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In an ultra-high-vacuum system, the pressure is measured to be \(1.00 \times 10^{-10}\) torr (where 1 torr \(=133 \mathrm{Pa}\) ). Assuming the molecular diameter is \(3.00 \times 10^{-10} \mathrm{m},\) the average molecular speed is \(500 \mathrm{m} / \mathrm{s}\), and the temperature is \(300 \mathrm{K}\) find (a) the number of molecules in a volume of \(1.00 \mathrm{m}^{3}\) (b) the mean free path of the molecules, and (c) the collision frequency.

Short Answer

Expert verified
The (a) number of molecules in a volume of \(1.00 m^3\) is \(3.01 \times 10^{20} molecules\), (b) the mean free path of the molecules is \(13.4 m\), and (c) the collision frequency is \(1.26 \times 10^{6} s^{-1}\)

Step by step solution

01

Convert pressure units

First, convert the pressure from torr to Pascal (Pa). The conversion factor is \(1 torr = 133 Pa\). Therefore, the pressure \(P\) in Pascal is \(P = 1.00 \times 10^{-10} torr \times 133 Pa/torr = 1.33 \times 10^{-8} Pa\)
02

Use the ideal gas law to find the number of molecules

The ideal gas law is \(PV = nRT\), where \(P\) is pressure, \(V\) is volume, \(n\) is the number of moles, \(R\) is the universal gas constant, and \(T\) is temperature. Rearrange the equation to solve for \(n (number of moles) = \frac{PV}{RT}\). To find the number of molecules I need to multiply \(n\) by Avogadro's number (\(6.022 \times 10^{23} mol^{-1}\)). Therefore, the number of molecules \(N = \frac{PV}{RT} \times 6.022 \times 10^{23} mol^{-1} = \frac{1.33 \times 10^{-8} Pa \times 1.00 m^3}{8.314 JK^{-1}mol^{-1} \times 300 K} \times 6.022 \times 10^{23} mol^{-1} = 3.01 \times 10^{20} molecules\)
03

Find the mean free path

The mean free path \(l\) can be given by formula \(l = \frac{kT}{\sqrt{2} \pi d^2 P}\), where \(k\) is Boltzmann constant (\(1.38 \times 10^{-23} J/K\)), \(T\) is the temperature, \(d\) is the molecular diameter, and \(P\) is the pressure. So, the mean free path \(l = \frac{1.38 \times 10^{-23} J/K \times 300 K}{\sqrt{2} \pi (3.00 \times 10^{-10} m)^2 \times 1.33 \times 10^{-8} Pa} = 13.4 m\)
04

Calculate the collision frequency

Collision frequency \(z\) can be given by \(z = \frac{1}{\sqrt{2} \pi d^2 v l}\), where \(v\) is the average molecular speed and \(l\) is the mean free path. So, the collision frequency \(z = \frac{1}{\sqrt{2} \pi (3.00 \times 10^{-10} m)^2 \times 500ms^{-1} \times 13.4 m} = 1.26 \times 10^{6} s^{-1}\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ideal Gas Law
The ideal gas law is a fundamental principle in physics that relates the pressure, volume, temperature, and number of molecules of a gas. In the equation form, it is expressed as:\[ PV = nRT \]
where:\[ P \]stands for the pressure of the gas,\[ V \]is its volume,\[ n \]is the number of moles,\[ R \]is the universal gas constant, and\[ T \]is the absolute temperature.
To use the ideal gas law for calculations, one must have a good understanding of these variables and the units they are measured in. For instance, pressure can be measured in pascals or torr, with temperature in kelvin, volume in cubic meters, and the constant R has the value of \(8.314 J\text{(K·mol)}^{-1}\). Converting between units, like from torr to pascal, is essential for correct application. Learning the ideal gas law allows one to predict the behavior of a gas under different conditions, which is crucial in fields like chemistry and environmental science.
Mean Free Path
The mean free path refers to the average distance a gas molecule travels between collisions with other molecules. This measurement is pivotal when studying the behavior of gases at various pressures, like in an ultra-high-vacuum system.

The mean free path (\( l \)) can be described with the formula:\[ l = \frac{kT}{\frac{\text{(2)}^{1/2} \times \text{(Ï€)} \times d^2 \times P}} \]
where:\[ k \]is Boltzmann's constant,\[ T \]is the temperature in kelvin,\[ P \]is the pressure, and\[ d \]is the molecular diameter.
Knowing the mean free path aids in understanding how gas molecules interact in various environments, which is especially important in fields like vacuum technology and aerosol physics.
Collision Frequency
Collision frequency describes the number of times a gas molecule collides with other molecules in a given time frame. It is dependent on factors such as temperature, molecular speed, and mean free path.

The collision frequency (\( z \)), for a molecule moving at an average speed (\( v \)), is calculated using:\[ z = \frac{1}{\text{(2)}^{1/2} \times \text{(Ï€)} \times d^2 \times v \times l} \]
where:\[ d \]is the molecular diameter and\[ l \]is the mean free path.
Understanding collision frequency can provide insights into reaction rates in gaseous systems and the efficiency of gas-based devices.
Pressure Conversion
Pressure conversion is an essential process in physics, allowing one to translate pressure units from one system to another. Common units include pascals, bar, atm, and torr.

