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Gas is contained in an \(8.00-\mathrm{L}\). vessel at a temperature of \(20.0^{\circ} \mathrm{C}\) and a pressure of 9.00 atm. \((\mathrm{a})\) Determine the number of moles of gas in the vessel. (b) How many molecules are there in the vessel?

Short Answer

Expert verified
a) There are 2.95 moles of gas in the vessel. b) There are \(1.78 \times 10^{24}\) molecules in the vessel.

Step by step solution

01

Identify the given variables

\(P = 9.00 \text{ atm}, V = 8.00 \text{ L}, T = 20.0^\circ\text{ C} = 293.15\text{ K}, R = 0.0821 \text{ L atm}/\text{mol K}\). It is important to convert the temperature to Kelvin as the ideal gas law requires this unit of measurement.
02

Calculate the Number of moles

Rearrange the ideal gas law, PV=nRT, to solve for the number of moles, n. This gives us, \(n = PV/RT\). Substituting the given values, we have, \(n = (9.00 \text{ atm} \times 8.00 \text{ L})/(0.0821 \text{ L atm/mol K} \times 293.15 \text{ K})\). Calculating this value, we find that \(n = 2.95 \text{ moles}\).
03

Determine the Number of Molecules

Avogadro's number is used to convert moles to molecules. Each mole of a substance contains \(6.022 \times 10^{23}\) molecules. So, we have \(2.95 \text{ moles} \times 6.022 \times 10^{23}\) molecules/mole. This yields \(1.78 \times 10^{24}\) molecules.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Moles Calculation
Calculating moles is an essential skill in chemistry. Moles represent a quantity that allows chemists to count particles like atoms or molecules by weighing a substance. To find the number of moles from the given conditions, we use the ideal gas law, PV = nRT. In this equation:
  • P stands for pressure, measured in atmospheres (atm).
  • V is the volume of gas in liters (L).
  • n is the number of moles.
  • R is the ideal gas constant, which is 0.0821 L atm/mol K.
  • T is the temperature in Kelvin (K).
The first step is converting the temperature from degrees Celsius to Kelvin. For our exercise, 20.0°C becomes 293.15K by adding 273.15. Next, rearrange the equation to find moles: \[ n = \frac{PV}{RT} \]Use the provided values to compute the moles, ensuring the consistent use of units throughout. This yields the solution of around 2.95 moles. Understanding how to manipulate the ideal gas law is crucial for effectively solving such problems.
Exploring Avogadro's Number
Avogadro's number is key to linking moles with particles. It is defined as the number of constituent particles, usually atoms or molecules, in one mole of a substance. The value of Avogadro's number is \(6.022 \times 10^{23}\) particles per mole.When you know the moles of a substance, Avogadro’s number helps convert this quantity into actual particles, making the abstract concept of moles practical and quantifiable. For instance, in our problem, we calculated 2.95 moles of gas. Multiplying this by Avogadro's number, you get the number of molecules present:\[ 2.95 \times 6.022 \times 10^{23} \approx 1.78 \times 10^{24} \] molecules.This conversion is invaluable for understanding chemical equations at the level of individual molecules or atoms.
An Introduction to Gas Laws
Gas laws describe how gases behave under varying conditions of pressure, temperature, and volume. They are essential for predicting how changes in one condition will affect another.The ideal gas law, expressed as \(PV = nRT\), is one of the most important gas laws. It encapsulates Charles's law, Boyle's law, and Avogadro's law. Each individual law describes the behavior of gases in specific conditions:
  • Boyle's Law - Describes the inverse relationship between pressure and volume at constant temperature.
  • Charles's Law - Describes the direct relationship between volume and temperature at constant pressure.
  • Avogadro's Law - States that equal volumes of gases at the same temperature and pressure contain an equal number of molecules.
The ideal gas law is an equation of state for a hypothetical gas called an "ideal gas." In practice, most real gases behave approximately like an ideal gas under many conditions, making this law a powerful tool in chemistry. Understanding these concepts prepares students to tackle complex problems involving gases and allows them to predict real-world gas behaviors with reasonable accuracy.

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Most popular questions from this chapter

(a) Show that the density of an ideal gas occupying a volume \(V\) is given by \(\rho=P M / R T,\) where \(M\) is the molar mass. (b) Determine the density of oxygen gas at atmospheric pressure and \(20.0^{\circ} \mathrm{C}\).

A tank having a volume of \(0.100 \mathrm{m}^{3}\) contains helium gas at 150 atm. How many balloons can the tank blow up if each filled balloon is a sphere \(0.300 \mathrm{m}\) in diameter at an absolute pressure of 1.20 atm?

In a chemical processing plant, a reaction chamber of fixed volume \(V_{0}\) is connected to a reservoir chamber of fixed volume \(4 V_{0}\) by a passage containing a thermally insulating porous plug. The plug permits the chambers to be at different temperatures. The plug allows gas to pass from either chamber to the other, ensuring that the pressure is the same in both. At one point in the processing, both chambers contain gas at a pressure of 1.00 atm and a temperature of \(27.0^{\circ} \mathrm{C}\). Intake and exhaust valves to the pair of chambers are closed. The reservoir is maintained at \(27.0^{\circ} \mathrm{C}\) while the reaction chamber is heated to \(400^{\circ} \mathrm{C}\). What is the pressure in both chambers after this is done?

Review problem. Following a collision in outer space, a copper disk at \(850^{\circ} \mathrm{C}\) is rotating about its axis with an angular speed of \(25.0 \mathrm{rad} / \mathrm{s} .\) As the disk radiates infrared light, its temperature falls to \(20.0^{\circ} \mathrm{C}\). No external torque acts on the disk. (a) Does the angular speed change as the disk cools off? Explain why. (b) What is its angular speed at the lower temperature?

Liquid nitrogen has a boiling point of \(-195.81^{\circ} \mathrm{C}\) at atmospheric pressure. Express this temperature (a) in degrees Fahrenheit and (b) in kelvins.

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