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The tensile stress in a thick copper bar is \(99.5 \%\) of its elastic breaking point of \(13.0 \times 10^{10} \mathrm{N} / \mathrm{m}^{2} .\) If a \(500-\mathrm{Hz}\) sound wave is transmitted through the material, (a) what displacement amplitude will cause the bar to break? (b) What is the maximum speed of the elements of copper at this moment? (c) What is the sound intensity in the bar?

Short Answer

Expert verified
The displacement amplitude is \(\approx 1.24 脳 10^{-11}\, \mathrm{m}\). The maximum speed of the elements of copper is \(\approx 1.96 脳 10^{-4}\, \mathrm{m/s}\). The sound intensity in the bar is \(\approx 1.14 脳 10^{-12}\, \mathrm{W/m^{2}}\).

Step by step solution

01

Determine the Maximum Stress

The first thing to do is find the maximum stress the copper bar can withstand. This is given as 99.5% of its elastic breaking point which is \(13.0 \times 10^{10} \, \mathrm{N/m^{2}}\). Hence, the maximum stress, \(Bm\), is given by:\[ Bm = 0.995 \times 13.0 \times 10^{10} \, \mathrm{N/m^{2}}.\]
02

Calculate the Displacement Amplitude

Remembering that stress is the product of the young's modulus, \(Y\), and the strain, out of which strain is equal to the amplitude, \(A\), over the wavelength, \(位\), we can rewrite the formula for stress as: \(Bm = YA/位\). Given the speed of sound in copper as \(v = 5000 \, \mathrm{m/s}\) and considering that \(v = 位f\), for \(f = 500 \, Hz\), the wavelength can be calculated. With this, the amplitude can be obtained by re-arranging the formula as: \(A = Bm位/Y\). Next, use \(A = Bm位/Y\) to find the displacement amplitude, \(A\).
03

Calculate the Maximum Velocity

Knowing the displacement amplitude and the frequency, we can find the maximum velocity using the formula: \(v_{m} = Af\omega\), where \(\omega = 2蟺f\).\nNext, substitute the calculated values of the displacement amplitude and the given value for frequency into the formula and solve to find the maximum velocity, \(v_{m}\).
04

Calculate the Sound Intensity

Sound intensity, \(I\), can be obtained using the formula: \(I = 0.5蟻v^{2}_{m}\omega^{2}A^{2}\). Where 蟻 is the density of copper which is \(8.96 脳 10^{3} \, \mathrm{kg/m^{3}}\). Substitute the calculated displacement amplitude, maximum velocity, frequency and known values into this formula and solve to get the sound intensity, \(I\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Displacement Amplitude
Displacement amplitude refers to the maximum distance that particles in a medium move from their rest position as a wave passes through. Imagine a wave traveling along a copper bar; the particles of the bar move back and forth around their equilibrium position. The maximum extent of this movement is known as the displacement amplitude. In the context of the given exercise, the displacement amplitude is significant because it directly affects the ability of a sound wave to cause stress in the bar. By calculating the displacement amplitude, we can determine the stress exerted on the copper bar when a sound wave is applied.
According to the formula: \[ Bm = \frac{YA}{位} \]
where:
  • \( Bm \) is the maximum stress it can tolerate,
  • \( Y \) is the Young's modulus of elasticity,
  • \( A \) is the displacement amplitude,
  • \( 位 \) is the wavelength.
From this, we rearrange to find the displacement amplitude \( A = \frac{Bm位}{Y} \). Once found, this can provide insight into how severe the deformation is and when the material might fail.
Maximum Velocity
Maximum velocity of the particles in the copper bar refers to the peak speed at which the particles oscillate during the transmission of the wave. This is crucial because higher velocities correlate with higher kinetic energy, influencing how the copper bar may react to the passing wave. The formula to calculate maximum velocity is:\[ v_m = A \cdot f \cdot \omega \]
where:
  • \( A \) is the displacement amplitude,
  • \( f \) is the frequency of the wave,
  • \( \omega = 2\pi f \) is the angular frequency.
Using these variables, we can uncover how fast the particles actually move. Understanding maximum velocity helps us assess how much energy each oscillation imparts on the material. It also aids in predicting the response of the copper bar under sound wave stress.
Sound Intensity
Sound intensity is a measure of the energy carried by a sound wave per unit area per unit time. It provides a way to gauge the power of the sound wave impacting the material. Given its dependence on displacement amplitude and maximum velocity, it can tell us about potential stresses acting on the material. The formula for sound intensity is:\[ I = 0.5 \rho v^2_m \omega^2 A^2 \]
where:
  • \( \rho \) is the density of copper,
  • \( v_m \) is maximum velocity,
  • \( \omega \) is angular frequency,
  • \( A \) is displacement amplitude.
Sound intensity takes into account all the dynamic movements within the wave; the higher the intensity, the more energy is transmitted through the copper bar. Understanding sound intensity helps us evaluate the potential for sound waves to reach the elastic breaking point of a material.
Elastic Breaking Point
The elastic breaking point is the maximum stress that a material, like copper, can withstand without permanently deforming or failing. When stress due to oscillating particles exceeds this breaking point, the material will break or be damaged. In the context of the problem, the elastic breaking point represents the threshold that should not be crossed when a sound wave impacts the copper bar.
Every material has its specific elastic breaking point, expressed often in terms of stress units like \( \, ext{N/m}^2 \). Copper's point is crucial because it determines the structural integrity when subjected to mechanical stresses, like those from a passing wave.
By understanding and calculating when stresses approach this limit, engineers can design and protect structures to avoid catastrophic failures. This exercise indirectly emphasizes the importance of knowing this point when dealing with materials under oscillating stresses.
Copper Material Properties
Copper is a versatile material known for its excellent electrical conductivity, thermal properties, and ductility. These characteristics make it invaluable in various engineering and industrial applications. In the realm of acoustics and structural mechanics, understanding copper's behavior under stress is essential. Some key properties include:
  • Young's Modulus: Provides a measure of stiffness, influencing how much the material will strain under stress.
  • Density: Affects sound wave transmission characteristics; copper has a density of \( 8.96 \times 10^3 \, ext{kg/m}^3 \).
  • Elastic Breaking Point: The maximum stress copper can withstand before experiencing irreversible deformation.
  • Ductility: Allows copper to bend without breaking; helpful in forming to fit specific applications without fracture.
Understanding these properties can both predict how copper will behave in wave transmission tasks and assist engineers in leveraging its advantages while avoiding exceeding its limitations.

