/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 49 Only two recording channels are ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Only two recording channels are required to give the illusion of sound coming from any point located between two speakers of a stereophonic sound system. If the same signal is recorded in both channels, a listener will hear it coming from a single direction halfway between the two speakers. This "phantom orchestra" illusion can be heard in the two-channel original Broadway cast recording of the song "Do-Re-Mi" from The Sound of Music (Columbia Records KOS 2020 ). Each of the eight singers can be heard at a different location between the loudspeakers. All listeners with normal hearing will agree on their locations. The brain can sense the direction of sound by noting how much earlier a sound is heard in one ear than in the other. Model your ears as two sensors \(19.0 \mathrm{cm}\) apart in a flat screen. If a click from a distant source is heard \(210 \mu\) s earlier in the left ear than in the right, from what direction does it appear to originate?

Short Answer

Expert verified
The direction from which the sound appears to originate is approximately 22 degrees to the right from straight ahead.

Step by step solution

01

Understand the situation

There are two sensors or ears placed 19.0 cm apart. A sound click originates from a distant source and reaches the left sensor \(210 \mu s\) earlier than the right sensor. One needs to find the direction of the sound source.
02

Convert time to distance

The sound travels faster in the ear that receives it first, which indicates that this ear is closer to the source. To determine the direction of the sound, we first convert the time difference to a distance difference using the formula \(d = v \cdot t\), where \(d\) is distance, \(v\) is the speed of sound (which is approximately \(343 m/s\) in air), and \(t\) is time. The time difference is \(210 \mu s\), or \(210 * 10^{-6} s\). Calculating the distance, we find it to be roughly \( d = 343 m/s * 210 * 10^{-6} s = 0.07203 m \) or \(7.203 cm\).
03

Find the Angle

This distance corresponds to the extra distance the sound has to travel to reach the far ear. Think of the ears and the source as vertices of a triangle. The distance we just calculated is one side of the triangle (the one opposite to the angle we want to find), and the distance between ears (19.0 cm) is the other side. We can use the sine function in trigonometry to find the required angle. The sine of the angle \( \theta \) is given by the ratio of the opposite side to the hypotenuse, i.e., \(7.203 cm / 19.0 cm\). Using an arcsin function to find the angle we have: \( \theta = arcsin(7.203/19.0) = 22.009\) degrees.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Interaural Time Difference (ITD)
Interaural Time Difference (ITD) is a pivotal concept in understanding how humans localize sound. It refers to the time it takes for a sound to reach one ear compared to the other. Our brains utilize this tiny difference, often just microseconds, to determine where a sound is coming from. When a sound reaches the left ear slightly before the right, the brain interprets this as the sound originating from the left.
It's fascinating that such small time gaps can produce a precise perception of sound direction. Imagine you hear a horn honking as you walk down the street: if it sounds earlier in your left ear, your brain flags it as coming from the left.
This principle is extremely useful not just in real-life scenarios, but also in designing audio systems like headphones and stereo speakers. The accurate perception of sound direction enhances everything from music to immersive VR environments./nThe key to ITD is in the horizontal plane, where most of our ear-based direction detection occurs. Our brain's ability to process these interaural differences is what allows us to experience a 3D auditory world.
Trigonometry in Physics
One might not immediately associate trigonometry with sound, but it's integral when calculating sound direction based on ITD. The exercise at hand uses trigonometry to pinpoint the angle of sound incidence when one ear detects sound slightly before the other. This is a classic example of applying trigonometry in physics.
The formula to find the angle uses the sine function, where the opposite side of a right-angled triangle is the extra path sound travels to reach the farther ear, and the hypotenuse is the separation between the ears. Here, the opposite side is calculated using the time difference converted into distance, thanks to the speed of sound known to be roughly 343 m/s.
Through the equation \( \theta = \arcsin\left( \frac{\text{opposite}}{\text{hypotenuse}} \right) \), we determine the angle from which the sound appears to originate. Trigonometry thus allows us to translate time differences into comprehensible directions, essential for both hearing and technical applications like sound engineering.
Stereophonic Sound System
The concept of a Stereophonic Sound System involves creating multidimensional audio by using two or more channels of sound. This technology manipulates ITD, among other parameters, to project sound in a way that mimics how we would naturally perceive it in a physical space.
By varying the intensity and timing of audio signals between the left and right speakers, stereophonic systems can create a virtual soundstage. This method tricks the brain into believing the sound is coming from various directions, sometimes even places where no speakers exist. It's what makes it possible to hear each singer in a recording, like the example from "The Sound of Music," at distinct locations in space—even with just two speakers.
The beauty of a stereophonic system lies in its ability to enhance listener experience without increasing the number of physical speakers. It's a prime example of how audio technology leverages biological auditory processing mechanisms to create immersive soundscapes.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The most soaring vocal melody is in Johann Sebastian Bach's Mass in \(B\) minor. A portion of the score for the Credo section, number \(9,\) bars 25 to \(33,\) appears in Figure \(P 17.23\) The repeating syllable \(\mathrm{O}\) in the phrase "resurrectionem mortuorum" (the resurrection of the dead) is seamlessly passed from basses to tenors to altos to first sopranos, like a baton in a relay. Each voice carries the melody up in a run of an octave or more. Together they carry it from D below middle C to A above a tenor's high C. In concert pitch, these notes are now assigned frequencies of \(146.8 \mathrm{Hz}\) and \(880.0 \mathrm{Hz}\). (a) Find the wavelengths of the initial and final notes. (b) Assume that the choir sings the melody with a uniform sound level of \(75.0 \mathrm{dB} .\) Find the pressure amplitudes of the initial and final notes. (c) Find the displacement amplitudes of the initial and final notes. (d) What If? In Bach's time, before the invention of the tuning fork, frequencies were assigned to notes as a matter of immediate local convenience. Assume that the rising melody was sung starting from \(134.3 \mathrm{Hz}\) and ending at \(804.9 \mathrm{Hz}\). How would the answers to parts (a) through (c) change?

Show that the difference between decibel levels \(\beta_{1}\) and \(\beta_{2}\) of a sound is related to the ratio of the distances \(r_{1}\) and \(r_{2}\) from the sound source by $$\beta_{2}-\beta_{1}=20 \log \left(\frac{r_{1}}{r_{2}}\right)$$

On a Saturday morning, pickup trucks and sport utility vehicles carrying garbage to the town dump form a nearly steady procession on a country road, all traveling at \(19.7 \mathrm{m} / \mathrm{s} .\) From one direction, two trucks arrive at the dump every 3 min. A bicyclist is also traveling toward the dump, at \(4.47 \mathrm{m} / \mathrm{s}\). (a) With what frequency do the trucks pass him? (b) What If? A hill does not slow down the trucks, but makes the out-of-shape cyclist's speed drop to \(1.56 \mathrm{m} / \mathrm{s} .\) How often do noisy, smelly, inefficient, garbage-dripping, roadhogging trucks whiz past him now?

An experimenter wishes to generate in air a sound wave that has a displacement amplitude of \(5.50 \times 10^{-6} \mathrm{m}\) The pressure amplitude is to be limited to \(0.840 \mathrm{N} / \mathrm{m}^{2}\) What is the minimum wavelength the sound wave can have?

The intensity of a sound wave at a fixed distance from a speaker vibrating at a frequency \(f\) is \(I\) (a) Determine the intensity if the frequency is increased to \(f^{\prime}\) while a constant displacement amplitude is maintained. (b) Calculate the intensity if the frequency is reduced to \(f / 2\) and the displacement amplitude is doubled. GRAPH CANT COPY

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.