/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 48 A liquid with a coefficient of v... [FREE SOLUTION] | 91Ó°ÊÓ

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A liquid with a coefficient of volume expansion \(\beta\) just fills a spherical shell of volume \(V_{i}\) at a temperature of \(T_{i}\) (see Fig. \(P 19.47) .\) The shell is made of a material that has an average coefficient of linear expansion \(\alpha .\) The liquid is free to expand into an open capillary of area \(A\) projecting from the top of the sphere. (a) If the temperature increases by \(\Delta T,\) show that the liquid rises in the capillary by the amount \(\Delta h\) given by \(\Delta h=\left(V_{i} / A\right)(\beta-3 \alpha) \Delta T\). (b) For a typical system, such as a mercury thermometer, why is it a good approximation to neglect the expansion of the shell?

Short Answer

Expert verified
a) The height, \(\Delta h\), to which the liquid would rise in the capillary tube when the system is heated, is given by the formula \(\Delta h = (V_{i} / A)(\beta - 3\alpha) \Delta T\). b) The expansion of the shell is negligible because the coefficient of volume expansion of mercury is much larger than the coefficient of linear expansion of glass.

Step by step solution

01

Initial and Final Volumes of The Liquid

When the temperature rises, the liquid inside the shell will expand. The initial volume of the liquid is \(V_{i}\) and after a temperature increase of \(\Delta T\), its volume will become \(V_{i}(1 + \beta \Delta T)\). The volume expansion coefficient, \(\beta\), accounts for the relative change in volume per degree change in temperature.
02

Final Volume of The Shell

The shell itself will also expand due to the increase in temperature. Being a sphere, a three-dimensional object, the expansion of the shell can be described by the linear expansion coefficient, \(\alpha\), which results in increased radius of the shell. The final volume of the shell, to the first order of \(\Delta T\), would be \(V_{i} (1 + 3\alpha \Delta T)\). The '3' here is due to the three dimensions for the expansion of the sphere.
03

Volume Taken by The Liquid in The Capillary

With a temperature increase, the liquid expands more than the shell, causing the liquid to rise into the capillary. The volume of this liquid in the capillary tube is equal to the difference of the final volumes of the liquid and the shell. So, \( V_{capillary} = V_{i}(1 + \beta \Delta T) - V_{i}(1 + 3\alpha \Delta T) = V_{i} (\beta - 3\alpha) \Delta T \).
04

Height of The Liquid in The Capillary Tube

The volume of liquid in the capillary tube equals the area of the capillary tube, \(A\), times the height, \(\Delta h\), that the liquid rises in the capillary tube. Therefore, \( V_{capillary} = A \Delta h \). By equating the expressions for \( V_{capillary} \) from Steps 3 and 4, we can solve for \(\Delta h\), where \(\Delta h = (V_{i} / A)(\beta - 3\alpha) \Delta T \).
05

Neglecting The Expansion of The Shell

In a typical system like a mercury thermometer, the volume expansion coefficient of the liquid (mercury) is much larger than that of the glass shell (The value of \(\beta\) for mercury is much larger than the value of \(\alpha\) for glass). Therefore, the relative expansion of the liquid is much more compared to the relative expansion of the glass shell. That's why it's a good approximation to neglect the expansion of the shell.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Coefficient of Volume Expansion
The coefficient of volume expansion, denoted as \(\beta\), is a vital concept in understanding the behavior of liquids under temperature changes. Imagine filling a balloon with water and heating it up—what happens? The balloon swells as the water expands. This swelling is because liquids tend to increase in volume when heated. The coefficient of volume expansion quantifies this increase per degree change in temperature. It's the ratio of the change in volume to the original volume and the change in temperature, mathematically expressed as \(\beta = \frac{\Delta V}{V_0 \Delta T}\).

In practical applications, accurate knowledge of \(\beta\) is crucial for designing equipment that operates with temperature fluctuations, as it ensures proper functioning and safety. For instance, when creating a thermometer, the \(\beta\) of the liquid inside determines how much the liquid will rise or fall with temperature and hence how the scale should be calibrated.
Coefficient of Linear Expansion
On the flip side of volume expansion in liquids, the coefficient of linear expansion, symbolized by \(\alpha\), brings us to the realm of solids. This coefficient tells us how much a solid object will elongate or shorten when the temperature changes—think of how train tracks have small gaps to accommodate this stretching and contracting. Mathematically, \(\alpha\) is defined as the change in length per unit original length per degree of temperature change, which is given by \(\alpha = \frac{\Delta L}{L_0 \Delta T}\).

For isotropic materials (those with properties that are the same in all directions), linear expansion suffices to describe their thermal behavior. However, for anisotropic materials (those with directionally dependent properties), such as many crystals, expansion might be different along different axes. This distinction must be considered when designing structures or components that may be exposed to significant temperature variations.
Capillary Action
Capillary action, or capillarity, is a fascinating phenomenon where a liquid spontaneously rises or falls in a narrow tube, defying gravity. It might remind you of how a paper towel soaks up a spill. This action is the result of two key factors: cohesion and adhesion. Cohesion is the force of attraction between particles within the liquid, while adhesion is the attraction between the liquid and the walls of the capillary.

