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The active element of a certain laser is made of a glass rod \(30.0 \mathrm{cm}\) long by \(1.50 \mathrm{cm}\) in diameter. If the temperature of the rod increases by \(65.0^{\circ} \mathrm{C},\) what is the increase in (a) its length, (b) its diameter, and (c) its volume? Assume that the average coefficient of linear expansion of the glass is \(9.00 \times 10^{-6}\left(^{\circ} \mathrm{C}\right)^{-1}\).

Short Answer

Expert verified
The increase in length, diameter and volume of the glass rod due to the temperature change are calculated using the coefficients of linear and volumetric expansion respectively. The final values will be the results of the calculations outlined in the step-by-step solution above.

Step by step solution

01

Determine the increase in length

The increase in length \( \Delta L \) of the rod can be calculated using the formula for linear expansion, which is \( \Delta L = \alpha \cdot L \cdot \Delta T \), where \(\alpha\) is the coefficient of linear expansion, \(L\) is the initial length and \( \Delta T \) is the change in temperature. Substituting the given values into the equation, we have \( \Delta L = 9.00 \times 10^{-6} (^{\circ} C)^{-1} \times 30.0 cm \times 65.0 ^{\circ} C \).
02

Determine the increase in diameter

The increase in diameter \( \Delta D \) of the rod can also be calculated using the formula for linear expansion since diameter is also a length. Therefore, the formula is \( \Delta D = \alpha \cdot D \cdot \Delta T \). Substituting values into the equation, we get \( \Delta D = 9.00 \times 10^{-6} (^{\circ} C)^{-1} \times 1.50 cm \times 65.0 ^{\circ} C \).
03

Determine the increase in volume

The increase in volume \( \Delta V \) of the rod can be calculated using the formula for volume expansion which is \( \Delta V = 3 \cdot \alpha \cdot V \cdot \Delta T \), where \(V\) is the initial volume. The initial volume can be calculated considering the rod as a cylinder \( V = \pi \cdot (D/2)^{2} \cdot L \). Substituting given values we get \( V = \pi \cdot (1.50 cm/2)^{2} \cdot 30.0 cm \). Once we have calculated V, we can substitute it along with the other values into the volume expansion equation to calculate \( \Delta V \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Linear Expansion
When materials are subjected to temperature changes, they typically undergo a change in size. This phenomenon, known as thermal expansion, is most easily observed in one-dimensional objects, such as rods or beams, where it is referred to as linear expansion. Imagine a metal rail on a hot day; it expands in length due to the increase in temperature. The key concept of linear expansion can be summarized with the formula:
\( \triangle L = \bar{\fontsize{12}{14.4}\text{7.056e-2}} \times L_0 \times \triangle T \).
Here, \(\triangle L\) represents the change in length, \(L_0\) is the initial length, \(\triangle T\) is the change in temperature, and \(\bar{\fontsize{12}{14.4}\text{7.056e-2}}\) is the coefficient of linear expansion for the material in question. The coefficient is unique to each material and is a measure of how sensitive it is to temperature changes.
Coefficient of Linear Expansion
The coefficient of linear expansion, traditionally denoted as \(\bar{\fontsize{12}{14.4}\text{7.056e-2}}\), is a crucial parameter in the study of thermal physics. It quantifies how much a unit length of a material expands per degree change in temperature. This coefficient varies from material to material and is central to understanding the behavior of materials under thermal stress. For example, metals usually have higher coefficients than plastics, indicating they expand more for a given temperature increase. When calculating the linear expansion of an object with the equation \( \triangle L = \bar{\fontsize{12}{14.4}\text{7.056e-2}} \times L_0 \times \triangle T \), a precise value for \(\bar{\fontsize{12}{14.4}\text{7.056e-2}}\) provides a more accurate prediction of the expansion, which can be critical in applications such as construction or design of machinery where tight tolerances are necessary.
Volume Expansion
Unlike linear expansion that concerns one-dimensional change, volume expansion considers the change in three-dimensional space. When a material heats up, not only does its length change, but its overall volume does too. For isotropic materials, which expand uniformly in all directions, the change in volume, \(\triangle V\), due to the change in temperature can be described by the formula:
\( \triangle V = \beta \times V_0 \times \triangle T \),
where \(\triangle V\) is the change in volume, \(V_0\) is the original volume, \(\triangle T\) is the change in temperature, and \(\beta\) is the coefficient of volume expansion. For most solids, \(\beta\) is approximately three times the coefficient of linear expansion, \(\beta \thickapprox 3\bar{\fontsize{12}{14.4}\text{7.056e-2}}\), reflecting the three dimensions in which expansion can occur.
Thermal Properties of Materials
Every material comes with inherent thermal properties that dictate how it will react to changes in temperature. These properties include heat capacity, thermal conductivity, and thermal expansion coefficients (both linear and volumetric). The thermal properties of materials are of vital importance in many technological applications—as they determine structural integrity and functionality in varying thermal environments. Understanding these properties allows for the prediction of a material's behavior under thermal stress and aids in selecting the right materials for specific applications, ensuring safety, efficiency, and longevity.
Physics of Lasers
Lasers, a ubiquitous tool in both everyday life and advanced scientific research, owe their operation to the principles of physics, particularly quantum mechanics and the interaction of light with matter. A core component of a laser is the 'gain medium' or 'lasing material', which can be a solid, liquid, or gas that amplifies light through stimulated emission. Thermal properties play an essential role in the design and operation of lasers; specifically, the thermal expansion of the gain medium can affect the optical path length and, consequently, the laser's performance. It is critical to understand and manage the thermal expansion through careful engineering to maintain the precision and stability required for the laser to function correctly.

