/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 46 Consider a system of two particl... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Consider a system of two particles in the \(x y\) plane: \(m_{1}=\) \(2.00 \mathrm{kg}\) is at the location \(\mathbf{r}_{1}=(1.00 \hat{\mathbf{i}}+2.00 \hat{\mathbf{j}}) \mathrm{m}\) and has a velocity of \((3.00 \hat{\mathbf{i}}+0.500 \hat{\mathbf{j}}) \mathrm{m} / \mathrm{s} ; m_{2}=3.00 \mathrm{kg}\) is at \(\mathbf{r}_{2}=\) \((-4.00 \hat{\mathbf{i}}-3.00 \hat{\mathbf{j}}) \mathrm{m}\) and has velocity \((3.00 \hat{\mathbf{i}}-2.00 \hat{\mathbf{j}}) \mathrm{m} / \mathrm{s}\) (a) Plot these particles on a grid or graph paper. Draw their position vectors and show their velocities. (b) Find the position of the center of mass of the system and mark it on the grid. (c) Determine the velocity of the center of mass and also show it on the diagram. (d) What is the total linear momentum of the system?

Short Answer

Expert verified
The position of the center of mass, its velocity, and the total linear momentum are calculated from the given parameters. The respective vectors are also plotted on a graph.

Step by step solution

01

Plot the particles

Use a graph to plot particles \(m_1\) and \(m_2\) at their respective locations, represented by the position vectors \(\mathbf{r}_1\) and \(\mathbf{r}_2\). Also, represent their respective velocities as vectors originating from each particle's position.
02

Compute the Center of Mass

To find the center of mass for the system, use the formula \(\mathbf{r}_{cm} = \frac{m_1 \mathbf{r}_1 + m_2 \mathbf{r}_2}{m_1+m_2}\). Calculate the parameters required and then the center of mass.
03

Compute the Velocity of the Center of Mass

To find the velocity of the center of mass, use the formula \(\mathbf{v}_{cm} = \frac{m_1 \mathbf{v}_1 + m_2 \mathbf{v}_2}{m_1+m_2}\). Calculate the parameters required and then the velocity of the center of mass.
04

Compute the Total Linear Momentum

The total linear momentum of the system is given by \(\mathbf{p}_{total} = m_1 \mathbf{v}_1 + m_2 \mathbf{v}_2\). Calculate the parameters required and then the total linear momentum.
05

Plotting the Results

Plot the center of mass and its velocity on the same graph. Also indicate the total linear momentum of the system.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Linear Momentum
Linear momentum is an essential concept in physics that describes the quantity of motion of an object. It depends on both the mass and velocity of the object. The formula for linear momentum \( \mathbf{p} \) is given by \( \mathbf{p} = m \mathbf{v} \), where \( m \) is the mass and \( \mathbf{v} \) is the velocity.
In a system with multiple particles, like in our exercise, the total linear momentum is calculated by summing the linear momenta of each individual particle.
For our two-particle system, the total linear momentum can be found using the formula:
  • \( \mathbf{p}_{total} = m_1 \mathbf{v}_1 + m_2 \mathbf{v}_2 \)
This is important because it allows us to analyze the motion of the entire system, rather than just individual components.
This concept of linear momentum is crucial in understanding how systems behave in collisions, propulsion, and other motion-related phenomena.
Position Vectors
Position vectors are useful tools in physics to describe the location of a point or particle in a coordinate system, using a vector that starts at an origin and points to the object's position. In our exercise, you deal with two particles having their own position vectors.
The position vector for any object is typically given in the form \( \mathbf{r} = x \hat{\mathbf{i}} + y \hat{\mathbf{j}} \) in a 2D plane, where \( x \) and \( y \) are the coordinates. For our particles:
  • Particle 1 has a position vector \( \mathbf{r}_1 = (1.00 \hat{\mathbf{i}} + 2.00 \hat{\mathbf{j}}) \) meters.
  • Particle 2 has a position vector \( \mathbf{r}_2 = (-4.00 \hat{\mathbf{i}} - 3.00 \hat{\mathbf{j}}) \) meters.
Understanding these vectors helps in determining the system's center of mass, since the position vectors are a factor in its calculation. The center of mass indicates where the mass of the system is theoretically concentrated and provides insight into the balance and motion of the system.
Velocity Vectors
Velocity vectors describe the speed and direction of an object's movement. They combine magnitude (how fast the object is moving) and direction, given in units of meters per second (m/s) in physics.
In our two-particle system, each particle has its own velocity vector describing how it's moving:
  • Particle 1 has a velocity vector \( \mathbf{v}_1 = (3.00 \hat{\mathbf{i}} + 0.50 \hat{\mathbf{j}}) \) m/s.
  • Particle 2 has a velocity vector \( \mathbf{v}_2 = (3.00 \hat{\mathbf{i}} - 2.00 \hat{\mathbf{j}}) \) m/s.
Velocity vectors are crucial for determining the resultant velocity of the center of mass of the system. By averaging the influence of all velocity vectors in the system, you can find the velocity of the center of mass using:
  • \( \mathbf{v}_{cm} = \frac{m_1 \mathbf{v}_1 + m_2 \mathbf{v}_2}{m_1 + m_2} \)
This enables us to understand how the entire system moves as a whole, making it easier to predict future states of the system.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Two particles with masses \(m\) and \(3 m\) are moving toward each other along the \(x\) axis with the same initial speeds \(v_{i}\) Particle \(m\) is traveling to the left, while particle \(3 m\) is traveling to the right. They undergo an elastic glancing collision such that particle \(m\) is moving downward after the collision at right angles from its initial direction. (a) Find the final speeds of the two particles. (b) What is the angle \(\theta\) at which the particle \(3 m\) is scattered?

