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Two narrow parallel slits separated by 0.850 mm are illuminated by 600 -nm light, and the viewing screen is \(2.80 \mathrm{m}\) away from the slits. (a) What is the phase difference between the two interfering waves on a screen at a point \(2.50 \mathrm{mm}\) from the central bright fringe? (b) What is the ratio of the intensity at this point to the intensity at the center of a bright fringe?

Short Answer

Expert verified
The phase difference between the two interfering waves on the screen at a point \(2.50 \mathrm{mm}\) from the central bright fringe is \( Ï• \), and the intensity ratio at this point to the intensity at the center of a bright fringe is \( I \).

Step by step solution

01

Find Distance to the First Fringe

First, calculate the distance \( d \) to the first fringe using the formula \( d= \frac{λ}{s} = \frac{600 E-009 m}{0.850 E-003 m}\) .
02

Find the Order Number

Calculate the order number \( m \) using the formula \( m= \frac{0.0025 m}{d}\).
03

Calculate the Path Difference

Calculate the path difference using the formula \( mλ\), where \( m \) is the order number and \( λ \) is the wavelength.
04

Determine the Phase Difference

The phase difference can be calculated by using the formula \( ϕ= \frac{2π}{λ} Δl \), where \( Δl \) is the path difference.
05

Calculate the Intensity Ratio

The intensity ratio can be determined using the formula \[ I = \frac{I_{max} cos^{2}(Ï•/2)}{I_{max}} \], where \( I_{max} \) is the maximum intensity. In this case, \( I_{max} \) is set to 1, so the intensity ratio is simply \( I = cos^{2}(Ï•/2) \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Wave Interference
Wave interference is a fundamental phenomenon occurring when two or more waves traverse the same space. When two waves meet, their displacements combine, resulting in a new wave pattern. This pattern can be constructive or destructive, depending on the relative phase of the individual waves. Constructive interference happens when the waves align with matching phases, amplifying the resultant wave. Conversely, destructive interference occurs when waves are out of phase, diminishing or even cancelling the resultant wave.

For instance, in the exercise with two slits, waves emanating from each slit combine to form an interference pattern on a screen. This pattern is composed of alternating bright and dark fringes where bright fringes denote areas of constructive interference, and dark fringes indicate destructive interference. Understanding the principles of wave interference allows for the prediction of such patterns in various practical applications, from engineering to medical imaging.
Path Difference Calculation
The path difference between two waves is crucial in determining the type of interference that occurs at a specific point. It's defined as the difference in the distances from each wave's origin to the point of interest. To calculate the path difference, one can use the relationship between the distance from the slits to the screen, the wavelength of the light, and the separation of the slits. In the provided exercise, the order number m gives the fringe number and, multiplied by the wavelength \( \lambda \), gives the path difference.

Calculating the path difference is the first step in predicting the interference pattern. In the case of the double-slit experiment, as the light from each slit travels different distances to reach the same point on the screen, this path difference is what causes the interference fringes to form.
Intensity Ratio in Interference
The intensity ratio in interference refers to the comparative brightness of different points in an interference pattern. This concept is particularly useful in understanding the visibility of the fringes on the screen. The intensity of the bright fringes depends on the degree of constructive interference, which in turn is determined by the path difference.

The intensity ratio is calculated using the maximum intensity \(I_{max}\) and the phase difference \(\phi\) between waves. The formula \[ I = \frac{I_{max} \cos^{2}(\phi/2)}{I_{max}} \] used in the exercise represents the intensity at any given point as a fraction of the maximum intensity observed at the center of a bright fringe. This allows students to understand how the intensity varies across the interference pattern and predict the contrast between bright and dark fringes.
Phase Difference in Waves
Phase difference is an important concept that describes the relative timing of two waves at a point in space. It is measured in radians or degrees and indicates whether waves are in step (constructive interference) or out of step (destructive interference). In physics, the phase difference is a reflection of the path difference, as it translates the physical separation between waves into their relative positions within a cycle.

The calculation of phase difference is demonstrated in the solution steps where the formula \(\phi= \frac{2\pi}{\lambda} \Delta l\) is employed. Here, \(\Delta l\) is the path difference. By calculating the phase difference, we can infer the type of interference and determine the brightness of the fringes at different points on the screen, cementing the connection between the wave’s spatial journey and its observable effects.

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Most popular questions from this chapter

A flat piece of glass is held stationary and horizontal above the flat top end of a 10.0 -cm-long vertical metal rod that has its lower end rigidly fixed. The thin film of air between the rod and glass is observed to be bright by reflected light when it is illuminated by light of wavelength \(500 \mathrm{nm} .\) As the temperature is slowly increased by \(25.0^{\circ} \mathrm{C}\) the film changes from bright to dark and back to bright 200 times. What is the coefficient of linear expansion of the metal?

Two narrow, parallel slits separated by \(0.250 \mathrm{mm}\) are illuminated by green light \((\lambda=546.1 \mathrm{nm}) .\) The interference pattern is observed on a screen \(1.20 \mathrm{m}\) away from the plane of the slits. Calculate the distance (a) from the central maximum to the first bright region on either side of the central maximum and (b) between the first and second dark bands.

Monochromatic light is beamed into a Michelson interferometer. The movable mirror is displaced \(0.382 \mathrm{mm}\) causing the interferometer pattern to reproduce itself 1700 times. Determine the wavelength of the light. What color is it?

The intensity on the screen at a certain point in a doubleslit interference pattern is \(64.0 \%\) of the maximum value. (a) What minimum phase difference (in radians) between sources produces this result? (b) Express this phase difference as a path difference for 486.1 -nm light.

When a liquid is introduced into the air space between the lens and the plate in a Newton's-rings apparatus, the diameter of the tenth ring changes from 1.50 to \(1.31 \mathrm{cm} .\) Find the index of refraction of the liquid.

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