/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 13 A \(40.0-\mathrm{kg}\) child swi... [FREE SOLUTION] | 91Ó°ÊÓ

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A \(40.0-\mathrm{kg}\) child swings in a swing supported by two chains, each \(3.00 \mathrm{m}\) long. If the tension in each chain at the lowest point is \(350 \mathrm{N},\) find \((\mathrm{a})\) the child's speed at the lowest point and (b) the force exerted by the seat on the child at the lowest point. (Neglect the mass of the seat.)

Short Answer

Expert verified
The speed of the child at the lowest point is 0 m/s, and the force exerted by the seat on the child at the lowest point is 300.8 N.

Step by step solution

01

Determine the Potential Energy

By applying the conservation of energy (potential energy at the top equals kinetic energy at the bottom), we can find the speed at the lowest point. However, we first need to find the Potential Energy (PE) at the highest point. The PE when the swing is at its extreme point will be given by the formula PE = mgh, where m is the mass of the child, g is the acceleration due to gravity, and h is the perpendicular height from the lowest point. h is also equal to chain length (l) minus l*cos(\(\theta\)). But when the swing is at extreme position, \(\theta\) = 180, so the h = 0. Thus the PE = 0.
02

Calculate the velocity

For the kinetic energy (KE) at the lowest point, we use the formula (KE = 1/2 m v^2) where m is again the mass of the child and v is the velocity that we need to find. Since PE = KE and PE = 0, this will give us 1/2 m v^2 = 0. Solving this equation for v, gives us the velocity which turns out to be 0 m/s.
03

Compute the Total Force

Now that we have the velocity, we need to solve for the net force acting on the child at the lowest point. Since the swing moves in a curved pathway, the forces acting on the child are his weight (Force due to gravity, Fg = mg) and the force of tension (Ft = 2T because of the 2 chains) in the chains. So we can write the net force (F_net) as Ft - Fg.
04

Solve for the Net Force (Seat Force)

Substituting the given values into the equation from Step 3, we get F_net = Ft - Fg = 2T - mg. Substituting the known values (T = 350N, m = 40kg, g = 9.81 m/s^2), we find F_net = 2*350N - 40kg*9.81m/s^2. Computing the values, we find that the force exerted by the seat on the child at the lowest point is 300.8 N.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Conservation of Energy
The principle of conservation of energy is one of the most fundamental concepts in physics. It posits that energy cannot be created or destroyed, only transformed from one form to another. This principle is key when solving problems involving the motion of objects, such as a child on a swing.

In the given exercise, we're looking at a scenario where a child's potential energy (at the maximum height of the swing) is converted into kinetic energy (at the lowest point of the swing). The exercise assumes that the energy conversion is perfect and that no energy is lost to air resistance or friction, which often isn't the case in real-life scenarios.

It's critical to recognize that in a more realistic scenario, we would have to account for these losses. The child's speed at the bottom would be less than what would be calculated assuming perfect energy conversion, but in ideal physics problems, we often ignore such losses to simplify calculations.
Potential Energy
Potential energy refers to the energy that an object has due to its position in a force field – commonly a gravitational field. It is called 'potential' because it has the potential to be converted into other forms of energy, such as kinetic energy.

In the context of our swing problem, the child has maximum potential energy at the highest point of the swing. This energy is given by the formula \( PE = mgh \) where \(m\) is the mass of the child, \(g\) is the acceleration due to gravity, and \(h\) is the height above the lowest point of the swing. However, in the solved exercise, the potential energy is mistakenly considered zero at the highest position. In an improved solution, we would calculate \(h\) correctly to find the initial potential energy before the swing descends.
Kinetic Energy
Kinetic energy is the energy an object possesses due to its motion. It depends on both the mass of the object and the square of its velocity and is given by the equation \( KE = \frac{1}{2}mv^2 \).

In our exercise involving the swing, all the potential energy the child has at the top is converted to kinetic energy at the bottom. The statement anticipates a velocity of 0 m/s at the lowest point, which implies, according to conservation of energy, that the potential energy at the highest point was also zero. This would be a mistake since the child must have had some potential energy to start with, which would convert into kinetic energy as the child moves down. The correct approach would be to determine the height of the swing at its peak and use conservation of energy to find the speed at the lowest point.
Forces in Circular Motion
When an object moves in a circular path, it experiences a force directed towards the center of the circle, known as centripetal force. The child on the swing, at the lowest point, is in circular motion and undergoes centripetal acceleration. The tensions in the chains provide the necessary centripetal force to keep the child moving in this curved path.

The force exerted by the seat on the child (also known as the normal force) is crucial in keeping the child in motion. It's the sum of the gravitational force and the centripetal force necessary for circular motion. Therefore, while the step-by-step solution calculated a net force, it’s important to understand that this net force should refer to the centripetal force necessary for circular motion, and not the actual force the seat exerts on the child.

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