Most of us know intuitively that in a head-on collision between a large dump truck and a subcompact car, you are better off being in the truck than in the car. Why is this? Many people imagine that the collision force exerted on the car is much greater than that experienced by the truck. To substantiate this view, they point out that the car is crushed, whereas the truck is only dented. This idea of unequal forces, of course, is false. Newton's third law tells us that both objects experience forces of the same magnitude. The truck suffers less damage because it is made of stronger metal. But what about the two drivers? Do they experience the same forces? To answer this question, suppose that each vehicle is initially moving at \(8.00 \mathrm{m} / \mathrm{s}\) and that they undergo a perfectly inelastic head-on collision. Each driver has mass 80.0 kg. Including the drivers, the total vehicle masses are \(800 \mathrm{kg}\) for the car and 4000 kg for the truck. If the collision time is \(0.120 \mathrm{s},\) what force does the seatbelt exert on each driver?

In a slow-pitch softball game, a \(0.200-\mathrm{kg}\) softball crosses the plate at \(15.0 \mathrm{m} / \mathrm{s}\) at an angle of \(45.0^{\circ}\) below the horizontal. The batter hits the ball toward center field, giving it a velocity of \(40.0 \mathrm{m} / \mathrm{s}\) at \(30.0^{\circ}\) above the horizontal. (a) Determine the impulse delivered to the ball. (b) If the force on the ball increases linearly for \(4.00 \mathrm{ms}\), holds constant for \(20.0 \mathrm{ms},\) and then decreases to zero linearly in another \(4.00 \mathrm{ms},\) what is the maximum force on the ball?

A neutron in a nuclear reactor makes an elastic head-on collision with the nucleus of a carbon atom initially at rest. (a) What fraction of the neutron's kinetic energy is transferred to the carbon nucleus? (b) If the initial kinetic energy of the neutron is \(1.60 \times 10^{-13} \mathrm{J},\) find its final kinetic energy and the kinetic energy of the carbon nucleus after the collision. (The mass of the carbon nucleus is nearly 12.0 times the mass of the neutron.)

George of the Jungle, with mass \(m\), swings on a light vine hanging from a stationary tree branch. A second vine of equal length hangs from the same point, and a gorilla of larger mass \(M\) swings in the opposite direction on it. Both vines are horizontal when the primates start from rest at the same moment. George and the gorilla meet at the lowest point of their swings. Each is afraid that one vine will break, so they grab each other and hang on. They swing upward together, reaching a point where the vines make an angle of \(35.0^{\circ}\) with the vertical. (a) Find the value of the ratio \(m / M\) (b) What If? Try this at home. Tie a small magnet and a steel screw to opposite ends of a string. Hold the center of the string fixed to represent the tree branch, and reproduce a model of the motions of George and the gorilla. What changes in your analysis will make it apply to this situation? What If? Assume the magnet is strong, so that it noticeably attracts the screw over a distance of a few centimeters. Then the screw will be moving faster just before it sticks to the magnet. Does this make a difference?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.