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A space station, in the form of a wheel 120 m in diameter, rotates to provide an "artificial gravity" of \(3.00 \mathrm{m} / \mathrm{s}^{2}\) for persons who walk around on the inner wall of the outer rim. Find the rate of rotation of the wheel (in revolutions per minute) that will produce this effect.

Short Answer

Expert verified
To solve for the rate of rotation that produces the 'artificial gravity', calculate the radius of the wheel first. Then, use the given 'artificial gravity' and the calculated radius to find the velocity. Finally, use the calculated velocity and radius to find the rate of rotation in revolutions per minute.

Step by step solution

01

Calculating the radius of the wheel

The radius of the wheel is half the diameter. Given that the diameter of the wheel is 120 m, the radius \( r \) would be \(\frac{120m}{2} = 60 m\).
02

Calculating the velocity

The formula for centripetal acceleration is \(a = \frac{{v^2}}{{r}}\), you can rearrange for velocity \( v = \sqrt{{a*r}}\). Substituting the given acceleration 3.00 \(m/s^2\) and the calculated radius 60 m, we find \(v = \sqrt{{3.00 m/s^2 * 60 m}}\). Calculate this to find the velocity.
03

Calculating the rate of rotation

The formula for the rate of rotation is \(v = 2*\pi*r*N\), where \(N\) is the revolution per minute. Rearranging for \(N\) yields \(N = \frac{v}{{2*\pi*r}}\). Substitute the calculated velocity and radius into the formula to obtain the rate of rotation in revolutions per minute.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Centripetal Acceleration
Centripetal acceleration is crucial for understanding why artificial gravity can exist in a rotating space station. It is the acceleration required to keep an object moving in a circular path and is directed toward the center of the circle. This occurs because when an object travels around a circle, it constantly changes direction, and acceleration is required for this change.
The formula for centripetal acceleration is \[ a = \frac{v^2}{r} \]where \( a \) is the centripetal acceleration, \( v \) is the velocity of the object, and \( r \) is the radius of the circle.
In the context of the space station, centripetal acceleration simulates gravity by creating a force toward the center of the station's rotation. This allows astronauts to feel as though they are being "pulled" down onto the floor of the station's outer rim, mimicking Earth’s gravity to some degree. This concept helps astronauts maintain their physiological functions over long missions.
Rate of Rotation
The rate of rotation refers to how quickly the space station completes a circular path, and it is usually measured in revolutions per minute (RPM). Knowing the rate of rotation is vital in calculating how much artificial gravity you can generate.
To find this, we rearrange the velocity formula to solve for the rate of rotation. Essentially, as the station rotates, people experience the centripetal force as gravity, allowing them to stand and walk as they would on Earth. For this space station:
  • The diameter is 120 m, so the radius \( r \) is 60 m.
  • Given centripetal acceleration \( a = 3.00 \mathrm{m/s}^2 \).
Calculate the velocity \( v \) using:\[ v = \sqrt{a \times r} \]After obtaining the velocity, use the formula:\[ N = \frac{v}{2 \pi r} \]This calculation lets us find \( N \), or the number of revolutions per minute needed for the desired artificial gravity. Understanding this helps in designing rotations that safely replicate gravity for long-term space dwellers.
Space Station Dynamics
Space station dynamics involve understanding the physics that govern the movement and stabilization of these immense structures in outer space. Rotational motion is key here.
For a wheel-shaped space station, achieving artificial gravity involves careful balancing of forces to maintain a stable rotation. The structure must spin at a rate that ensures crew comfort and safety, simulating conditions on Earth as closely as possible.
  • Stable rotation keeps space debris and various unnecessary vibrations from destabilizing the station.
  • Systems need to manage any energy losses due to friction or external forces acting on the rotating system.
In this dynamic environment, engineers must also consider aspects like energy sources, materials used to construct the station, and the effects of radiation. By understanding these dynamics, astronauts can live and work in space with minimized risks, making space exploration more accessible and sustainable. Such designs not only promote crew comfort but might one day facilitate longer missions and even future space tourism.

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Most popular questions from this chapter

A car rounds a banked curve as in Figure \(6.6 .\) The radius of curvature of the road is \(R\), the banking angle is \(\theta,\) and the coefficient of static friction is \(\mu_{s}\) (a) Determine the range of speeds the car can have without slipping up or down the road. (b) Find the minimum value for \(\mu_{s}\) such that the minimum speed is zero. (c) What is the range of speeds possible if \(R=100 \mathrm{m}, \theta=10.0^{\circ},\) and \(\mu_{s}=0.100\) (slippery conditions)?

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