/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 76 Prepare a graph of the relativis... [FREE SOLUTION] | 91Ó°ÊÓ

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Prepare a graph of the relativistic kinetic energy and the classical kinetic energy, both as a function of speed, for an object with a mass of your choice. At what speed does the classical kinetic energy underestimate the experimental value by \(1 \% ?\) by \(5 \% ?\) by \(50 \% ?\)

Short Answer

Expert verified
The graph should show the classical kinetic energy starting off equal to the relativistic kinetic energy when the speed is zero, and then diverging as the speed increases. Solving the equation \((E_r - E_c)/E_r * 100\% = x\%\) for the different percentages will yield the corresponding speeds.

Step by step solution

01

Graph the Energies as a Function of Speed

Choose a mass for the object. Then, using the formulas for classical and relativistic kinetic energy, plot both on the same graph as a function of speed. \(v\) should range from 0 to a value close to \(c\). Make sure to label each curve with its respective energy.
02

Calculate the Speed at 1%

Once the graphs are plotted, we need to determine the speed at which the classical kinetic energy underestimates the experimental value by \(1\%\). To do so, set \((E_r - E_c)/E_r * 100\% = 1\%\). Solve the resulting equation for \(v\).
03

Repeat for The Other Percentages

Repeat step 2, but substitute \(5\%\) and then \(50\%\) for 1% in the equation.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Classical Kinetic Energy
Classical kinetic energy embodies the energy that an object possesses due to its motion, an idea that's rooted in Newtonian mechanics. It's expressed through the formula
\begin{align*}K = \frac{1}{2}mv^2, d{align*}where \(m\) is the mass of the object, and \(v\) is the velocity at which it's travelling. In the scope of classical mechanics, kinetic energy is a straightforward way to understand how much work the object can do by virtue of its motion or how much energy is needed to bring it to rest from its current state of movement. This principle is essential when studying motion and forms the basis of many equations and laws in physics.
However, classical kinetic energy assumes that speeds are much lower than the speed of light \(c\), and the relationship between kinetic energy and speed is directly proportional - the energy increases with the square of the speed. But as objects reach speeds that are a significant fraction of \(c\), classical mechanics breaks down, and we must turn to the principles of special relativity to understand the energy dynamics accurately.
Graphing Kinetic Energy
Graphing kinetic energy as a function of speed provides an illustrative comparison between classical and relativistic kinetic energy calculations. We plot the kinetic energy on the y-axis and the object's speed on the x-axis. For classical kinetic energy, the plot is a parabola starting at the origin, reflecting the \(\frac{1}{2}mv^2\) relationship; where the slope increases as speed increases, depicting that energy required to accelerate the object increases at higher speeds.
Using graphing software or manual plotting, you can see the divergence from classical to relativistic kinetic energy as speeds get closer to \(c\). A notable detail in these graphs is the drastic increase in relativistic kinetic energy as the object's speed approaches the speed of light, showing us the nonlinearity of the relationship and illustrating how at high speeds, calculating kinetic energy with classical means significantly underestimates the actual energy of the object. This visualization is an excellent tool for comprehending the limitations of classical physics and the necessity for a relativistic framework.
Special Relativity
Special relativity is a groundbreaking theory put forth by Albert Einstein in 1905, which revolutionized our understanding of space, time, and energy. It's based on two fundamental postulates: the laws of physics are the same for all observers in uniform motion relative to one another (the principle of relativity), and the speed of light in a vacuum is the same for all observers, regardless of the movement of the light source or observer.
Kinetic energy in the realm of special relativity is calculated differently from classical mechanics to account for the effects near the speed of light. The relativistic kinetic energy equation is:\begin{align*}E_k = (\frac{1}{\radical{0}{1 - \frac{v^2}{c^2}}} - 1)mc^2, d{align*}which shows that as an object's velocity (\(v\)) approaches the speed of light (\(c\)), its kinetic energy approaches infinity, making it theoretically impossible for an object with mass to reach this cosmic speed limit.
This concept shakes the foundation of physics, prompting the reevaluation of many classical ideas. For students grappling with these principles, understanding this conceptual leap concerning energy and motion at high velocities is crucial, as is recognizing the seamless transition from Newtonian to Einsteinian physics as one explores phenomena across a wide range of speeds.

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Most popular questions from this chapter

A physics professor on the Earth gives an exam to her students, who are in a spacecraft traveling at speed \(v\) relative to the Earth. The moment the craft passes the professor, she signals the start of the exam. She wishes her students to have a time interval \(T_{0}\) (spacecraft time) to complete the exam. Show that she should wait a time interval (Earth time) of $$ T=T_{0} \sqrt{\frac{1-v / c}{1+v / c}} $$ before sending a light signal telling them to stop. (Suggestion: Remember that it takes some time for the second light signal to travel from the professor to the students.)

A ball is thrown at \(20.0 \mathrm{m} / \mathrm{s}\) inside a boxcar moving along the tracks at \(40.0 \mathrm{m} / \mathrm{s} .\) What is the speed of the ball relative to the ground if the ball is thrown (a) forward (b) backward (c) out the side door?

Compact high-power lasers can produce a \(2.00-\mathrm{J}\) light pulse of duration \(100 \mathrm{fs}\), focused to a spot \(1 \mu \mathrm{m}\) in diameter. (See Mourou and Umstader, "Extreme Light," Scientific American, May \(2002, \text { page } 81 .)\) The electric field in the light accelerates electrons in the target material to near the speed of light. (a) What is the average power of the laser during the pulse? (b) How many electrons can be accelerated to \(0.9999 c\) if \(0.0100 \%\) of the pulse energy is converted into energy of electron motion?

A gamma ray (a high-energy photon) can produce an electron \(\left(\mathrm{e}^{-}\right)\) and a positron \(\left(\mathrm{e}^{+}\right)\) when it enters the electric field of a heavy nucleus: \(\gamma \rightarrow \mathrm{e}^{+}+\mathrm{e}^{-} .\) What minimum gamma-ray energy is required to accomplish this task? (Note: The masses of the electron and the positron are equal.)

An alien spaceship traveling at \(0.600 c\) toward the Earth launches a landing craft with an advance guard of purchasing agents and physics teachers. The lander travels in the same direction with a speed of \(0.800 c\) relative to the mother ship. As observed on the Earth, the spaceship is 0.200 ly from the Earth when the lander is launched. (a) What speed do the Earth observers measure for the approaching lander? (b) What is the distance to the Earth at the time of lander launch, as observed by the aliens? (c) How long does it take the lander to reach the Earth as observed by the aliens on the mother ship? (d) If the lander has a mass of \(4.00 \times 10^{5} \mathrm{kg},\) what is its kinetic energy as observed in the Earth reference frame?

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