/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 45 A \(10.0-\mathrm{V}\) battery is... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A \(10.0-\mathrm{V}\) battery is connected to a \(120-\Omega\) resistor. Ignoring the internal resistance of the battery, calculate the power delivered to the resistor.

Short Answer

Expert verified
The power delivered to the resistor is \(0.833\) watts.

Step by step solution

01

Apply Ohm's Law

Ohm's law states that the current \(I\) in a circuit is directly proportional to the voltage \(V\) and inversely proportional to the resistance \(R\). Mathematically this is represented as \(I = \frac{V}{R}\). Given in the problem is \(V = 10 V\) and \(R = 120 \Omega\). Substituting these values into the formula, the current is calculated as \(I = \frac{10}{120} = 0.0833\) amperes.
02

Calculate Power

The power \(P\) in an electrical circuit can be found using the formula \(P = VI\), where \(V\) is the voltage and \(I\) is the current. Substituting the given value of \(V = 10 V\) and the calculated current \(I = 0.0833 A\) into this formula, we get \$P = 10 \times 0.0833 = 0.833\) watts.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electrical Circuits
An electrical circuit is essentially a loop through which electricity flows. It comprises a power source such as a battery, conductive wires, and components like resistors that control the flow of electricity. The fundamental purpose of an electrical circuit is to provide a controlled environment for electricity to perform work, such as lighting a bulb or powering a device.

Understanding electrical circuits is crucial because it forms the basis of electronics. To analyze a circuit's behavior, we can use various physical laws and mathematical equations which predict how the circuit will respond to different changes, whether it's altering the resistance or the power source. This sets the stage for troubleshooting and optimizing circuit designs for various applications.
Ohm's Law
Ohm's Law is a fundamental principle in the field of electronics and electrical engineering that describes the relationship between voltage, current, and resistance in an electrical circuit. It states that the current flowing through a conductor between two points is directly proportional to the voltage across the two points and inversely proportional to the resistance between them.

Mathematically, Ohm's Law is expressed by the equation: \( I = \frac{V}{R} \), where \(I\) is the current in amperes (A), \(V\) is the voltage in volts (V), and \(R\) is the resistance in ohms (\(\Omega\)). This formula allows us to calculate any one of the three variables if the other two are known, enabling us to predict the behavior of electrical components and systems.
Power in Electrical Circuits
Power in electrical circuits is a measure of how much work is being done or how much energy is being used per unit of time. The unit used to measure electrical power is the watt (W). It's important to understand how power relates to electrical devices since it dictates the energy consumption and efficiency of those devices.

The power equation in the context of electrical circuits is: \( P = VI \), where \(P\) is power in watts, \(V\) is voltage in volts, and \(I\) is current in amperes. This relationship reveals that power can be increased either by raising the voltage or the current. However, it is critical to note that increasing either can lead to more heat in the circuit, which needs to be managed properly to avoid damage.
Resistance in Electrical Circuits
Resistance in electrical circuits is a measure of the opposition to current flow within the circuit. Resistance is measured in ohms (\(\Omega\)), named after Georg Ohm, who formulated Ohm's Law. The resistance of an electrical conduit affects how much current will flow for a given voltage.

Various factors can influence resistance, including the material's intrinsic resistivity, temperature, and physical dimensions (length and cross-sectional area). For example, metals like copper and aluminum have low resistance and are commonly used for wiring. High resistance leads to less current flow and can be utilized in components like resistors to manage and regulate the flow of electricity within a circuit.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

We estimate that 270 million plug-in electric clocks are in the United States, approximately one clock for each person. The clocks convert energy at the average rate 2.50 W. To supply this energy, how many metric tons of coal are burned per hour in coal-fired electric generating plants that are, on average, \(25.0 \%\) efficient? The heat of combustion for coal is \(33.0 \mathrm{M} \mathrm{J} / \mathrm{kg}\).

Suppose that a voltage surge produces \(140 \mathrm{V}\) for a moment. By what percentage does the power output of a \(120-\mathrm{V}, 100-\mathrm{W}\) lightbulb increase? Assume that its resistance does not change.

A Van de Graall generator produces a beam of \(2.00-\mathrm{MeV}\) deuterons, which are heavy hydrogen nuclei containing a proton and a neutron. (a) If the beam current is \(10.0 \mu \mathrm{A}\) how far apart are the deuterons? (b) Is the electric force of repulsion among them a significant factor in beam stability? Explain.

A high-voltage transmission line carries \(1000 \mathrm{A}\) starting at \(700 \mathrm{kV}\) for a distance of \(100 \mathrm{mi}\). If the resistance in the wire is \(0.500 \Omega / \mathrm{mi},\) what is the power loss due to resistive losses?

A straight cylindrical wire lying along the \(x\) axis has a length \(L\) and a diameter \(d\). It is made of a material that obeys Ohm's law with a resistivity \(\rho .\) Assume that potential \(V\) is maintained at \(x=0,\) and that the potential is zero at \(x=L .\) In terms of \(L, d, V, \rho,\) and physical constants, derive expressions for (a) the electric field in the wire, (b) the resistance of the wire, (c) the electric current in the wire, and (d) the current density in the wire. Express vectors in vector notation. (e) Prove that \(\mathbf{E}=\rho \mathbf{J}\).

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.