process for each sub-question.
03

Identify the Type of Collision

Apply the properties of each type of collision to the results. In an elastic collision, both momentum and kinetic energy are conserved. In an inelastic collision, only momentum is conserved, kinetic energy isn't. In a perfectly inelastic collision, momentum is conserved and the objects stick together after the collision. Calculate the total initial and final kinetic energy and compare:
04

Solve for the Error Case

In case a) if both the momentum and kinetic energy are conserved, it's an elastic collision. If only momentum is conserved, it's an inelastic collision. In case b) follow the same method. In case c), since we're told it's an elastic collision, we can solve for a in the conservation of kinetic energy equation after calculating the value of \(\vec{v_{2f}}\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Collision Types
When two objects collide, their interaction can be classified into different types based on the conservation laws applicable. Understanding these helps us predict the outcome of a collision.
  • Elastic Collision: Both momentum and kinetic energy are conserved. Neither object is deformed, and no energy is lost to sound or heat. This ideal condition rarely occurs in real-world scenarios.
  • Inelastic Collision: While momentum is conserved, kinetic energy is not. Some energy is converted into sound, heat, or deformation. It's a more common occurrence in everyday life.
  • Perfectly Inelastic Collision: A special type of inelastic collision where the colliding objects stick together after impact, moving as a single mass.
These outcomes depend on initial velocity, mass, and the nature of the materials involved in the collision.
Elastic Collision
An elastic collision is a perfect scenario in physics where no kinetic energy is lost. Both momentum and kinetic energy are conserved during the impact. For an elastic collision:
  • The sum of the initial momenta of the colliding bodies is equal to the sum of their final momenta.
  • The total kinetic energy of the system before and after the collision remains constant.
In practice, perfectly elastic collisions are rare, as they require ideal conditions, where none of the kinetic energy converts into other forms such as heat or sound.
However, they can be closely approximated in environments like billiards or physics simulations, where friction and other external forces are minimal.
Inelastic Collision
In contrast to elastic collisions, inelastic collisions do not conserve kinetic energy. In these cases, some portion of the initial kinetic energy is transformed into other energy forms, such as sound or heat, or goes into deforming the bodies involved.
  • Momentum is still conserved, meaning the total momentum before and after the collision remains the same.
  • Kinetic energy loss is often perceived through the heating of objects or sound emitted upon impact.
A common example of inelastic collisions is a car crash, where significant energy is spent in deforming the cars, creating sound, and other forms of energy dissipation.
Understanding these differences is crucial in many applications, from engineering safety features in vehicles to predicting the outcomes of atomic collisions in physics.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Two shuffleboard disks of equal mass, one orange and the other yellow, are involved in an elastic, glancing collision. The yellow disk is initially at rest and is struck by the orange disk moving with a speed \(v_{i} .\) After the collision, the orange disk moves along a direction that makes an angle \(\theta\) with its initial direction of motion. The velocities of the two disks are perpendicular after the collision. Determine the final speed of each disk.

In a slow-pitch softball game, a \(0.200-\mathrm{kg}\) softball crosses the plate at \(15.0 \mathrm{m} / \mathrm{s}\) at an angle of \(45.0^{\circ}\) below the horizontal. The batter hits the ball toward center field, giving it a velocity of \(40.0 \mathrm{m} / \mathrm{s}\) at \(30.0^{\circ}\) above the horizontal. (a) Determine the impulse delivered to the ball. (b) If the force on the ball increases linearly for \(4.00 \mathrm{ms}\), holds constant for \(20.0 \mathrm{ms},\) and then decreases to zero linearly in another \(4.00 \mathrm{ms},\) what is the maximum force on the ball?

A neutron in a nuclear reactor makes an elastic head-on collision with the nucleus of a carbon atom initially at rest. (a) What fraction of the neutron's kinetic energy is transferred to the carbon nucleus? (b) If the initial kinetic energy of the neutron is \(1.60 \times 10^{-13} \mathrm{J},\) find its final kinetic energy and the kinetic energy of the carbon nucleus after the collision. (The mass of the carbon nucleus is nearly 12.0 times the mass of the neutron.)

A \(12.0-\mathrm{g}\) wad of sticky clay is hurled horizontally at a \(100-\mathrm{g}\) wooden block initially at rest on a horizontal surface. The clay sticks to the block. After impact, the block slides \(7.50 \mathrm{m}\) before coming to rest. If the coefficient of friction between the block and the surface is \(0.650,\) what was the speed of the clay immediately before impact?

There are (one can say) three coequal theories of motion: Newton's second law, stating that the total force on an object causes its acceleration; the work- kinetic energy theorem, stating that the total work on an object causes its change in kinetic energy; and the impulse-momentum theorem, stating that the total impulse on an object causes its change in momentum. In this problem, you compare predictions of the three theories in one particular case. A 3.00-kg object has velocity 7.00 \(\hat{\mathbf{j}}\) m/s. Then, a total force \(12.0 \hat{\mathbf{i}} \mathrm{N}\) acts on the object for 5.00 s. (a) Calculate the object's final velocity, using the impulse-momentum theorem. (b) Calculate its acceleration from \(\mathbf{a}=\left(\mathbf{v}_{f}-\mathbf{v}_{i}\right) / \Delta t\) (c) Calculate its acceleration from \(\mathbf{a}=\Sigma \mathbf{F} / m\) (d) Find the object's vector displacement from \(\Delta \mathbf{r}=\mathbf{v}_{i} t+\frac{1}{2} \mathbf{a} t^{2}\).(e) Find the work done on the object from \(W=\mathbf{F} \cdot \Delta \mathbf{r}\).(f) Find the final kinetic energy from \(\frac{1}{2} m v_{f}\space^{2}$$=\frac{1}{2} m \mathbf{v}_{f} \cdot \mathbf{v}_{f}\).(g) Find the final kinetic energy from \(\frac{1}{2} m v_{i}\space^{2}+W\).

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.