/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 20 A truck covers \(40.0 \mathrm{m}... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A truck covers \(40.0 \mathrm{m}\) in \(8.50 \mathrm{s}\) while smoothly slowing down to a final speed of \(2.80 \mathrm{m} / \mathrm{s} .\) (a) Find its original speed. (b) Find its acceleration.

Short Answer

Expert verified
The initial speed of the truck was \(2.167 m/s\) and the acceleration was \(-0.098 m/s^2\). The negative sign indicates deceleration.

Step by step solution

01

Identify the Given Information

We know that the truck covers a distance of \(40.0 \mathrm{m}\) in \(8.50 \mathrm{s}\) and slows down to a final speed of \(2.80 \mathrm{m} / \mathrm{s}\). In other words, we have \(d = 40.0 \mathrm{m}\), \(t = 8.50 \mathrm{s}\), and \(v_f = 2.80 \mathrm{m} / \mathrm{s}\).
02

Applying the Equation of Motion to Determine the Original Speed

We use the equation of motion \(d = v_i t + 0.5 a t^2\) to solve for the initial speed \(v_i\). But since we don't have the acceleration given or found yet, we can apply the other equation \(v_f = v_i + a t\) to find the initial speed. Since we want to find the initial speed for a decelerating body, the equation becomes \(v_f = v_i - a t\). But we can't employ this equation directly as we still do not have the acceleration. So we need to find that first.
03

Applying the Equation of Motion to Determine the Acceleration

We will use the equation \(v_f^2 = v_i^2 + 2ad\) to find the acceleration. Rearrange the equation to isolate \(a\) by the equation \[a = \frac{{v_f^2 - v_i^2}}{{2d}}\]. Since \(v_i\) is still unknown, this equation can be further manipulated to be \[a = \frac{{v_f^2 - (v_i^2 - 2ad)}}{2d}\], which simplifies to \[a = \frac{{v_f^2}}{2d}\]. Substituting the given values, we get \[a = \frac{{(2.8 m/s)^2}}{{2 \times 40 m}} = -0.098 m/s^2\]. The negative sign indicates deceleration.
04

Applying the Equation of Motion to Determine the Original Speed

Now that we have the acceleration, use it to calculate the initial speed \(v_i\) using the equation \(v_f = v_i - a t\). Rearrange it to find \(v_i\): \[v_i = v_f + at\]. Substituting the given values, we get \[v_i = 2.8 m/s + (-0.098 m/s^2)(8.5 s) = 2.167 m/s\].

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Equations of Motion
Kinematics, the branch of physics concerned with the motion of objects, often relies on equations of motion to describe and predict such movements. These equations allow us to calculate unknown properties of moving objects, such as initial speed or acceleration.

One of the key equations is:
  • \(d = v_i t + \frac{1}{2} a t^2\)
This formula calculates the distance an object travels, using its initial speed \(v_i\), acceleration \(a\), and time \(t\). Another important equation is:
  • \(v_f = v_i + a t\)
where \(v_f\) is the final speed. This helps when we need to find missing variables in uniformly accelerated motion.

To find acceleration or initial speed, we rearrange these formulas. For instance, if acceleration is unknown, we can derive it from the final speed equation by solving for \(a\). Similarly, to determine initial speed, we might rearrange the equations accordingly. These formulas are versatile tools for solving motion problems.
Initial Speed Calculation
The initial speed, \(v_i\), is the velocity at which an object begins its motion. It is a crucial parameter when analyzing an object's journey. Given the equations of motion, we can determine \(v_i\) when other components such as distance and time are known.

In our problem, the truck's initial speed needs to be calculated. We start with the equation \(v_f = v_i - a t\), since the object is decelerating. Rearranging this to find \(v_i\), we use:
  • \(v_i = v_f + a t\)
Knowing the final speed \(v_f\) and the calculated acceleration \(a\), we substitute these into the equation to find \(v_i\). This approach requires precise values for other variables like time and final velocity to ensure accurate results. This calculation forms the foundation for predicting the object's entire motion course.
Acceleration Determination
Determining acceleration \(a\) is essential in kinematics. It describes how quickly an object's speed changes over time. In physics problems involving motion, knowing the acceleration helps us predict future and past behavior of a moving object.

To calculate the truck's acceleration, we use the equation:
  • \(v_f^2 = v_i^2 + 2ad\)
Here, \(d\) indicates distance traveled. We rearrange to isolate \(a\):
  • \(a = \frac{{v_f^2 - v_i^2}}{{2d}}\)
This formula effectively calculates acceleration when initial speed \(v_i\) is not directly available, as in our exercise. The setup and solving of this equation require a clear understanding of the underlying physics principles.

Once we insert values for \(v_f\) and \(d\), it allows us to solve for \(a\). This computation is straightforward but critical, as it reveals whether the object is experiencing acceleration or deceleration.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A test rocket is fired vertically upward from a well. A catapult gives it an initial speed of \(80.0 \mathrm{m} / \mathrm{s}\) at ground level. Its engines then fire and it accelerates upward at \(4.00 \mathrm{m} / \mathrm{s}^{2}\) until it reaches an altitude of \(1000 \mathrm{m} .\) At that point its engines fail and the rocket goes into free fall, with an acceleration of \(-9.80 \mathrm{m} / \mathrm{s}^{2} .\) (a) How long is the rocket in motion above the ground? (b) What is its maximum altitude? (c) What is its velocity just before it collides with the Earth? (You will need to consider the motion while the engine is operating separate from the free-fall motion.)

A freely falling object requires \(1.50 \mathrm{s}\) to travel the last \(30.0 \mathrm{m}\) before it hits the ground. From what height above the ground did it fall?

A 745 i BMW car can brake to a stop in a distance of \(121 \mathrm{ft}\). from a speed of \(60.0 \mathrm{mi} / \mathrm{h} .\) To brake to a stop from a speed of \(80.0 \mathrm{mi} / \mathrm{h}\) requires a stopping distance of \(211 \mathrm{ft}\) What is the average braking acceleration for (a) \(60 \mathrm{mi} / \mathrm{h}\) to rest, (b) \(80 \mathrm{mi} / \mathrm{h}\) to rest, \((\mathrm{c}) 80 \mathrm{mi} / \mathrm{h}\) to \(60 \mathrm{mi} / \mathrm{h} ?\) Express the answers in \(\mathrm{mi} / \mathrm{h} / \mathrm{s}\) and in \(\mathrm{m} / \mathrm{s}^{2}\) .

Kathy Kool buys a sports car that can accelerate at the rate of \(4.90 \mathrm{m} / \mathrm{s}^{2} .\) She decides to test the car by racing with another speedster, Stan Speedy. Both start from rest, but experienced Stan leaves the starting line 1.00 s before Kathy. If Stan moves with a constant acceleration of \(3.50 \mathrm{m} / \mathrm{s}^{2}\) and Kathy maintains an acceleration of \(4.90 \mathrm{m} / \mathrm{s}^{2},\) find. (a) the time at which Kathy overtakes Stan, (b) the distance she travels before she catches him, and (c) the speeds of both cars at the instant she overtakes him.

A student throws a set of keys vertically upward to her sorority sister, who is in a window \(4.00 \mathrm{m}\) above. The keys are caught 1.50 s later by the sister's outstretched hand. (a) With what initial velocity were the keys thrown? (b) What was the velocity of the keys just before they were caught?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.