In a glass capillary filled with water, adhesion between the water and glass causes the water to climb up the sides of the tube. At the same time, cohesion tries to keep the water's surface flat. As a result of these competing forces, the water surface in the capillary will be curved or meniscated. For liquids like mercury, which have stronger cohesion than adhesion with glass, the liquid will depress rather than rise. Capillary action is vital in many natural processes, such as how plants draw water up from their roots, and technological applications like inkjet printing.
Thermal Expansion in Solids
Thermal expansion in solids is a physical property that causes materials to change their size or shape when subjected to changes in temperature. Similar to liquids, when most solids heat up, their atoms and molecules jostle more vigorously. This increased motion causes the solid to expand. However, the expansion of solids is usually less dramatic than that of liquids because the particles in a solid are more closely bound together. Nonetheless, this phenomenon must be accounted for in construction, manufacturing, and technology design.

Specialty materials and compounds, such as bi-metallic strips in thermostats or expansion joints in bridges, specifically exploit thermal expansion properties to fulfill precise functions. For example, in the context of the original exercise, the spherical shell's expansion could potentially be neglected because its coefficient of linear expansion \(\alpha\) is much smaller than the coefficient of volume expansion \(\beta\) of the liquid, leading to a tiny change in the shell's overall volume compared to the liquid's significant expansion.

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Most popular questions from this chapter

Review problem. A perfectly plane house roof makes an angle \(\theta\) with the horizontal. When its temperature changes, between \(T_{c}\) before dawn each day to \(T_{h}\) in the middle of each afternoon, the roof expands and contracts uniformly with a coefficient of thermal expansion \(\alpha_{1} .\) Resting on the roof is a flat rectangular metal plate with expansion coefficient \(\alpha_{2},\) greater than \(\alpha_{1} .\) The length of the plate is \(L_{0}\), measured up the slope of the roof. The component of the plate's weight perpendicular to the roof is supported by a normal force uniformly distributed over the area of the plate. The coefficient of kinetic friction between the plate and the roof is \(\mu_{k} .\) The plate is always at the same temperature as the roof, so we assume its temperature is continuously changing. Because of the difference in expansion \(\mathrm{co}\) efficients, each bit of the plate is moving relative to the roof below it, except for points along a certain horizontal line running across the plate. We call this the stationary line. If the temperature is rising, parts of the plate below the stationary line are moving down relative to the roof and feel a force of kinetic friction acting up the roof. Elements of area above the stationary line are sliding up the roof and on them kinetic friction acts downward parallel to the roof. The stationary line occupies no area, so we assume no force of static friction acts on the plate while the temperature is changing. The plate as a whole is very nearly in equilibrium, so the net friction force on it must be equal to the component of its weight acting down the incline. (a) Prove that the stationary line is at a distance of $$ \frac{L}{2}\left(1-\frac{\tan \theta}{\mu_{k}}\right) $$ below the top edge of the plate. (b) Analyze the forces that act on the plate when the temperature is falling, and prove that the stationary line is at that same distance above the bottom edge of the plate. (c) Show that the plate steps down the roof like an inchworm, moving each day by the distance $$ \frac{L\left(\alpha_{2}-\alpha_{1}\right)\left(T_{h}-T_{\epsilon}\right) \tan \theta}{\mu_{k}} $$ (d) Evaluate the distance an aluminum plate moves each day if its length is \(1.20 \mathrm{m},\) if the temperature cycles between \(4.00^{\circ} \mathrm{C}\) and \(36.0^{\circ} \mathrm{C},\) and if the roof has slope \(18.5^{\circ}\) coefficient of linear expansion \(1.50 \times 10^{-5}\left(^{\circ} \mathrm{C}\right)^{-1}\) and coefficient of friction 0.420 with the plate. (e) What If? What if the expansion coefficient of the plate is less than that of the roof? Will the plate creep up the roof?

The density of gasoline is \(730 \mathrm{kg} / \mathrm{m}^{3}\) at \(0^{\circ} \mathrm{C} .\) Its average coefficient of volume expansion is \(9.60 \times 10^{-4} /^{\circ} \mathrm{C} .\) If 1.00 gal of gasoline occupies \(0.00380 \mathrm{m}^{3},\) how many extra kilograms of gasoline would you get if you bought \(10.0 \mathrm{gal}\) of gasoline at \(0^{\circ} \mathrm{C}\) rather than at \(20.0^{\circ} \mathrm{C}\) from a pump that is not temperature compensated?

An automobile tire is inflated with air originally at \(10.0^{\circ} \mathrm{C}\) and normal atmospheric pressure. During the process, the air is compressed to \(28.0 \%\) of its original volume and the temperature is increased to \(40.0^{\circ} \mathrm{C} .\) (a) What is the tire pressure? (b) After the car is driven at high speed, the tire air temperature rises to \(85.0^{\circ} \mathrm{C}\) and the interior volume of the tire increases by \(2.00 \% .\) What is the new tire pressure (absolute) in pascals?

A tank having a volume of \(0.100 \mathrm{m}^{3}\) contains helium gas at 150 atm. How many balloons can the tank blow up if each filled balloon is a sphere \(0.300 \mathrm{m}\) in diameter at an absolute pressure of 1.20 atm?

A liquid has a density \(\rho\). (a) Show that the fractional change in density for a change in temperature \(\Delta T\) is \(\Delta \rho / \rho=-\beta \Delta T\). What does the negative sign signify? (b) Fresh water has a maximum density of \(1.0000 \mathrm{g} / \mathrm{cm}^{3}\) at \(4.0^{\circ} \mathrm{C} .\) At \(10.0^{\circ} \mathrm{C},\) its density is \(0.9997 \mathrm{g} / \mathrm{cm}^{3} .\) What is \(\beta\) for water over this temperature interval?

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