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A golf ball is released from rest from the top of a very tall building. Neglecting air resistance, calculate (a) the position and (b) the velocity of the ball after \(1.00,2.00,\) and \(3.00 \mathrm{s}\).

Short Answer

Expert verified
The ball falls the following distances: about 4.9 m, 19.6 m, and 44.1 m, and it's moving at the speeds: 9.8 m/s, 19.6 m/s, and 29.4 m/s after 1.00, 2.00, and 3.00 seconds, respectively.

Step by step solution

01

Identify Variables

Here are the variables in the problem: initial velocity (u) = 0 (since the ball is released from rest), time (t) = 1.00, 2.00, and 3.00 seconds, acceleration due to gravity (a) = \(-9.8 \mathrm{m/s^2}\) which is always constant and acts in the downward direction, final velocity (v), and distance (d).
02

Calculate Distance (position) at t = 1, 2, 3 seconds

Use the equation of motion that relates distance, initial velocity, time, and acceleration: \(d = ut + \frac{1}{2}at^2\). Since u = 0, the first term cancels out which gives: \(d = \frac{1}{2}at^2\). Plug in the times t = 1.00 s, 2.00 s, 3.00 s and a= \(-9.8 \mathrm{m/s^2}\) to get the distances corresponding to these times.
03

Calculate Velocity at t = 1, 2, 3 seconds

Use the equation of motion that relates velocity, initial velocity, acceleration, and time: \(v = u + at\). Here, u = 0, so v = at. Plug in the times t = 1.00, 2.00, 3.00 seconds and a= \(-9.8 \mathrm{m/s^2}\) to get the velocities corresponding to these times.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kinematics
Kinematics is the branch of physics that deals with the motion of objects without considering the forces that cause the motion. It's all about describing how things move—think position, velocity, and acceleration. When we talk about a golf ball being dropped from a building, as in the provided exercise, kinematics gives us the tools to predict where and how fast the ball will be at any given moment.

To do this, we use a series of kinematic equations that relate these quantities to each other. In the case of the golf ball, we are initially concerned with its position over time. Since the ball starts from rest, its initial velocity (commonly noted as 'u') is zero. Then, to figure out its position after 1, 2, and 3 seconds, we'd use the kinematic equation for displacement under constant acceleration, which, due to gravity, is present in our scenario.
Equations of Motion
The equations of motion are a set of formulas that provide a simple way of predicting the position and velocity of an object moving under constant acceleration. When an object, such as our golf ball, is dropped from a height, it accelerates downwards—thanks to gravity—at a constant rate. This allows us to apply these equations to predict the ball's future location and velocity.

Calculating Position

One such equation is used for computing the distance (or position) that the ball has fallen: \(d = ut + \frac{1}{2}at^2\). In this formula, 'd' represents distance, 'u' is the initial velocity, 'a' is the acceleration, and 't' is the time. Since the ball starts from rest ('u' being 0), the equation simplifies to just \(d = \frac{1}{2}at^2\). By plugging in the values, we'd get the ball's position at various times.

Calculating Velocity

Similarly, another equation gives us the final velocity ('v') after some time: \(v = u + at\). With the initial velocity being zero, the equation simplifies, and we can calculate how fast the ball is moving after 1, 2, and 3 seconds.

These equations are powerful as they allow us to make accurate predictions about an object's motion without knowing the forces involved—an essential skill in physics problem-solving.
Free Fall
Free fall is a specific type of motion that occurs when an object is only influenced by gravity. The key point about free fall is that it doesn't matter what the object is; everything falls at the same rate when air resistance is negligible. This is precisely the situation with our golf ball.

In this scenario, the golf ball undergoes free fall from the top of the building, and its acceleration 'a' is due to the force of gravity alone. Gravity pulls it downward at a constant acceleration of approximately \(-9.8 \mathrm{m/s^2}\), which is the value used in our equations of motion. This negative sign indicates the direction of the acceleration—towards the center of the Earth.

Understanding free fall is crucial because it not only simplifies the calculations by ensuring a constant acceleration but also provides a foundational concept that relates to other more complex physics scenarios. The idea that all objects in free fall (ignoring air resistance) experience the same gravitational pull regardless of their mass can sometimes seem unintuitive, but it's a cornerstone of classical physics.

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Most popular questions from this chapter

A baseball is hit so that it travels straight upward after being struck by the bat. A fan observes that it takes 3.00 s for the ball to reach its maximum height. Find (a) its initial velocity and (b) the height it reaches.

Setting a new world record in a \(100-\mathrm{m}\) race, Maggie and Judy cross the finish line in a dead heat, both taking \(10.2 \mathrm{s}\) Accelerating uniformly, Maggie took \(2.00 \mathrm{s}\) and \(\mathrm{Judy} 3.00 \mathrm{s}\) to attain maximum speed, which they maintained for the rest of the race. (a) What was the acceleration of each sprinter? (b) What were their respective maximum speeds? (c) Which sprinter was ahead at the \(6.00-\) s mark, and by how much?

A freely falling object requires \(1.50 \mathrm{s}\) to travel the last \(30.0 \mathrm{m}\) before it hits the ground. From what height above the ground did it fall?

An inquisitive physics student and mountain climber climbs a 50.0 -m cliff that overhangs a calm pool of water. He throws two stones vertically downward, \(1.00 \mathrm{s}\) apart, and observes that they cause a single splash. The first stone has an initial speed of \(2.00 \mathrm{m} / \mathrm{s} .\) (a) How long after release of the first stone do the two stones hit the water? (b) What initial velocity must the second stone have if they are to hit simultaneously? (c) What is the speed of each stone at the instant the two hit the water?

Draw motion diagrams for (a) an object moving to the right at constant speed, (b) an object moving to the right and speeding up at a constant rate, \((c)\) an object moving to the right and slowing down at a constant rate, (d) an object moving to the left and speeding up at a constant rate, and (e) an object moving to the left and slowing down at a constant rate. (f) How would your drawings change if the changes in speed were not uniform; that is, if the speed were not changing at a constant rate?

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