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A \(400-\mathrm{N}\) child is in a swing that is attached to ropes \(2.00 \mathrm{m}\) long. Find the gravitational potential energy of the child-Earth system relative to the child's lowest position when (a) the ropes are horizontal, (b) the ropes make a \(30.0^{\circ}\) angle with the vertical, and (c) the child is at the bottom of the circular arc.

Short Answer

Expert verified
a) 800 J, b) 108.2 J, c) 0 J

Step by step solution

01

Calculate the Gravitational Potential Energy when the ropes are horizontal

When the ropes are horizontal, the child is at the maximum height of the swing's arc. As the ropes are 2.00 m long, this means the child is 2.00 m from the lowest point. The Child's mass can be calculated from the given weight (400 N) by dividing by the acceleration due to gravity: m = 400 N / 9.8 m/s^2 = 40.82 kg. Now, substitute these values into the formula for gravitational potential energy: PE = m*g*h = 40.82 kg * 9.8 m/s^2 * 2.00 m = 800 J.
02

Calculate the Gravitational Potential Energy when the ropes make a 30.0 degree angle with the vertical

In this situation, the child is not at the maximum height. To find the height, the length of the rope (2.00 m) can be multiplied by the cosine of the angle to find the adjacent side of the triangle, which represents the vertical distance from the bottom of the arc. Now, to find the height (h) above the bottom, you must subtract this distance from the length of the rope, because when the swing is at the bottom, the entire length of the rope is vertical. h = (2.00 m) - (2.00 m * cos(30)) = 0.27 m. Substituting these values into the formula for gravitational potential energy, we get: PE = m*g*h = 40.82 kg * 9.8 m/s^2 * 0.27 m = 108.2 J.
03

Calculate the Gravitational Potential Energy when the child is at the bottom of the circular arc

When the child is at the bottom of the circular arc, the height is 0, because the gravitational potential energy is being calculated relative to this point. Therefore, the gravitational potential energy is 0 J, as it is given by the equation PE = m*g*h and in this case h is 0.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Child in Swing
Imagine a child enjoying a ride on a swing in a playground. This fun experience is not just a game but a wonderful example of physics in action. The swing acts like a pendulum, constantly converting between potential and kinetic energy. In our problem, we're focused on calculating the gravitational potential energy of a child in a swing at different positions. Let's understand this better.
One of the most important concepts here is gravitational potential energy, which depends on three elements:
  • The mass of the child;
  • The height above the reference point (in this instance, the lowest point of the swing);
  • The gravitational acceleration (usually approximated to 9.8 m/s² on Earth).
Gravitational potential energy (PE) can be calculated using the formula:

\[ \text{PE} = m \cdot g \cdot h \]

Where \( m \) is the mass of the child, \( g \) is the acceleration due to gravity, and \( h \) is the height above the reference point.
When the swing is at two different heights, it changes the potential energy involved. At the highest point (when the ropes are horizontal), the energy is maximal, while at the bottom, the potential energy is at its minimum (zero, because height is zero). Understanding this ebb and flow of energy helps demystify pendulum motion.
Pendulum Motion
A swing in motion acts like a simple pendulum, swinging back and forth in a regular path. This type of motion is quite fascinating and is governed by basic principles of physics. Here, understanding how pendulum motion plays a role is key.
In our swing example, the ropes resemble the arms of a pendulum, and the arc created as the child swings back and forth is called the pendulum motion.
Several vital aspects define pendulum motion:
  • The length of the pendulum influences the time it takes to complete a swing. A longer pendulum swings more slowly than a shorter one.
  • Regardless of the weight of the pendulum, if the rope length is consistent, they take the same time to complete a swing.
  • Each swing or "oscillation" follows a predictable path due to the force of gravity acting on the child and the swing.
Pendulum motion allows us to calculate kinetic and potential energy at different positions along the swing's path. At the highest points, energy is mostly potential, and it converts to kinetic energy as the swing moves downward. Grasping these concepts is fundamental when approaching swing-related physics problems.
Physics Problems
Physics problems involving swings like our example provide a perfect blend of theory and real-world application.
When solving these types of problems, one crucial step involves deciding which point will serve as the reference for zero potential energy. In our exercise, this is the lowest point of the swing.
Let's consolidate the steps involved in such calculations:
  • Identify the system's parameters, such as mass, length, and angles.
  • Apply the fundamental equations of mechanical energy, like the gravitational potential energy formula.
  • Account for the effects of angles in calculations when the swing is not at maximum height (e.g., using trigonometric ratios).
For instance, the gravitational potential energy is easy to calculate when the swing ropes are horizontal because the task is straightforward: substitute all values into our formula \( \text{PE} = m \cdot g \cdot h \). For angles other than zero or ninety degrees, we also need trigonometry to determine the height accordingly. Properly understanding each step helps break down the complexity and makes solving similar physics problems much easier.

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Most popular questions from this chapter

A uniform chain of length \(8.00 \mathrm{m}\) initially lies stretched out on a horizontal table. (a) If the coefficient of static friction between chain and table is \(0.600,\) show that the chain will begin to slide off the table if at least 3.00 m of it hangs over the edge of the table. (b) Determine the speed of the chain as all of it leaves the table, given that the coefficient of kinetic friction between the chain and the table is \(0.400 .\)

Dave Johnson, the bronze medalist at the 1992 Olympic decathlon in Barcelona, leaves the ground at the high jump with vertical velocity component \(6.00 \mathrm{m} / \mathrm{s}\). How far does his center of mass move up as he makes the jump?

A single conservative force acting on a particle varies as \(\mathbf{F}=\left(-A x+B x^{2}\right) \hat{\mathbf{i}} N,\) where \(A\) and \(B\) are constants and \(x\) is in meters. (a) Calculate the potential-energy function \(U(x)\) associated with this force, taking \(U=0\) at \(x=0 .\) (b) Find the change in potential energy and the change in kinetic energy as the particle moves from \(x=2.00 \mathrm{m}\) to \(x=3.00 \mathrm{m}\).

A toy cannon uses a spring to project a \(5.30-\mathrm{g}\) soft rubber ball. The spring is originally compressed by \(5.00 \mathrm{cm}\) and has a force constant of \(8.00 \mathrm{N} / \mathrm{m}\). When the cannon is fired, the ball moves \(15.0 \mathrm{cm}\) through the horizontal barrel of the cannon, and there is a constant friction force of \(0.0320 \mathrm{N}\) between the barrel and the ball. (a) With what speed does the projectile leave the barrel of the cannon? (b) At what point does the ball have maximum speed? (c) What is this maximum speed?

Air moving at \(11.0 \mathrm{m} / \mathrm{s}\) in a steady wind encounters a windmill of diameter \(2.30 \mathrm{m}\) and having an efficiency of \(27.5 \% .\) The energy generated by the windmill is used to pump water from a well \(35.0 \mathrm{m}\) deep into a tank \(2.30 \mathrm{m}\) above the ground. At what rate in liters per minute can water be pumped into the tank?

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