To convert from torr to pascal:\[ 1 \text{ torr} = 133 \text{ Pa} \]
Therefore, for an ultra-high-vacuum system measured in torr, it is necessary to multiply by 133 to obtain the value in pascals. Accurate pressure conversions are crucial for precision in scientific calculations and experimental setups.
Molecular Dynamics
Molecular dynamics is a simulation method in physics used to study the behavior of atoms and molecules in time. It allows scientists to predict the motion of these particles by solving Newton's equations of motion for systems with a large number of interacting particles.

Molecular dynamics is important for understanding the physical properties of matter, such as diffusion, thermal conductivity, and phase transitions. These simulations require details such as molecular speed and interactions, which can be influenced by conditions described in the ideal gas law.
Avogadro's Number
Avogadro's number is a key constant in chemistry, representing the number of constituent particles, typically atoms or molecules, contained in one mole of substance. Its value is approximately:\[ 6.022 \times 10^{23} \text{ molecules/mol} \]
This number is used to convert between the number of moles and the number of molecules. Understanding Avogadro's number is critical for performing calculations involving the ideal gas law and for interpreting chemical reactions at the molecular level.
Boltzmann Constant
The Boltzmann constant (\( k \)) plays a vital role in statistical mechanics and thermodynamics, linking the macroscopic and microscopic worlds. It relates the average kinetic energy of particles in a gas with the temperature of the gas and is given by:\[ k = 1.38 \times 10^{-23} \text{ J/K} \]
The Boltzmann constant appears in many fundamental equations, including those used to calculate the mean free path and thermal motion of molecules. Its value determines the energy scale at a molecular level for a given temperature.

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Most popular questions from this chapter

Fifteen identical particles have various speeds: one has a speed of \(2.00 \mathrm{m} / \mathrm{s} ;\) two have speeds of \(3.00 \mathrm{m} / \mathrm{s} ;\) three have speeds of \(5.00 \mathrm{m} / \mathrm{s} ;\) four have speeds of \(7.00 \mathrm{m} / \mathrm{s}\) three have speeds of \(9.00 \mathrm{m} / \mathrm{s} ;\) and two have speeds of \(12.0 \mathrm{m} / \mathrm{s} .\) Find (a) the average speed, (b) the rms speed, and (c) the most probable speed of these particles.

An incandescent lightbulb contains a volume \(V\) of argon at pressure \(P_{i} .\) The bulb is switched on and constant power \(\mathscr{P}\) is transferred to the argon for a time interval \(\Delta t\) (a) Show that the pressure \(P\) in the bulb at the end of this process is \(P_{f}=P_{i}\left[1+(\mathscr{P} \Delta t R) /\left(P_{i} V C_{V}\right)\right] .\) (b) Find the pressure in a spherical light bulb \(10.0 \mathrm{cm}\) in diameter \(4.00 \mathrm{s}\) after it is switched on, given that it has initial pressure 1.00 atm and that 3.60 W of power is transferred to the gas.

A sealed cubical container \(20.0 \mathrm{cm}\) on a side contains three times Avogadro's number of molecules at a temperature of \(20.0^{\circ} \mathrm{C}\). Find the force exerted by the gas on one of the walls of the container.

A diatomic ideal gas \((\gamma=1.40)\) confined to a cylinder is put through a closed cycle. Initially the gas is at \(P_{i}, V_{i},\) and \(T_{i} .\) First, its pressure is tripled under constant volume. It then expands adiabatically to its original pressure and finally is compressed isobarically to its original volume. (a) Draw a PV diagram of this cycle. (b) Determine the volume at the end of the adiabatic expansion. Find (c) the temperature of the gas at the start of the adiabatic expansion and \((\mathrm{d})\) the temperature at the end of the cycle. (e) What was the net work done on the gas for this cycle?

A vertical cylinder with a heavy piston contains air at a temperature of \(300 \mathrm{K}\). The initial pressure is \(200 \mathrm{kPa},\) and the initial volume is \(0.350 \mathrm{m}^{3} .\) Take the molar mass of air as \(28.9 \mathrm{g} / \mathrm{mol}\) and assume that \(C_{V}=5 R / 2 .\) (a) Find the specific heat of air at constant volume in units of \(\mathrm{J} / \mathrm{kg} \cdot^{\circ} \mathrm{C}\) A vertical cylinder with a heavy piston contains air at a temperature of \(300 \mathrm{K}\). The initial pressure is \(200 \mathrm{kPa},\) and the initial volume is \(0.350 \mathrm{m}^{3} .\) Take the molar mass of air as \(28.9 \mathrm{g} / \mathrm{mol}\) and assume that \(C_{V}=5 R / 2 .\) (a) Find the specific heat of air at constant volume in units of \(\mathrm{J} / \mathrm{kg} \cdot^{\circ} \mathrm{C}\)

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