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Two coils are close to each other. The first coil carries a timevarying current given by \(I(t)=(5.00 \mathrm{A}) e^{-0.0250 t} \sin (377 t)\) At \(t=0.800 \mathrm{s},\) the emf measured across the second coil is \(-3.20 \mathrm{V} .\) What is the mutual inductance of the coils?

Short Answer

Expert verified
To find the mutual inductance, you need to find the rate of change of the current in the first coil at the specified time, and then substitute this value along with the given emf value into Faraday's law. After rearranging and substituting these values into Faraday's law, the mutual inductance can be solved. Note the final calculation of mutual inductance would require the specific derivative of the given current function.

Step by step solution

01

Identify Relevant Information

We know that Faraday's law of induction describes how a time varying magnetic field can induce an electromotive force (emf) in a circuit. Here, it's given that the emf across the second coil at the time \(t = 0.800 s\) is \(-3.20 V\). The current that flows through the first coil is given by the equation \(I(t) = 5.00A * e^{-0.025t} * \sin(377t)\). We need to find the rate of change of this current at \(t = 0.800 s\). Also identify that Faraday's law of electromagnetic induction is given by \(-M * dI/dt = emf\), where M is the mutual inductance we are trying to find.
02

Calculate the derivative of current with respect to time

The rate of change of the current with respect to time can be found by calculating the derivative of the current function. The derivative of the current \(dI/dt\) at \(t = 0.800 s\) will be \(dI/dt = \frac{d}{dt} [5.00A e^{-0.025t} \sin(377t)]\). Calculating this derivative for \(t = 0.800 s\) will give us the rate of change of the current at the specified time.
03

Calculate Mutual Inductance

Now that we have the rate of change of the current at \(t = 0.800 s\) we can substitute this along with the given emf value into Faraday's law and solve for the mutual inductance \(M\). This gives us the equation \(-M * dI/dt = emf\), which can be rearranged to give \(M = - emf / (dI/dt)\). By substituting the known values into this expression, we can solve for the mutual inductance \(M\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Faraday's Law of Induction
Faraday's Law of Induction is a fundamental principle that lies at the heart of electromagnetic theory. It describes how a changing magnetic field can induce an electromotive force (emf) in a circuit. This is the basic operation principle behind many electrical devices like transformers and generators. The law is mathematically expressed as \(-\text{emf} = \frac{d\Phi_B}{dt}\) where \(\Phi_B\) is the magnetic flux. In simpler terms, whenever there’s a change in the magnetic environment of a coil, it causes voltage, or emf, to be generated.

In practical applications, Faraday's law allows us to calculate the induced emf from the rate of change of current linked to the coil. This exercise shows us how the emf across a second coil is related to the changing current in the first coil. By understanding this relationship, we're able to explore how energy is transferred through induction.
Time-Varying Current
Time-varying current is an electrical current that changes its value over time. It is often represented mathematically as a function of time, such as \(I(t) = 5.00A \cdot e^{-0.025t} \cdot \sin(377t)\). This kind of current is crucial in systems like AC circuits, where the current oscillates rather than remaining constant.

In the given exercise, the current in the first coil is not static. Instead, it’s described by an exponential sine function that varies with time. This variation is what causes changes in the magnetic field around the coil, which, according to Faraday's Law, induces an emf in the second coil. By differentiating this time-varying current, we can find its rate of change at a specific moment, which, in this exercise, is critical for determining the mutual inductance.
Electromotive Force (emf)
Electromotive Force, or emf, is the potential difference generated by a source of electrical energy such as a battery or dynamic movements within a magnetic field. In this exercise's context, emf is seen in the second coil as a result of the current change in the first coil. It is not a force at all but rather a voltage that can cause electric current to flow.

Using Faraday’s law, the measured emf of \(-3.20\, \text{V}\) in the second coil reflects the impact of the time-varying current in the first coil. This induced emf is crucial for computing the mutual inductance. To do so, we apply the relation \(\text{emf} = -M \cdot \frac{dI}{dt}\), demonstrating how mutual inductance can be derived from observed values of \(\text{emf}\) and the current’s rate of change. Thus, understanding emf is essential to predict and harness the influence of magnetic fields in electrical engineering.

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Most popular questions from this chapter

An inductor that has an inductance of \(15.0 \mathrm{H}\) and a resistance of \(30.0 \Omega\) is connected across a \(100-\mathrm{V}\) battery. What is the rate of increase of the current (a) at \(t=0\) and (b) at \(t=1.50 \mathrm{s} ?\)

A solenoid has 120 turns uniformly wrapped around a wooden core, which has a diameter of \(10.0 \mathrm{mm}\) and a length of \(9.00 \mathrm{cm} .\) (a) Calculate the inductance of the solenoid. (b) What If? The wooden core is replaced with a soft iron rod that has the same dimensions, but a magnetic permeability \(\mu_{m}=800 \mu_{0} .\) What is the new inductance?

The energy of an \(R L C\) circuit decreases by \(1.00 \%\) during each oscillation when \(R=2.00 \Omega .\) If this resistance is removed, the resulting \(L C\) circuit oscillates at a frequency of \(1.00 \mathrm{kHz}\). Find the values of the inductance and the capacitance.

A fixed inductance \(L=1.05 \mu \mathrm{H}\) is used in series with a variable capacitor in the tuning section of a radiotelephone on a ship. What capacitance tunes the circuit to the signal from a transmitter broadcasting at \(6.30 \mathrm{MHz} ?\)

(a) A flat circular coil does not really produce a uniform magnetic field in the area it encloses, but estimate the selfinductance of a flat, compact circular coil, with radius \(R\) and \(N\) turns, by assuming that the field at its center is uniform over its area. (b) A circuit on a laboratory table consists of a 1.5 -volt battery, a \(270-\Omega\) resistor, a switch, and three 30 -cm-long patch cords connecting them. Suppose the circuit is arranged to be circular. Think of it as a flat coil with one turn. Compute the order of magnitude of its self-inductance and (c) of the time constant describing how fast the current increases when you close the switch.

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