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Two small silver spheres, each with a mass of \(10.0 \mathrm{g},\) are separated by \(1.00 \mathrm{m} .\) Calculate the fraction of the electrons in one sphere that must be transferred to the other in order to produce an attractive force of \(1.00 \times 10^{4} \mathrm{N}\) (about 1 ton) between the spheres. (The number of electrons per atom of silver is \(47,\) and the number of atoms per gram is Avogadro's number divided by the molar mass of silver, \(107.87 \mathrm{g} / \mathrm{mol} .\) )

Short Answer

Expert verified
The fraction of electrons that must be transferred from one sphere to the other is \( 2.64 * 10^{-11} \) or approximately \( 1/\(3.78 * 10^{10}\) \).

Step by step solution

01

Use Coulomb's Law

Coulomb’s law formula gives the interaction force between two charges. Given are the force \( F = 1.00 * 10^4 N \), and the separation distance \( r = 1 m \). Considering \( k = 9.00 * 10^9 N * m^2/C^2 \), the formula is rearranged to calculate the charge.
02

Calculate the Charge

Rearranging \( F = k * |Q1 * Q2| / r^2 \) to calculate the charge results in \( |Q1 * Q2| = F * r^2 / k \). After plugging the values in, it is found that \( Q1 * Q2 =1.11 * 10^{-15} C^2 \). As \( Q1 = Q2 \), \( Q=e = 1.60*10^{-19} C \) can be defined.
03

Calculate the Number of Transferred Electrons

To find the number of transferred electrons, solve \( Q = n * e \) for \( n \), obtaining \( n = Q/e \). This calculates the number of electrons transferred, finding approximately \( n = 6.94 * 10^{12} \) transferred electrons.
04

Calculate the initial number of Electrons

The number of electrons is obtained approximating Avogadro's number \( N_a = 6.0221 * 10^{23} \) over the molar mass of silver \( 107.87 g/mol \), multiplied by the mass \( m = 10.0 g \) of the sphere and the number of electrons per atom, here \( 47 \). This results in approximately \( n_i = 2.63 * 10^{23} \) initial electrons.
05

Calculate the Fraction of Transferred Electrons

The final step is to find the fraction of transferred electrons. By dividing the number of transferred electrons by the total number in the sphere: \( Fraction = n/n_i \). The fraction resulted is about \( 2.64 * 10^{-11} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electric Charge
In physics, electric charge is a fundamental property of certain subatomic particles, which gives rise to and interacts with electromagnetic forces.
It comes in two types: positive and negative. The most common carriers of electric charge are electrons (negative charge) and protons (positive charge).
Coulomb's Law helps us calculate the force between charged objects. According to this law, like charges repel each other, while opposite charges attract.
The formula is expressed as \[ F = \frac{k \cdot |Q_1 \cdot Q_2|}{r^2} \]where:
  • \( F \) is the magnitude of the force between the charges,
  • \( k \) is Coulomb’s constant \( (9.00 \times 10^9 \, N \cdot m^2/C^2) \),
  • \( Q_1 \) and \( Q_2 \) are the amounts of charge, and
  • \( r \) is the distance between the centers of the two charges.
This formula implies that the force increases with larger charges and decreases with greater distance between them.
Electron Transfer
Electron transfer is a process where electrons are moved from one atom or molecule to another. This movement can change the electrical neutrality of an object, thereby creating charged objects.
In the context of the silver spheres exercise, transferring electrons from one sphere to the other results in creating opposite charges on both spheres, which leads to an attractive electrostatic force as per Coulomb's Law.
The precise number of electrons that need to be transferred to achieve a specific force can be calculated using the charge of a single electron, approximately \( 1.60 \times 10^{-19} \, C \) (coulombs).
To find how many electrons are transferred, we solve for \( n \) using the formula \[ Q = n \cdot e \]where:
  • \( Q \) is the resulting charge on each sphere,
  • \( n \) is the number of electrons transferred, and
  • \( e \) represents the elementary charge of an electron.
In problems involving large objects, even the transfer of a tiny fraction of available electrons can result in a significant force.
Silver Atom
Silver is a metallic element, represented by the symbol Ag, and is known for its electrical conductivity.
Each silver atom contains 47 electrons, which make up its electron cloud, and these electrons play a crucial role in electrical conduction and charge transfer processes.
To calculate the number of electrons in a given mass of a silver object, like the silver sphere in the exercise, we need to consider:
  • The atomic composition of silver, which includes 47 electrons per atom,
  • The molar mass of silver, which is approximately \( 107.87 \, g/mol \), and
  • Avogadro's number \( (6.0221 \times 10^{23} \, atoms/mol) \), which allows us to find the number of atoms in a mole.
By using these values and the given mass of the silver object, we determine the total number of electrons present.
This is essential for solving problems that require understanding how altering a small number of electrons affects electrical interactions.

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Most popular questions from this chapter

(a) Find to three significant digits the charge and the mass of an ionized hydrogen atom, represented as \(\mathrm{H}^{+}\). Suggestion: Begin by looking up the mass of a neutral atom on the periodic table of the elements. (b) Find the charge and the mass of \(\mathrm{Na}^{+},\) a singly ionized sodium atom. (c) Find the charge and the average mass of a chloride ion Cl \(^{-}\) that joins with the Na \(^{+}\) to make one molecule of table salt. (d) Find the charge and the mass of \(\mathrm{Ca}^{++}=\mathrm{Ca}^{2+},\) a doubly ionized calcium atom. (e) You can model the center of an ammonia molecule as an \(\mathrm{N}^{3-}\) ion. Find its charge and mass. (f) The plasma in a hot star contains quadruply ionized nitrogen atoms, \(\mathbf{N}^{4+} .\) Find their charge and mass. (g) Find the charge and the mass of the nucleus of a nitrogen atom. (h) Find the charge and the mass of the molecular ion \(\mathrm{H}_{2} \mathrm{O}^{-}\)

Two identical conducting small spheres are placed with their centers \(0.300 \mathrm{m}\) apart. One is given a charge of \(12.0 \mathrm{nC}\) and the other a charge of \(-18.0 \mathrm{nC} .\) (a) Find the electric force exerted by one sphere on the other. (b) What If? The spheres are connected by a conducting wire. Find the electric force between the two after they have come to equilibrium.

A line of charge with uniform density \(35.0 \mathrm{nC} / \mathrm{m}\) lies along the line \(y=-15.0 \mathrm{cm},\) between the points with coordinates \(x=0\) and \(x=40.0 \mathrm{cm} .\) Find the electric field it creates at the origin.

A rod \(14.0 \mathrm{cm}\) long is uniformly charged and has a total charge of \(-22.0 \mu \mathrm{C} .\) Determine the magnitude and direction of the electric field along the axis of the rod at a point \(36.0 \mathrm{cm}\) from its center.

The electric field along the axis of a uniformly charged disk of radius \(R\) and total charge \(Q\) was calculated in Example \(23.9 .\) Show that the electric field at distances \(x\) that are large compared with \(R\) approaches that of a point charge \(Q=\sigma \pi R^{2} .\) (Suggestion: First show that \(x /\left(x^{2}+R^{2}\right)^{1 / 2}=\) \(\left(1+R^{2} / x^{2}\right)^{-1 / 2}\) and use the binomial expansion \(\left.(1+\delta)^{n} \approx 1+n \delta \text { when } \delta<<1 .\right)\)

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