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A diffraction grating has 4200 rulings/cm. On a screen \(2.00 \mathrm{m}\) from the grating, it is found that for a particular order \(m,\) the maxima corresponding to two closely spaced wavelengths of sodium \((589.0 \mathrm{nm} \text { and } 589.6 \mathrm{nm})\) are separated by \(1.59 \mathrm{mm} .\) Determine the value of \(m\)

Short Answer

Expert verified
The value of \(m\) is approximately 3.

Step by step solution

01

Understand the Grating Equation

The grating equation is \(d \cdot \sin(\theta) = m \cdot \lambda\), where \(d\) is the distance between slits (1 divided by the number of rulings per unit), \(\theta\) is the angle of diffraction, \(m\) is the diffraction order and \(\lambda\) is the wavelength.
02

Conversion of units

First, convert the given values to the appropriate units for use in the formula. The number of rulings per centimetre needs to be converted to rulings per meter, so: \(rulings/meter = 4200 \cdot 10^2 = 420000\). The distance between slits \(d\) is then calculated: \(d = 1/rulings = 1/420000 = 2.38 \cdot 10^{-6}\) m. Similarly, the wavelengths have to be converted to meters: \(\lambda_1 = 589.0 \cdot 10^{-9}\) m and \(\lambda_2 = 589.6 \cdot 10^{-9}\) m.
03

Differences in wavelengths and angles

Next, calculate the difference between the two wavelengths, which corresponds to the difference in the angles for each maximum: \(\Delta \lambda = \lambda_2 - \lambda_1 = 0.6 \cdot 10^{-9}\) m. The difference in the angles of maxima \(\theta_1\) and \(\theta_2\) are linked to the difference in position on the screen given by: \(\Delta y = 1.59 \cdot 10^{-3}\) m. From the right triangle formed, \(\sin(\Delta \theta) = \Delta y / L\), where \(L\) is the screen distance. Thus, \(\Delta \theta = \arcsin( \Delta y / L) = \arcsin(1.59 \cdot 10^{-3} / 2) = 7.95 \cdot 10^{-4}\) radians.
04

Apply the Grating Equation and solve for m

Substitute the calculated differences into the grating equation: \(d \cdot \Delta \theta = m \cdot \Delta \lambda\) . Solving for \(m\), one gets: \(m = d \cdot \Delta \theta / \Delta \lambda = (2.38 \cdot 10^{-6} \cdot 7.95 \cdot 10^{-4}) / (0.6 \cdot 10^{-9})\) .
05

Calculate m

Finally, calculate \(m\) using the values found in the previous steps, yielding \(m \approx 3\). This means the diffraction order for the given setup and wavelengths is three.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Grating Equation
A diffraction grating is a tool used in optics to separate light into its different wavelengths or colors. It's like a series of tiny slits or grooves that scatter light in certain directions. The grating equation helps us predict where each wavelength will end up on a screen or detector.

The grating equation is written as:
  • \(d \cdot \sin(\theta) = m \cdot \lambda\)
    • In this formula:
      • \(d\) is the distance between the slits in the grating. To find it, divide 1 by the number of rulings per meter of grating.
      • \(\theta\) is the angle at which the light exits the grating.
      • \(m\) is the diffraction order, which is the number of wavelengths by which paths differ.
      • \(\lambda\) is the wavelength of light, which we often convert from nanometers to meters for consistency.

      By using this equation, we can precisely determine how light will spread out when it hits the grating. This is critical for analyzing the composition of light sources and understanding physical phenomena like rainbows or spectrums.
Wavelength Separation
When multiple wavelengths of light pass through a diffraction grating, the light is spread out into distinct paths. This creates what we call separation between different wavelengths on a screen. Wavelength separation is crucial in applications like spectroscopy, where the goal is to analyze different components of light.

Given two closely related wavelengths, their separation on the screen depends on several factors:
  • The diffraction order \(m\) - Higher orders might result in greater separation.
  • The distance \(L\) from the grating to the screen.
  • The actual difference between the wavelengths \(\Delta \lambda\).
To calculate the distance between the two wavelengths on the screen, we use the small angle approximation, where:
  • \(\Delta y = L \cdot \Delta \theta\).
Here, \(\Delta \theta\) represents the change in angle derived from the separation of the two maxima on the grating. This simple relation helps us understand the spread of each wavelength as it hits a screen or detector.
Diffraction Order
Diffraction order is a way we label the multiple paths or fringes created by a diffraction grating. In essence, each time light is deflected from the grating, it can create various sets of constructive interference, leading to different paths termed as orders, denoted by \(m\).

The key factors that affect how diffraction order works include:
  • The wavelength \(\lambda\) of light used - Different wavelengths will create different maxima at different angles \(\theta\).
  • The grating spacing \(d\).
  • The angle \(\theta\) at which each path emerges.

In some cases, higher orders can allow us to spread light over a broader spectrum, providing more resolution in identifying wavelengths. However, it’s essential to remember that higher diffraction orders can sometimes overlap, complicating the analysis of spectral data. By calculating the diffraction order \(m\), using the formula \(m = d \cdot \Delta \theta / \Delta \lambda\), we can predict which order matches certain regions of data we might be interested in analyzing.

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Most popular questions from this chapter

Light of wavelength \(500 \mathrm{nm}\) is incident normally on a diffraction grating. If the third-order maximum of the diffraction pattern is observed at \(32.0^{\circ},\) (a) what is the number of rulings per centimeter for the grating? (b) Determine the total number of primary maxima that can be observed in this situation.

A beam of laser light of wavelength \(632.8 \mathrm{nm}\) has a circular cross section \(2.00 \mathrm{mm}\) in diameter. A rectangular aperture is to be placed in the center of the beam so that, when the light falls perpendicularly on a wall \(4.50 \mathrm{m}\) away, the central maximum fills a rectangle \(110 \mathrm{mm}\) wide and \(6.00 \mathrm{mm}\) high. The dimensions are measured between the minima bracketing the central maximum. Find the required width and height of the aperture.

When Mars is nearest the Earth, the distance separating the two planets is \(88.6 \times 10^{6} \mathrm{km} .\) Mars is viewed through a telescope whose mirror has a diameter of \(30.0 \mathrm{cm} .\) (a) If the wavelength of the light is \(590 \mathrm{nm},\) what is the angular resolution of the telescope? (b) What is the smallest distance that can be resolved between two points on Mars?

Light from an argon laser strikes a diffraction grating that has 5310 grooves per centimeter. The central and firstorder principal maxima are separated by \(0.488 \mathrm{m}\) on a wall \(1.72 \mathrm{m}\) from the grating. Determine the wavelength of the laser light.

Helium-neon laser light \((\lambda=632.8 \mathrm{nm})\) is sent through a \(0.300-\mathrm{mm}\) -wide single slit. What is the width of the central maximum on a screen \(1.00 \mathrm{m}\) from the slit?

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