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Most popular questions from this chapter

A sinusoidal sound wave is described by the displacement wave function $$s(x, t)=(2.00 \mu \mathrm{m}) \cos \left[\left(15.7 \mathrm{m}^{-1}\right) x-\left(858 \mathrm{s}^{-1}\right)t\right]$$ (a) Find the amplitude, wavelength, and speed of this wave. (b) Determine the instantaneous displacement from equilibrium of the elements of air at the position \(x=0.0500 \mathrm{m}\) at \(t=3.00 \mathrm{ms} .\) (c) Determine the maximum speed of the element's oscillatory motion.

The most soaring vocal melody is in Johann Sebastian Bach's Mass in \(B\) minor. A portion of the score for the Credo section, number \(9,\) bars 25 to \(33,\) appears in Figure \(P 17.23\) The repeating syllable \(\mathrm{O}\) in the phrase "resurrectionem mortuorum" (the resurrection of the dead) is seamlessly passed from basses to tenors to altos to first sopranos, like a baton in a relay. Each voice carries the melody up in a run of an octave or more. Together they carry it from D below middle C to A above a tenor's high C. In concert pitch, these notes are now assigned frequencies of \(146.8 \mathrm{Hz}\) and \(880.0 \mathrm{Hz}\). (a) Find the wavelengths of the initial and final notes. (b) Assume that the choir sings the melody with a uniform sound level of \(75.0 \mathrm{dB} .\) Find the pressure amplitudes of the initial and final notes. (c) Find the displacement amplitudes of the initial and final notes. (d) What If? In Bach's time, before the invention of the tuning fork, frequencies were assigned to notes as a matter of immediate local convenience. Assume that the rising melody was sung starting from \(134.3 \mathrm{Hz}\) and ending at \(804.9 \mathrm{Hz}\). How would the answers to parts (a) through (c) change?

To permit measurement of her speed, a skydiver carries a buzzer emitting a steady tone at \(1800 \mathrm{Hz}\). A friend on the ground at the landing site directly below listens to the amplified sound he receives. Assume that the air is calm and that the sound speed is \(343 \mathrm{m} / \mathrm{s}\), independent of altitude. While the skydiver is falling at terminal speed, her friend on the ground receives waves of frequency \(2150 \mathrm{Hz}\) (a) What is the skydiver's speed of descent? (b) What If? Suppose the skydiver can hear the sound of the buzzer reflected from the ground. What frequency does she receive?

This problem represents a possible (but not recommended) way to code instantaneous pressures in a sound wave into 16 -bit digital words. Example 17.2 mentions that the pressure amplitude of a \(120-\mathrm{dB}\) sound is \(28.7 \mathrm{N} / \mathrm{m}^{2}\) Let this pressure variation be represented by the digital -code \(65536 .\) Let zero pressure variation be represented on the recording by the digital word \(0 .\) Let other intermediate pressures be represented by digital words of intermediate -size, in direct proportion to the pressure. (a) What digital word would represent the maximum pressure in a \(40 \mathrm{dB}\) -sound? (b) Explain why this scheme works poorly for soft -sounds. (c) Explain how this coding scheme would clip off half of the waveform of any sound, ignoring the actual -shape of the wave and turning it into a string of zeros. By introducing sharp corners into every recorded waveform, this coding scheme would make everything sound like a buzzer or a kazoo.

Find the speed of sound in mercury, which has a bulk modulus of approximately \(2.80 \times 10^{10} \mathrm{N} / \mathrm{m}^{2}\) and a density of \(13600 \mathrm{kg} / \mathrm{m}^{3}\)

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