/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 20 Unpolarized light in vacuum is i... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Unpolarized light in vacuum is incident onto a sheet of glass with index of refraction \(n .\) The reflected and refracted rays are perpendicular to each other. Find the angle of incidence. This angle is called Brewster's angle or the polarizing angle. In this situation the reflected light is linearly polarized, with its electric field restricted to be perpendicular to the plane containing the rays and the normal.

Short Answer

Expert verified
Brewster's angle or the polarising angle (angle of incidence) can be calculated under normal conditions by taking the arctangent of the index of refraction of the medium, and is expressed mathematically as \(i = atan(n)\).

Step by step solution

01

Understand Brewster's angle

Brewster's angle is the angle of incidence at which light with a particular polarization is perfectly transmitted through a transparent dielectric surface, with no reflection. When unpolarized light is incident at this angle, the light that is reflected from the surface is therefore perfectly polarized. This phenomena is named after the Scottish physicist Sir David Brewster (1781–1868).
02

Transcribe the problem into equations

According to the problem, the reflected and refracted rays are perpendicular to each other. Thus the sum of the angle of incidence \(i\) and angle of refraction \(r\) is 90 degrees. Mathematically \(i + r = 90^o\) or \(r = 90^o - i\).
03

Apply Snell's law

Snell's Law states that the ratio of the sine of the angles of incidence and refraction is equivalent to the ratio of phase velocities (v1 / v2) in the two media, or equivalently, to the opposite ratio of the indices of refraction (n2 / n1). So the equation for Snell's law is: \(sin(i) / sin(r) = n_2 / n_1\). Here n_1 is index of refraction of medium 1(in the case of light, vacuum, it is 1), n_2 is index of refraction of medium 2(in the case of glass, it is \(n\)). Substitute \(r\) into the Snell's law \(sin(i) / sin(90^o - i) = n / 1\). This yields: \(sin(i) = n * cos(i)\).
04

Solve for angle i

This equation is a standard form for Brewster's angle. The solution for this equation for angle \(i\) (in degrees) is \(i = atan(n)\). Thus angle of incidence i, Brewster's angle, can be calculated under normal conditions by taking the arctangent of the index of refraction of the medium.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Snell's Law
Snell's Law is a fundamental principle in optics that describes how light changes direction as it travels between different media with varying optical densities. It is the reason why a pencil appears bent when it's dipped in water and why we see a rainbow after a storm.

When light rays pass from one medium to another (say, from air to water), their speed changes due to the difference in the media's optical properties. This change in speed causes the light rays to bend—a phenomenon known as refraction. Snell's Law mathematically represents this relationship through an equation: \[\frac{\sin(\theta_i)}{\sin(\theta_r)} = \frac{n_2}{n_1}\]where \(\theta_i\) is the angle of incidence, \(\theta_r\) the angle of refraction, and \(n_1\) and \(n_2\) represent the indices of refraction for the first and second medium, respectively. In vacuum, the index of refraction is 1, making this the base reference for light's speed. Snell’s Law not only allows us to calculate the degree of bending but also underpins the concept of the critical angle and total internal reflection—a critical effect in fiber optics and diamond brilliancy.
Polarization of Light
Polarization is a property of waves that describes the orientation of their oscillations. For light, which is an electromagnetic wave, polarization refers to the direction in which the electric field oscillates. Unpolarized light consists of waves vibrating in multiple planes, whereas polarized light vibrates in only one plane.

There are several methods for achieving light polarization, one of which involves reflection at Brewster's angle, named after Sir David Brewster. When light reflects at this angle, the reflected light is linearly polarized. Polarized sunglasses and certain camera filters take advantage of this property to reduce glare by blocking horizontally polarized light. Polarization is extensively exploited in optical applications ranging from photography to liquid crystal displays found in digital watches and most televisions.
Index of Refraction
The index of refraction, often simply called refractive index, is represented by the symbol \(n\) and is a dimensionless number expressing the optical density of a medium. It describes how much the speed of light in the medium is reduced compared to its speed in a vacuum, which is the ultimate speed limit for light.The refractive index for a vacuum is defined as 1. When light enters a medium like glass or water, its speed decreases, corresponding to a refractive index greater than 1. For instance, a typical glass might have an index of refraction around 1.5. This means light travels 1.5 times slower in glass than in a vacuum. The refractive index not only determines how much the path of light is bent—or refracted—when entering a different medium but also affects phenomena such as reflection and dispersion—the splitting of white light into a spectrum of colors.
Angle of Incidence and Refraction
Two critical angles when studying light's interaction with materials are the angle of incidence and the angle of refraction. The angle of incidence is the angle between an incoming light ray and an imaginary line called the 'normal', which is perpendicular to the surface at the point of contact. The angle of refraction, on the other hand, is the angle between the refracted ray and the normal.

The relationship between these two angles is governed by Snell's Law. It is essential to consider these angles while designing optical devices like lenses, as they affect the focusing properties of the lenses. The angle of incidence also plays a vital role in determining the level of reflection and refraction a ray of light will experience upon entering a new medium.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A dance hall is built without pillars and with a horizontal ceiling \(7.20 \mathrm{m}\) above the floor. A mirror is fastened flat against one section of the ceiling. Following an earthquake, the mirror is in place and unbroken. An engineer makes a quick check of whether the ceiling is sagging by directing a vertical beam of laser light up at the mirror and observing its reflection on the floor. (a) Show that if the mirror has rotated to make an angle \(\phi\) with the horizontal, the normal to the mirror makes an angle \(\phi\) with the vertical. (b) Show that the reflected laser light makes an angle \(2 \phi\) with the vertical. (c) If the reflected laser light makes a spot on the floor \(1.40 \mathrm{cm}\) away from the point vertically below the laser, find the angle \(\phi\).

A light ray initially in water enters a transparent substance at an angle of incidence of \(37.0^{\circ},\) and the transmitted ray is refracted at an angle of \(25.0^{\circ} .\) Calculate the speed of light in the transparent substance.

Compare this problem with the preceding problem. A plane sound wave in air at \(20^{\circ} \mathrm{C},\) with wavelength \(589 \mathrm{mm},\) is incident on a smooth surface of water at \(25^{\circ} \mathrm{C},\) at an angle of incidence of \(3.50^{\circ} .\) Determine the angle of refraction for the sound wave and the wavelength of the sound in water..

A prism that has an apex angle of \(50.0^{\circ}\) is made of cubic zirconia, with \(n=2.20 .\) What is its angle of minimum deviation?

For \(589-\) nm light, calculate the critical angle for the following materials surrounded by air: (a) diamond, (b) flint glass, and (c) ice.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.