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A person sees clearly when he wears eyeglasses that have a power of -4.00 adopters and sit \(2.00 \mathrm{cm}\) in front of his eyes. If the person wants to switch to contact lenses, which are placed directly on the eyes, what lens power should be prescribed?

Short Answer

Expert verified
The power of the contact lenses should be -4.5 D.

Step by step solution

01

Understand and mark known quantities

We know the eyeglasses have a power of -4.00 D and they are 2 cm in front of the eyes. We also know that contact lenses will be placed directly on the eyes, i.e., 0 cm from the eyes.
02

Apply the lens power formula

The lens power formula relating the object distance \(u\), image distance \(v\), and focal length \(f\) is given by \( 1/f = 1/v - 1/u \). Substituting the given values (keep in mind that power of glasses and focal length have an inverse relation, and that conventionally, distances toward the left of the lens are taken as negative), we get \( 1/f_{glasses} = 1/(-2 cm) - (-4 D) = -4.5 D \). Note that the overall power is less negative than the eyepiece power because the eyepiece is moved away from the eye, causing the eye to 'see' less power.
03

Calculate the power of the contact lenses

The contact lenses are placed directly on the eyes, which means the distance between them and the eye is essentially zero. Therefore, their effective power is the same as their actual power. So, \( P_{contacts} = -4.5 D \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Lens Power
Lens power, often measured in diopters (D), describes the optical strength of a lens. It indicates how well a lens can converge or diverge light. The power is determined by the focal length (\( f \)), with the formula: \( P = \frac{1}{f} \).

A positive lens power implies a converging (convex) lens, suitable for correcting farsightedness (hyperopia). Conversely, a negative power denotes a diverging (concave) lens, used to correct nearsightedness (myopia).

When determining the proper lens power for glasses or contact lenses, it's crucial to consider the distance from the eye. This proximity impacts the effective power, as lenses further from or closer to the eye behave differently.
Contact Lenses
Contact lenses are thin lenses placed directly on the surface of the eyes. Unlike eyeglasses, which sit a small distance away from the eyes, contact lenses move with the eye.

Three primary types of contact lenses include:
  • Soft contact lenses: Made from flexible plastic that allows oxygen to pass through to the cornea.
  • Rigid gas permeable lenses: Made from more durable materials, offering clearer vision for some users.
  • Hybrid lenses: Combine features of both soft and rigid lenses, offering comfort and sharp vision.
Contact lenses are often favored for activities where glasses might become cumbersome, but require strict hygiene practices to avoid infections.
Vision Correction
Vision correction using lenses aims to adjust the focusing power of the eye to bring light rays precisely onto the retina.

For people with nearsightedness:
  • Light focuses in front of the retina.
  • Diverging lenses extend the focus to the retina.


For farsighted individuals:
  • Light rays converge behind the retina.
  • Converging lenses adjust the light to focus on the retina.


Addressing these refractive errors not only aids in seeing clearly but also enhances quality of life by reducing eye strain and providing a normal field of vision.
Lens Formula
The lens formula provides a mathematical relationship between the optical properties of lenses, described by:\[ \frac{1}{f} = \frac{1}{v} - \frac{1}{u} \]

Where:
  • \( f \): Focal length of the lens
  • \( v \): Image distance from the lens
  • \( u \): Object distance from the lens

This formula is crucial for calculating the required power of lenses, especially when switching between eyeglasses and contact lenses, as the object and image distances vary.

In practical scenarios, it's essential to understand that increasing the lens distance from the eye (as in eyeglasses) decreases its effective power, necessitating adjustments when switching to contact lenses that sit directly on the eye.

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Most popular questions from this chapter

A cataract-impaired lens in an eye may be surgically removed and replaced by a manufactured lens. The focal length required for the new lens is determined by the lens-to-retina distance, which is measured by a sonar-like device, and by the requirement that the implant provide for correct distant vision. (a) Assuming the distance from lens to retina is \(22.4 \mathrm{mm},\) calculate the power of the implanted lens in adopters. (b) Because no accommodation occurs and the implant allows for correct distant vision, a corrective lens for close work or reading must be used. Assume a reading distance of \(33.0 \mathrm{cm}\) and calculate the power of the lens in the reading glasses.

A concave mirror has a focal length of \(40.0 \mathrm{cm} .\) Determine the object position for which the resulting image is upright and four times the size of the object.

The disk of the Sun subtends an angle of \(0.533^{\circ}\) at the Earth. What are the position and diameter of the solar image formed by a concave spherical mirror with a radius of curvature of \(3.00 \mathrm{m} ?\)

The Yerkes refracting telescope has a \(1.00-\mathrm{m}\) diameter objective lens of focal length \(20.0 \mathrm{m} .\) Assume it is used with an eyepiece of focal length \(2.50 \mathrm{cm} .\) (a) Determine the magnification of the planet Mars as seen through this telescope. (b) Are the Martian polar caps right side up or upside down?

In some types of optical spectroscopy, such as photoluminescence and Raman spectroscopy, a laser beam exits from a pupil and is focused on a sample to stimulate electromagnetic radiation from the sample. The focusing lens usually has an antireflective coating preventing any light loss. Assume a \(100-\mathrm{mW}\) laser is located \(4.80 \mathrm{m}\) from the lens, which has a focal length of \(7.00 \mathrm{cm} .\) (a) How far from the lens should the sample be located so that an image of the laser exit pupil is formed on the surface of the sample? (b) If the diameter of the laser exit pupil is \(5.00 \mathrm{mm},\) what is the diameter of the light spot on the sample? (c) What is the light intensity at the spot?

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