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Vector A has a magnitude of 8.00 units and makes an angle of \(45.0^{\circ}\) with the positive \(x\) axis. Vector \(\mathbf{B}\) also has a magnitude of 8.00 units and is directed along the negative x axis. Using graphical methods, find (a) the vector sum \(\mathbf{A}+\mathbf{B}\) and \((\mathbf{b})\) the vector difference \(\mathbf{A}-\mathbf{B}\)

Short Answer

Expert verified
The vector sum A+B is 6.13 units at 112.9 degrees and the vector difference A-B is 14.79 units at 22.4 degrees.

Step by step solution

01

Convert vector A into Cartesian coordinates

The x and y components of vector A can be represented by \(A_x=A\cos(\theta)\) and \(A_y=A\sin(\theta)\). Plugging in the given magnitude (8.00) and angle (45 degrees), we get: \(A_x=8.00\cos(45.0^{\circ})=5.66\) units and \(A_y=8.00\sin(45.0^{\circ})=5.66\) units.
02

Convert vector B into Cartesian coordinates

Since vector B is directed along the negative x-axis with magnitude 8.00 units, the x component is -8.00 units, and the y component is 0.
03

Compute vector A + B and A - B

The vector sum and difference can be calculated by adding or subtracting the respective components of the vectors. For A + B: \(AB_x=A_x + B_x = 5.66-8.00=-2.34\) units, \(AB_y=A_y + B_y = 5.66+0=5.66\) units. For A - B: \(AB_x=A_x - B_x = 5.66-(-8.00)=13.66\) units, \(AB_y=A_y - B_y = 5.66-0=5.66\) units.
04

Find Magnitude and Direction for A + B and A - B

For A + B: Magnitude \(\sqrt{(-2.34)^2+(5.66)^2}=6.13\) units, Direction \(\tan^{-1}(\frac{5.66}{-2.34})=112.9^{\circ}\). For A - B: Magnitude \(\sqrt{(13.66)^2+(5.66)^2}=14.79\) units, Direction \(\tan^{-1}(\frac{5.66}{13.66})=22.4^{\circ}\).
05

Write the final answer

The vector sum A+B has magnitude 6.13 units and direction 112.9 degrees. The vector difference A-B has magnitude 14.79 units and direction 22.4 degrees.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Vector Addition
Vector addition is the process of combining two or more vectors to get another vector. In essence, it's about taking the sum of their corresponding components.

When dealing with vectors in two dimensions, each has an x-component and a y-component. For example, to find the vector sum \(\mathbf{A} + \mathbf{B}\), we start by adding their individual x-components and y-components together:
  • If \(A_x\) and \(B_x\) are the x-components of vectors \(\mathbf{A}\) and \(\mathbf{B}\), the x-component of the resulting vector is given by \(A_x + B_x\).
  • Similarly, the y-component is \(A_y + B_y\).
After calculating these components, the magnitude and direction of the resultant vector are found using the Pythagorean theorem and trigonometric functions respectively:
  • For magnitude: \(\sqrt{(AB_x)^2 + (AB_y)^2}\)
  • For direction: \(\tan^{-1}(\frac{AB_y}{AB_x})\)
Understanding vector addition is crucial in physics, as it's used to describe forces, velocities, and other vector quantities. It also plays a significant role in computer graphics, navigation, and mechanical engineering.
Vector Subtraction
Vector subtraction is similar to vector addition, but instead of adding, you subtract the components of one vector from another. This process allows us to determine a vector's change or difference in position.

To perform vector subtraction, let's consider vectors \(\mathbf{A}\) and \(\mathbf{B}\). We find the difference, \(\mathbf{A} - \mathbf{B}\), by:
  • Subtracting the x-components: \(A_x - B_x\)
  • Subtracting the y-components: \(A_y - B_y\)
The resulting components give a new vector which represents the direction and magnitude of change:
  • Magnitude: \(\sqrt{(AB_x)^2 + (AB_y)^2}\)
  • Direction: \(\tan^{-1}(\frac{AB_y}{AB_x})\)
The logic of vector subtraction is used extensively in physics to find relative velocities or the resultant force when two forces act in opposite directions. It's also vital in navigation, computer simulations, and robotics.
Cartesian Coordinates
Cartesian coordinates allow us to locate vector positions in a plane using an ordered pair \((x, y)\). This system facilitates the representation and manipulation of vectors by breaking them down into their horizontal (x) and vertical (y) components.

In this coordinate system:
  • A vector is expressed as \((A_x, A_y)\), where \(A_x\) and \(A_y\) are the projections onto the x and y axes.
  • The position and calculation of vectors become straightforward by using these components.
When converting a vector given in polar form (magnitude and angle) to Cartesian coordinates:
  • The x-component \(A_x\) is found using \(A \cos(\theta)\), where \(\theta\) is the angle measured from the positive x-axis.
  • The y-component \(A_y\) is \(A \sin(\theta)\).
Using Cartesian coordinates simplifies many operations we perform with vectors, especially in computational geometry, engineering, and physics. They are a fundamental tool in calculating displacements, forces, and many other vector-related quantities.

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Most popular questions from this chapter

A surveyor measures the distance across a straight river by the following method: starting directly across from a tree on the opposite bank, she walks \(100 \mathrm{m}\) along the riverbank to cstablish a basclinc. Then she sights across to the tree. The angle from her bascline to the tree is \(35.0^{\circ} .\) How wide is the river?

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A map suggests that Atlanta is 730 miles in a direction of \(5.00^{\circ}\) north of east from Dallas. The same map shows that Chicago is 560 miles in a direction of \(21.0^{\circ}\) west of north from Atlanta. Modeling the Earth as flat, use this information to find the displacement from Dallas to Chicago.

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