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Most popular questions from this chapter

A sample of dry air that has a mass of \(100.00 \mathrm{g},\) collected at sea level, is analyzed and found to consist of the following gases: nitrogen \(\left(\mathrm{N}_{2}\right)=75.52 \mathrm{g}\) oxygen \(\left(\mathrm{O}_{2}\right)=23.15 \mathrm{g}\) $$ \text { argon }(\mathrm{Ar})=1.28 \mathrm{g} $$ carbon dioxide \(\left(\mathrm{CO}_{2}\right)=0.05 \mathrm{g}\) plus trace amounts of neon, helium, methane, and other gases. (a) Calculate the partial pressure (see Problem 65 ) of each gas when the pressure is \(1.013 \times 10^{5} \mathrm{Pa}\). (b) Determine the volume occupied by the \(100-\mathrm{g}\) sample at a temperature of \(15.00^{\circ} \mathrm{C}\) and a pressure of 1.00 atm. What is the density of the air for these conditions? (c) What is the effective molar mass of the air sample?

A certain telescope forms an image of part of a cluster of stars on a square silicon charge-coupled detector (CCD) chip \(2.00 \mathrm{cm}\) on each side. A star field is focused on the CCD chip when it is first turned on and its temperature is \(20.0^{\circ} \mathrm{C} .\) The star field contains 5342 stars scattered uniformly. To make the detector more sensitive, it is cooled to \(-100^{\circ} \mathrm{C} .\) How many star images then fit onto the chip? The average coefficient of linear expansion of silicon is \(4.68 \times 10^{-6}\left(^{\circ} \mathrm{C}\right)^{-1}\).

The Golden Gate Bridge in San Francisco has a main span of length \(1.28 \mathrm{km}\) -one of the longest in the world. Imagine that a taut steel wire with this length and a cross-sectional area of \(4.00 \times 10^{-6} \mathrm{m}^{2}\) is laid on the bridge deck with its ends attached to the towers of the bridge, on a summer day when the temperature of the wire is \(35.0^{\circ} \mathrm{C}\) (a) When winter arrives, the towers stay the same distance apart and the bridge deck keeps the same shape as its expansion joints open. When the temperature drops to \(-10.0^{\circ} \mathrm{C},\) what is the tension in the wire? Take Young's modulus for steel to be \(20.0 \times 10^{10} \mathrm{N} / \mathrm{m}^{2} .\) (b) Permanent deformation occurs if the stress in the steel exceeds its elastic limit of \(3.00 \times 10^{8} \mathrm{N} / \mathrm{m}^{2} .\) At what temperature would this happen? (c) What If? How would your answers to (a) and (b) change if the Golden Gate Bridge were twice as long?

A volumetric flask made of Pyrex is calibrated at \(20.0^{\circ} \mathrm{C} .\) It is filled to the 100 -mL mark with \(35.0^{\circ} \mathrm{C}\) acetone. (a) What is the volume of the acetone when it cools to \(20.0^{\circ} \mathrm{C} ?\) (b) How significant is the change in volume of the flask?

An automobile tire is inflated with air originally at \(10.0^{\circ} \mathrm{C}\) and normal atmospheric pressure. During the process, the air is compressed to \(28.0 \%\) of its original volume and the temperature is increased to \(40.0^{\circ} \mathrm{C} .\) (a) What is the tire pressure? (b) After the car is driven at high speed, the tire air temperature rises to \(85.0^{\circ} \mathrm{C}\) and the interior volume of the tire increases by \(2.00 \% .\) What is the new tire pressure (absolute) in pascals?

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